Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 a. Find a model that expresses the revenue R as a function of x . (Remember, R = x p ).

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Answer 1

Question

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Expert Solution & Answer

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Answer 2

Question

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Answer 6

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

Answer 7

Chapter 4.4, Problem 3AYU

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

Answer 8

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

Answer 9

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

Answer 10

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

Answer 11

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

Answer 12

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

Answer 13

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

Answer 14

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Answer 15

To determine

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Answer 16

Expert Solution & Answer

Answer 17

Expert Solution & Answer

Answer 18

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Answer 19

Ch. 4.1 - Answers are given at the end of these exercises....Ch. 4.1 - Prob. 2AYU Ch. 4.1 - Prob. 3AYU Ch. 4.1 - Prob. 4AYU Ch. 4.1 - Prob. 5AYU Ch. 4.1 - Prob. 6AYU Ch. 4.1 - Prob. 7AYU Ch. 4.1 - Prob. 8AYU Ch. 4.1 - 9. True or False The slope of a nonvertical line...Ch. 4.1 - Prob. 10AYU

Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 a. Find a model that expresses the revenue R as a function of x . (Remember, R = x p ).

Concept explainers

Videos

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?

Want to see the full answer?

Chapter 4 Solutions

Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 a. Find a model that expresses the revenue R as a function of x . (Remember, R = x p ).

Concept explainers

Videos

To find: Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 a. Find a model that expresses the revenue R as a function of x . (Remember, R = xp ).

To find: Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 b. What is the domain of R ?

To find: Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 c. What is the revenue if 200 units are sold?

To find: Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 d. What quantity x maximizes revenue? What is the maximum revenue?

To find: Maximizing Revenue. The price p (in dollars) and the quantity x sold of a certain product obey the demand equation, p = − 1 6 x + 100 e. What price should the company charge to maximize revenue?

Want to see the full answer?

Chapter 4 Solutions

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

a. Find a model that expresses the revenue $R$ as a function of $x$ . (Remember, $R = x p$ ).

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

b. What is the domain of $R$ ?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

c. What is the revenue if 200 units are sold?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

d. What quantity $x$ maximizes revenue? What is the maximum revenue?

To find: Maximizing Revenue. The price $p$ (in dollars) and the quantity $x$ sold of a certain product obey the demand equation,

$p = - \frac{1}{6} x + 100$

e. What price should the company charge to maximize revenue?