Explanation Given: The figures are: Calculation: Part a: The condition is: f ″ ( x ) < 0 for all x . So, f ( x ) is concave down. The graph of (C) is concave down. Hence, the correct option for (a) is (C). Part b: The condition is: f ″ ( x ) goes form + to − . It means the function goes from concave up to concave down. The graph of (A) goes from concave up to concave down

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.4, Problem 1E

To determine

Match the figure with their correct description:

a. f″(x)<0 for all x.

b. f″(x) goes from + to −.

c. f″(x)>0 for all x.

d. f″(x) goes from − to +.

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Chapter 4.4, Problem 6PQ

Chapter 4.4, Problem 2E

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Chapter 4 Solutions

CALCULUS (CLOTH)

Ch. 4.1 - Prob. 1PQ Ch. 4.1 - Prob. 2PQ Ch. 4.1 - Prob. 3PQ Ch. 4.1 - Prob. 4PQ Ch. 4.1 - Prob. 1E Ch. 4.1 - Prob. 2E Ch. 4.1 - Prob. 3E Ch. 4.1 - Prob. 4E Ch. 4.1 - Prob. 5E Ch. 4.1 - Prob. 6E

Ch. 4.1 - Prob. 7E Ch. 4.1 - Prob. 8E Ch. 4.1 - Prob. 9E Ch. 4.1 - Prob. 10E Ch. 4.1 - Prob. 11E Ch. 4.1 - Prob. 12E Ch. 4.1 - Prob. 13E Ch. 4.1 - Prob. 14E Ch. 4.1 - Prob. 15E Ch. 4.1 - Prob. 16E Ch. 4.1 - Prob. 17E Ch. 4.1 - Prob. 18E Ch. 4.1 - Prob. 19E Ch. 4.1 - Prob. 20E Ch. 4.1 - Prob. 21E Ch. 4.1 - Prob. 22E Ch. 4.1 - Prob. 23E Ch. 4.1 - Prob. 24E Ch. 4.1 - Prob. 25E Ch. 4.1 - Prob. 26E Ch. 4.1 - Prob. 27E Ch. 4.1 - Prob. 28E Ch. 4.1 - Prob. 29E Ch. 4.1 - Prob. 30E Ch. 4.1 - Prob. 31E Ch. 4.1 - Prob. 32E Ch. 4.1 - Prob. 33E Ch. 4.1 - Prob. 34E Ch. 4.1 - Prob. 35E Ch. 4.1 - Prob. 36E Ch. 4.1 - Prob. 37E Ch. 4.1 - Prob. 38E Ch. 4.1 - Prob. 39E Ch. 4.1 - Prob. 40E Ch. 4.1 - Prob. 41E Ch. 4.1 - Prob. 42E Ch. 4.1 - Prob. 43E Ch. 4.1 - Prob. 44E Ch. 4.1 - Prob. 45E Ch. 4.1 - Prob. 46E Ch. 4.1 - Prob. 47E Ch. 4.1 - Prob. 48E Ch. 4.1 - Prob. 49E Ch. 4.1 - Prob. 50E Ch. 4.1 - Prob. 51E Ch. 4.1 - Prob. 52E Ch. 4.1 - Prob. 53E Ch. 4.1 - Prob. 54E Ch. 4.1 - Prob. 55E Ch. 4.1 - Prob. 56E Ch. 4.1 - 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Match the figure with their correct description: a. f ″ ( x ) < 0 for all x . b. f ″ ( x ) goes from + to − . c. f ″ ( x ) > 0 for all x . d. f ″ ( x ) goes from − to + .

Solution Summary: The author explains that the correct option for (a) is (C), (b), and (c).

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Match the figure with their correct description:

a. f″(x)<0 for all x.

b. f″(x) goes from + to −.

c. f″(x)>0 for all x.

d. f″(x) goes from − to +.

Want to see the full answer?

Chapter 4 Solutions

Match the figure with their correct description: a. f ″ ( x ) &lt; 0 for all x . b. f ″ ( x ) goes from + to − . c. f ″ ( x ) &gt; 0 for all x . d. f ″ ( x ) goes from − to + .

Solution Summary: The author explains that the correct option for (a) is (C), (b), and (c).

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Match the figure with their correct description: a. f″(x)<0 for all x. b. f″(x) goes from + to −. c. f″(x)>0 for all x. d. f″(x) goes from − to +.

Want to see the full answer?

Chapter 4 Solutions

Match the figure with their correct description: a. f ″ ( x ) < 0 for all x . b. f ″ ( x ) goes from + to − . c. f ″ ( x ) > 0 for all x . d. f ″ ( x ) goes from − to + .

Match the figure with their correct description:

a. f″(x)<0 for all x.

b. f″(x) goes from + to −.

c. f″(x)>0 for all x.

d. f″(x) goes from − to +.