EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 8220106637203
Author: Chang
Publisher: YUZU
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Chapter 5, Problem 5.117QP

(a)

Interpretation Introduction

Interpretation:

The pressures in valves (b) and (c) has to be calculated.

(a)

Expert Solution
Check Mark

Answer to Problem 5.117QP

The partial pressures in valves (b) and (c) is

PB=8.0atm

PC=5.3atm

Explanation of Solution

Bulb (b) contains the same number of particles as (a), but is half the volume.  The pressure will be double that of A.

PB=(2)(4.0atm)=8.0atm

The volume of bulb (c) is the same as bulb (a), but there are 12 particles in (c) while there are 9 particles in (a).  The pressure is directly proportional to the number of moles of gas (or particles of gas) at the same temperature and volume.

PC=(129)(4.0atm)=5.3atm

(b)

Interpretation Introduction

Interpretation:

The total pressure and partial pressure of each gas after the valves are opened has to be calculated.

(b)

Expert Solution
Check Mark

Answer to Problem 5.117QP

The total pressure in the container is the sum of the partial pressures is Ptotal=5.3atm

The partial pressure is PA=PB=2.65 atm

Explanation of Solution

The valves are opened at constant temperature, the gases expand to fill the entire container.  In bulb (a), the pressure before opening the valve is 4.0atm and the volume is 4.0 L.  After the valves are opened, the volume is now 10 L (4 L + 2 L + 4 L). We use Boyle’s law to calculate the partial pressure of each sample of gas after the valves are opened.

Given data,

P1 Valves pressure is 4.0atm

V1=4.0L

V2=10.0L

(a)P1V1=P2V2(4.0atm)(4.0L)=P2(10.0L)P2=1.6atm

Given data,

P1 Valves pressure is 8.0atm

V1=2.0L

V2=10.0L

(b)P1V1=P2V2(8.0atm)(2.0L)=P2(10.0L)P2=1.6atm

Given data,

P1 Valves pressure is 5.3 atm

V1=4.0L

V2=10.0L

(c)P1V1=P2V2(5.3atm)(4.0L)=P2(10.0L)P2=2.1atm

The total pressure in the container is the sum of the partial pressures

Ptotal=1.6atm+1.6atm+2.1atm=5.3atm

There are 15 particles of gas A and 15 particles of gas B in the container. Therefore, the partial pressure of each gas will be half the total pressure of 5.3atm

PA=PB=2.65 atm

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Chapter 5 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

