Chapter 4.8, Problem 65STP

To determine

To Find: The number of ways of arrangement of students.

Answer to Problem 65STP

G

Explanation of Solution

Given:

Total number of students $=5$

No. of students on both the side of the center (tallest) $=2$

Calculation:

  $\begin{array}{l}\text{Let,}\\ \text{The number of students be }=A,B,C,D\&E\\ \text{Height of the respective students be}=h_A,h_B,h_c,h_d\&h_e\\ \text{Tallest student be}=E\\ \text{Smallest student be}=A\&B\\ \text{Now arranging }C\&D\\ \begin{array}{ccccc}A& C& E& D& B\\ A& D& E& C& B\\ B& C& E& D& A\\ B& D& E& C& B\end{array}\\ \text{The total number of ways of arranging while keeping tallest at the center and smallest on both side}\text{is }=4\end{array}$

Conclusion:

Thus the number of ways of arranging is $4$ i.e. G.