Explanation Given: The given function is y = 2 x 2 + 1 − x . Calculation: Given: the given interval is [ 0 , 2 ] . Use sum/ difference rule . ( f ± g ) ' = f ' ± g ' y = 2 x 2 + 1 − x y ' = 2 d d x x 2 + 1 − d d x ( x ) Apply chain rule. d f ( u ) d x = d f d u ⋅ d u d x y ' = 2 d d x x 2 + 1 − d d x ( x ) Let f = u , u = x 2 + 1 y ' = [ 2 d d u u d d x ( x 2 + 1 ) ] − 1 y ' = [ 2 1 2 u ⋅ 2 x ] − 1 Substitute u = x 2 + 1 y ' = [ 2 1 2 x 2 + 1 ⋅ 2 x ] − 1 y ' = 2 x x 2 + 1 − 1 For critical point y ' = 0

4th Edition

ISBN: 9781319545956

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 4.2, Problem 42E

To determine

Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4.2, Problem 41E

Chapter 4.2, Problem 43E

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Chapter 4 Solutions

CALCULUS W/ACHIEVE PLATFORM

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

Solution Summary: The author calculates the minimum and maximum values of a given function in the given interval by comparing with critical and end points.

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Find the minimum and maximum values of the given function in the given interval by comparing with critical and end points.

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Chapter 4 Solutions