Explanation Given Information: The system of equations: − 0.1 y + 0.2 z = 0.2 0.1 x + 0.1 y + 0.1 z = 0.2 − 0.1 x + 0.3 z = 0.2 Formula used: To solve a system of three linear equations in three variables Step 1: Write each equation in standard form A x + B y + C z = D . Step 2: Choose a pair of equations and use the addition method to eliminate one of the variables. Step 3: Choose a different pair of equations and eliminate the same variable. Step 4: Now, there are two equations in two variables. Use the substitution or the addition method to solve this system. Step 5: Substitute the values of the variables found in Step 4 into any of the three originalequations that contain the third variable. Solve for the third variable. Step 6: Check the ordered triple in each of the original equations. Calculation: Label the given system of equations as: − 0.1 y + 0.2 z = 0.2 …...…... (A) 0.1 x + 0.1 y + 0.1 z = 0.2 …...…... (B) − 0.1 x + 0.3 z = 0.2 …...…... (C) Step 1: The equations are already in standard form. Step 2: The y variable can be eliminated from equations A and B. Add equation A to equation B as follows: − 0.1 y + 0.2 z = 0.2 0.1 x + 0.1 y + 0.1 z = 0.2 _ 0.1 x + 0.3 z = 0.4 …...…... (D) Step 3: The y variable can be eliminated from equations D and C. Add equation D to equation C as follows: 0.1 x + 0.3 z = 0.4 − 0.1 x + 0.3 z = 0.2 _ 0.6 z = 0.6 z = 1 Step 4: Substitute the above obtained value of z in equation D as follows: 0.1 x + 0.3 z = 0.4 0.1 x + 0.3 ( 1 ) = 0.4 0.1 x + 0.3 = 0.4 0

5th Edition

ISBN: 9781259616754

Author: Julie Miller, Molly O'Neill, Nancy Hyde

Publisher: McGraw-Hill Education

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Chapter 4.5, Problem 45PE

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To calculate: If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows:

−0.1y+0.2z=0.20.1x+0.1y+0.1z=0.2−0.1x +0.3z=0.2

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Chapter 4.5, Problem 44PE

Chapter 4.5, Problem 46PE

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Chapter 4 Solutions

Beginning and Intermediate Algebra

Ch. 4.1 - Determine whether the ordered paired is a solution...Ch. 4.1 - Determine whether the ordered paired is a solution...Ch. 4.1 - Solve the system by the graphing method. y = − 3 x...Ch. 4.1 - Solve the system by the graphing method. y = 2 x −...Ch. 4.1 - Solve the system by the graphing. 5. Ch. 4.1 - Solve the system by the graphing. 6. Ch. 4.1 - a. A______ of linear equations consists of two or...Ch. 4.1 - For Exercises 2-10, determine if the given point...Ch. 4.1 - Prob. 3PE Ch. 4.1 - Prob. 4PE

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If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows: − 0.1 y + 0.2 z = 0.2 0.1 x + 0.1 y + 0.1 z = 0.2 − 0.1 x + 0.3 z = 0.2

Solution Summary: The author explains how to solve a system of three linear equations in three variables.

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To calculate: If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows:

−0.1y+0.2z=0.20.1x+0.1y+0.1z=0.2−0.1x +0.3z=0.2

Want to see the full answer?

Chapter 4 Solutions

If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows: − 0.1 y + 0.2 z = 0.2 0.1 x + 0.1 y + 0.1 z = 0.2 − 0.1 x + 0.3 z = 0.2

Solution Summary: The author explains how to solve a system of three linear equations in three variables.

Videos

To calculate: If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows: −0.1y+0.2z=0.20.1x+0.1y+0.1z=0.2−0.1x +0.3z=0.2

Want to see the full answer?

Chapter 4 Solutions

To calculate: If the given system of equations is dependent or inconsistent or has a unique solution. If there is a unique solution, solve for it. The system of equations is given as follows:

−0.1y+0.2z=0.20.1x+0.1y+0.1z=0.2−0.1x +0.3z=0.2