Concept explainers
Exercises 31–38 should be done in two ways: by hand and by using technology where possible.
Let
Evaluate:
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- In Exercises 9–12, find all real solutions to the equations.arrow_forwardFor Exercises 101–104, verify by substitution that the given values of x are solutions to the given equation. 101. x + 25 = 0 102. x + 49 = 0 a. x = 5i a. x = 7i b. x = -5i b. x = -7i 103. x - 4x + 7 = 0 104. x - 6x + 11 = 0 a. x = 2 + iV3 b. x = 2 – iV3 a. x = 3 + iVā b. x = 3 – iV2arrow_forwardExercises 7–12: Determine whether the equation is linear or nonlinear by trying to write it in the form ax + b = 0. 7. 3x – 1.5 = 7arrow_forward
- Exercises 38–40 will help you prepare for the material covered in the first section of the next chapter. In Exercises 38-39, simplify each algebraic expression. 38. (-9x³ + 7x? - 5x + 3) + (13x + 2r? – &x – 6) 39. (7x3 – 8x? + 9x – 6) – (2x – 6x? – 3x + 9) 40. The figures show the graphs of two functions. y y 201 10- .... -20- flx) = x³ glx) = -0.3x + 4x + 2arrow_forwardYou may find it helpful to review the information in the Reasonable Answers box from this section before answering Exercises 13–16. Verify that the solutions you found to Exercise 9 are indeed homogeneous solutions.arrow_forwardIn Exercises 23–25, solve each equation. If the solution set is Ø or (-0, ), classify the equation as an inconsistent equation or an identity. 23. 3(2x – 4) = 9 – 3(x + 1) 2x 24. x - 4 x + 1 4 2 4 25. 3(x – 4) + x = 2(6 + 2x)arrow_forward
- For Exercises 39–42, multiply the radicals and simplify. Assume that all variable expressions represent positive real numbers. 39. (6V5 – 2V3)(2V3 + 5V3) 40. (7V2 – 2VIT)(7V2 + 2V1T) 41. (2c²Va – 5ď Vc) 42. (Vx + 2 + 4)²arrow_forwardFor Exercises 37–44, find the difference quotient and simplify. (See Examples 4-5) 37. f(х) — — 2х + 5 38. f(x) = -3x + 8 39. f(x) = -5x² – 4x + 2 40. f(x) = -4x - 2x + 6 41. f(x) = x' + 5 42. f(x) = 1 43. f(x) = 1 44. f(x) = x + 2arrow_forwardIn Exercises 20–21, solve each rational equation. 11 20. x + 4 + 2 x2 – 16 - x + 1 21. x? + 2x – 3 1 1 x + 3 x - 1 ||arrow_forward
- Can you answer exercise no 1?arrow_forwardIn Exercises 43–54, solve each absolute value equation or indicate the equation has no solution. 43. |x – 2| = 7 45. |2x – 1| = 5 47. 2|3x – 2| = 14 44. |x + 1| = 5 46. |2r – 3| = 11 48. 3|2x – 1| = 21 %3D %3D 5 24 - + 6 = 18 50. 4 1 x + 7 = 10 51. |x + 1| + 5 = 3 53. |2x – 1| + 3 = 3 52. |x + 1| + 6 = 2 54. |3x – 2| + 4 = 4arrow_forwardPlease do #1, all parts thank you!arrow_forward
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