Explanation Vertical asymptotes of y = 1 x 2 -6x+8 Take the denominators of y = 1 x 2 -6x+8 and compare to zero Solve x 2 − 6 x + 8 = 0 x 1 , 2 = − b ± b 2 − 4 a c 2 a For a = 1 , b = − 6 , c = 8 : x 1 , 2 = − ( − 6 ) ± ( − 6 ) 2 − 4 × 1 × 8 2 × 1 x = − ( − 6 ) ± ( − 6 ) 2 − 4 × 1 × 8 2 × 1 Apply rule − ( − a ) = a 6 + ( − 6 ) 2 − 4 × 1 × 8 2 Multiply the numbers : 2 × 1 = 2 = 6 + ( − 6 ) 2 − 4 × 1 × 8 2 = 6 + 36 − 32 2 = 6 + 4 2 = 6 + 2 2 = 8 2 = 4 x = − ( − 6 ) − ( − 6 ) 2 − 4 × 1 × 8 2 × 1 Apply rule − ( − a ) = a = − ( − 6 ) − ( − 6 ) 2 − 4 × 1 × 8 2 × 1 Multiply the

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 4.5, Problem 63E

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The function of graph the transition points and asymptotes for the equation y = 1x2−6x+8

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Chapter 4.5, Problem 62E

Chapter 4.5, Problem 64E

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Chapter 4 Solutions

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Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

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Asymptotes - What are they? : ExamSolutions Maths Revision; Author: ExamSolutions;https://www.youtube.com/watch?v=5Hl_WJXcR6M;License: Standard YouTube License, CC-BY

The function of graph the transition points and asymptotes for the equation y = 1 x 2 − 6 x + 8

Solution Summary: The author explains that the solution for vertical asymptotes of x is 4, 2 and horizontal y is 0.

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The function of graph the transition points and asymptotes for the equation y = 1x2−6x+8

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Chapter 4 Solutions