Concept explainers
What must the distance be between charges of +2.25 and −1.86 in order for the attractive force between them to be the same as that between charges of +4.06 and −2.11 separated by a distance of 2.16 pm?
Interpretation:
The distance between the two given charges using given data should be determined.
Concept Introduction:
Coulombs law: It states that the force of attraction between two point charges is directly proportional to the product of the point charges and inversely proportional the square of the distances between the charges.
Valence electron: The electron is considered as valence electron if it present in outermost shell of atom which gets involved in the formation of chemical bond.
Effective nuclear charge: It is the overall positive charge experienced by the outermost electrons present in the atom from the nucleus of the atom.
Screening Effect: The core electrons present near the nucleus shields the outermost electrons (valence electrons) from the charge of the nucleus.
To determine: The distance between the two given charges by using the force of attraction obtained from the two other given charges.
Answer to Problem 6PPB
Answer
The distance between two given charges is 1.51
Explanation of Solution
Determine the force of attraction between+4.06 and -2.11.
The attraction force between charges
The attraction force is determined by substituting the given charges+4.06 and -2.11 and the distance values in the formula give the attraction force value as -1.84.
Determine the distance between the charges
Given data says that attraction forces between
The distance between the
Solving for the value of x gives the distance between the two given charges.
Therefore, the distance between
Conclusion
The distance between the given charges is determined by using the coulombs formula.
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Chapter 4 Solutions
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