Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
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Chapter 43, Problem 16SP
To determine
To show: The expression for the total energy of the orbiting electron according to
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Find the ranges of wavelengths of the Lyman series (=R (-),
2,3,4, ....) and of the Balmer series (=R (-), n = 3,4,5, ....) in the
n =
emission spectrum of a 1 hydrogen atom. Do these ranges overlap?
Determine all the allowed electron transitions for the hydrogen atom involving
only the lowest 5 energy levels. [Ignore electron spin.]
a.
Explicitly note the number of possible transitions.
[For parts b and c, the atom is in an external magnetic field of 2.2T. Find
numerical values.]
b.
C.
Determine AE for the transition with the lowest energy change.
Determine AE for the transition with the highest energy change.
The Lyman series comprises a set of spectral lines. All of these lines involve a hydrogen atom whose electron undergoes a change in energy level, either beginning at the n = 1 level (in the case of an absorption line) or ending there (an emission line).
The inverse wavelengths for the Lyman series in hydrogen are given by
1 -
where n = 2, 3, 4, ... and the Rydberg constant R, = 1.097 x 10' m-. (Round your answers to at least one decimal place. Enter your answers in nm.)
%3D
(a) Compute the wavelength for the first line in this series (the line corresponding to n = 2).
nm
(b) Compute the wavelength for the second line in this series (the line corresponding to n = 3).
nm
(c) Compute the wavelength for the third line in this series (the line corresponding to n = 4).
nm
(d) In which part of the electromagnetic spectrum do these three lines reside?
O x-ray region
O ultraviolet region
O infrared region
O gamma ray region
O visible light region
Chapter 43 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
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- The wavelengths of the Lyman series for hydrogen are given by: = RH(1-1), n = 2, 3, 4, ... For the second of this series; calculate the energy (in eV). Note: 1.60 x 10^-19 J = 1.0 eV O 4.10 x 10^3 eV 2.12 x 10^3 eV 3² O 1.21 x 10^3 eV 3.30 x 10^3 eVarrow_forwardA hydrogen atom in an excited 5f state is in a magnetic fi eld of 3.00 T. How many energy states can the electron have in the 5f subshell? (Ignore the magnetic spin effects.) What is the energy of the 5f state in the absence of a magnetic fi eld? What will be the energy of each state in the magnetic field?arrow_forward(a) The Lyman series in hydrogen is the transition from energy levels n = 2, 3, 4, ... to the ground state n = 1. The energy levels are given by 13.60 eV En n- (i) What is the second longest wavelength in nm of the Lyman series? (ii) What is the series limit of the Lyman series? [1 eV = 1.602 x 1019 J, h = 6.626 × 10-34 J.s, c = 3 × 10° m.s] %3D Two emission lines have wavelengts A and + A2, respectively, where AA <<2. Show that the angular separation A0 in a grating spectrometer is given aproximately by (b) A0 = V(d/m)-2 where d is the grating constant and m is the order at which the lines are observed.arrow_forward
- Hydrogen atoms are excited by a laser to the ?=4, state and then allowed to emit. Calculate the wavelength of the 3⟶1 transition.arrow_forwardWhat would the orbital radius of an electron on a hydrogen atom be if it were at the very excited state where n = 50? [. ? ] nm Enterarrow_forwardline X1,s [eV] S Lyman a 1 Balmer a 2 10.20 Paschen a 12.09 Brackett a 4 12.75 What does the variation mean in practical terms.arrow_forward
- If, in 1 1 = Ry - you set ni = 1 and take n2 greater than 1, you generate what is known as the Lyman %3D series. Find the wavelength of the first mem- ber of this series. The value of ħ is 1.05457 × 10¬34 J.s; the Rydberg constant for hydrogen is 1.09735 × 10’ m¬'; the Bohr radius is 5.29177 × 10¬1" m; and the ground state energy for hydrogen is 13.6057 eV. Answer in units of nm. Consider the next three members of this se- ries. The wavelengths of successive members of the Lyman series approach a common limit as n2 → ∞. What is this limit? Answer in units of nm.arrow_forwardFor hydrogen atoms in a 4p state what is the maximum difference in potential energy (in eV) between atoms when placed in a magnetic field of 5.1 T? Ignore intrinsic spin. 2.34e-4 ev Need Help? Submit Answer Read It Viewing Saved Work Revert to Last Responsearrow_forwardAn electron in the hydrogen atom makes a transition from an energy state of principal quantum numbers ni to the n = 2 state. If the photon emitted has a wavelength of 434 nm, what is the value of ni? Can you give me the full solution? It says that the answer is 5 but I don't know how to get that. Thank you!arrow_forward
- The ionization energy for neon (Z=10) is 21.6 eV, and thatfor sodium(Z=11) is 5.1 eV. Explain the large difference.arrow_forwardThe shortest wavelength of the Lyman series of hydrogen is 91.13 nm. Find the three longest wavelengths in this series! Please Answer my question Im needed Max 30 minutes please.... Thank uarrow_forwardThe energy difference between the 1st excited state (n = 2) and the 2nd excited state (n = 3) in the hydrogen atom is 1.9 eV, what is the wavelength of the emission line resulting from the electron transitions between those two levels? Give your answer in units of nanometers (nm).arrow_forward
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