Ch. 5.5 - Prob. 1PECh. 5.5 - Prob. 2PECh. 5.5 - Prob. 1RCCh. 5.6 - Prob. 1PECh. 5.6 - Prob. 2PECh. 5.6 - Prob. 1RCCh. 5.7 - Prob. 1PECh. 5.7 - Prob. 1RCCh. 5 - Prob. 5.1QPCh. 5 - Prob. 5.2QPCh. 5 - Prob. 5.3QPCh. 5 - Prob. 5.4QPCh. 5 - Prob. 5.5QPCh. 5 - 5.6 Describe what would happen to the column of...Ch. 5 - Prob. 5.7QPCh. 5 - 5.8 Is the atmospheric pressure in a mine that is...Ch. 5 - 5.9 What is the difference between a gas and a...Ch. 5 - Prob. 5.10QPCh. 5 - Prob. 5.11QPCh. 5 - Prob. 5.12QPCh. 5 - Prob. 5.13QPCh. 5 - 5.14 The atmospheric pressure at the summit of Mt....Ch. 5 - 5.15 State the following gas laws in words and...Ch. 5 - Prob. 5.17QPCh. 5 - Prob. 5.18QPCh. 5 - 5.19 A gas occupying a volume of 725 mL at a...Ch. 5 - 5.20 At 46°C a sample of ammonia gas exerts a...Ch. 5 - Prob. 5.21QPCh. 5 - Prob. 5.22QPCh. 5 - Prob. 5.23QPCh. 5 - Prob. 5.24QPCh. 5 - Prob. 5.25QPCh. 5 - Prob. 5.26QPCh. 5 - Prob. 5.27QPCh. 5 - Prob. 5.28QPCh. 5 - Prob. 5.29QPCh. 5 - Prob. 5.30QPCh. 5 - Prob. 5.31QPCh. 5 - Prob. 5.32QPCh. 5 - Prob. 5.33QPCh. 5 - Prob. 5.34QPCh. 5 - Prob. 5.35QPCh. 5 - 5.36 The temperature of 2.5 L of a gas initially...Ch. 5 - Prob. 5.37QPCh. 5 - Prob. 5.38QPCh. 5 - Prob. 5.39QPCh. 5 - Prob. 5.40QPCh. 5 - Prob. 5.41QPCh. 5 - Prob. 5.42QPCh. 5 - Prob. 5.43QPCh. 5 - Prob. 5.44QPCh. 5 - Prob. 5.45QPCh. 5 - Prob. 5.46QPCh. 5 - Prob. 5.47QPCh. 5 - Prob. 5.48QPCh. 5 - Prob. 5.49QPCh. 5 - Prob. 5.50QPCh. 5 - Prob. 5.51QPCh. 5 - Prob. 5.52QPCh. 5 - Prob. 5.53QPCh. 5 - Prob. 5.54QPCh. 5 - Prob. 5.55QPCh. 5 - Prob. 5.56QPCh. 5 - Prob. 5.57QPCh. 5 - Prob. 5.58QPCh. 5 - Prob. 5.59QPCh. 5 - Prob. 5.60QPCh. 5 - Prob. 5.61QPCh. 5 - Prob. 5.62QPCh. 5 - Prob. 5.63QPCh. 5 - Prob. 5.64QPCh. 5 - Prob. 5.65QPCh. 5 - Prob. 5.66QPCh. 5 - Prob. 5.67QPCh. 5 - Prob. 5.68QPCh. 5 - 5.69 What does the Maxwell speed distribution...Ch. 5 - Prob. 5.70QPCh. 5 - Prob. 5.71QPCh. 5 - Prob. 5.72QPCh. 5 - Prob. 5.73QPCh. 5 - Prob. 5.74QPCh. 5 - Prob. 5.75QPCh. 5 - Prob. 5.76QPCh. 5 - Prob. 5.78QPCh. 5 - 5.79 Write the van der Waals equation for a real...Ch. 5 - Prob. 5.80QPCh. 5 - Prob. 5.81QPCh. 5 - Prob. 5.82QPCh. 5 - 5.83 Discuss the following phenomena in terms of...Ch. 5 - Prob. 5.84QPCh. 5 - Prob. 5.85QPCh. 5 - Prob. 5.86QPCh. 5 - Prob. 5.87QPCh. 5 - 5.88 Identify the Maxwell speed distribution...Ch. 5 - Prob. 5.89QPCh. 5 - Prob. 5.90QPCh. 5 - Prob. 5.91QPCh. 5 - Prob. 5.92QPCh. 5 - Prob. 5.93QPCh. 5 - Prob. 5.94QPCh. 5 - Prob. 5.95QPCh. 5 - Prob. 5.96QPCh. 5 - Prob. 5.97QPCh. 5 - Prob. 5.98QPCh. 5 - Prob. 5.99QPCh. 5 - Prob. 5.100QPCh. 5 - Prob. 5.101QPCh. 5 - Prob. 5.102QPCh. 5 - Prob. 5.104QPCh. 5 - Prob. 5.105QPCh. 5 - Prob. 5.106QPCh. 5 - Prob. 5.107QPCh. 5 - Prob. 5.108QPCh. 5 - Prob. 5.109QPCh. 5 - Prob. 5.110QPCh. 5 - Prob. 5.111QPCh. 5 - Prob. 5.112QPCh. 5 - Prob. 5.113QPCh. 5 - Prob. 5.114QPCh. 5 - Prob. 5.115QPCh. 5 - Prob. 5.116QPCh. 5 - Prob. 5.117QPCh. 5 - 5.118 Apply your knowledge of the kinetic theory...Ch. 5 - Prob. 5.119SPCh. 5 - Prob. 5.120SPCh. 5 - Prob. 5.121SPCh. 5 - Prob. 5.122SPCh. 5 - Prob. 5.123SPCh. 5 - Prob. 5.124SPCh. 5 - Prob. 5.125SPCh. 5 - Prob. 5.126SPCh. 5 - Prob. 5.127SPCh. 5 - Prob. 5.128SP
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