Computer Science: An Overview (13th Edition) (What's New in Computer Science)
13th Edition
ISBN: 9780134875460
Author: Glenn Brookshear, Dennis Brylow
Publisher: PEARSON
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Chapter 4.1, Problem 2QE
Program Plan Intro
Bridge:
The bridge is a device used for the network connection. A bridge connects two buses, but it does not pass all the information and messages through the connection.
Switch:
The switch is a device used for the network connection. A switch connects multiple buses that are more than two buses across the connection. It is used to connect the segments of the networks.
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Students have asked these similar questions
Calculate the voltage across the points P and R
shown in the figure Q4. Also find the value of resistor Rs
to balance the bridge.
R1
R2
50 Ω
100 O
100V
R
Rs
P
Vs
Vout
40 Q
Strain Gauge
50 2
Figure Q4
1
A combinational circuit has three inputs (C,1,,1o) and two
outputs (01,00). The function is implemented as the following:
If C
= 0, then O,00 becomes I, 1o. If C = 1, then O,0, becomes
(1,11)+1. For example, if C = 1 and 1, is 01, 0,0, becomes
10. Note that, if I, 1, is 11 and = 1, then the output value wraps
around 00, without any overflow.
%3D
F
Oo
The Boolean expression for 01 and O0 and in sum of minterms form are:
Select one:
None of the above.
Oo = E(2,3,4,5)
Oc 01 = E(2,3,5,6) 0, = E(1,3,4,6)
O01Σ (1,3,5,6) 00Σ( 2,3,4,5)
O c.
%3D
0 Σ(1,3,5,6) 0,-Σ(2,3,4,5)
Chapter 4 Solutions
Computer Science: An Overview (13th Edition) (What's New in Computer Science)
Ch. 4.1 - What is an open network?Ch. 4.1 - Prob. 2QECh. 4.1 - What is a router?Ch. 4.1 - Prob. 4QECh. 4.1 - Prob. 5QECh. 4.1 - Prob. 6QECh. 4.2 - Prob. 1QECh. 4.2 - Prob. 2QECh. 4.2 - Prob. 3QECh. 4.2 - Prob. 4QE
Ch. 4.2 - Prob. 5QECh. 4.2 - Prob. 6QECh. 4.2 - Prob. 7QECh. 4.2 - Prob. 8QECh. 4.3 - Prob. 1QECh. 4.3 - Prob. 2QECh. 4.3 - Prob. 3QECh. 4.3 - Prob. 4QECh. 4.3 - Prob. 5QECh. 4.4 - Prob. 1QECh. 4.4 - Prob. 2QECh. 4.4 - Prob. 3QECh. 4.4 - What keeps a computer on the Internet from...Ch. 4.5 - Prob. 1QECh. 4.5 - Prob. 2QECh. 4.5 - Prob. 3QECh. 4.5 - Prob. 4QECh. 4.6 - Prob. 1QECh. 4.6 - Prob. 2QECh. 4.6 - Prob. 3QECh. 4.6 - Prob. 4QECh. 4.6 - Prob. 5QECh. 4 - Prob. 1CRPCh. 4 - Prob. 2CRPCh. 4 - Prob. 3CRPCh. 4 - Prob. 4CRPCh. 4 - Prob. 5CRPCh. 4 - Prob. 6CRPCh. 4 - Prob. 7CRPCh. 4 - Prob. 8CRPCh. 4 - Prob. 9CRPCh. 4 - Prob. 10CRPCh. 4 - Prob. 11CRPCh. 4 - Prob. 12CRPCh. 4 - Prob. 13CRPCh. 4 - Prob. 14CRPCh. 4 - Prob. 15CRPCh. 4 - Prob. 16CRPCh. 4 - Prob. 17CRPCh. 4 - Prob. 18CRPCh. 4 - Prob. 19CRPCh. 4 - Prob. 20CRPCh. 4 - Prob. 21CRPCh. 4 - Prob. 22CRPCh. 4 - Prob. 23CRPCh. 4 - Prob. 24CRPCh. 4 - Prob. 25CRPCh. 4 - Prob. 26CRPCh. 4 - Prob. 27CRPCh. 4 - Prob. 28CRPCh. 4 - Prob. 29CRPCh. 4 - Prob. 30CRPCh. 4 - Prob. 31CRPCh. 4 - Prob. 32CRPCh. 4 - Prob. 33CRPCh. 4 - Prob. 34CRPCh. 4 - Prob. 35CRPCh. 4 - Prob. 36CRPCh. 4 - Prob. 37CRPCh. 4 - Prob. 38CRPCh. 4 - Prob. 39CRPCh. 4 - Prob. 40CRPCh. 4 - Prob. 41CRPCh. 4 - Prob. 42CRPCh. 4 - Prob. 43CRPCh. 4 - Prob. 44CRPCh. 4 - Prob. 45CRPCh. 4 - Prob. 46CRPCh. 4 - Prob. 47CRPCh. 4 - Prob. 48CRPCh. 4 - Prob. 49CRPCh. 4 - Prob. 50CRPCh. 4 - Prob. 1SICh. 4 - Prob. 2SICh. 4 - Prob. 3SICh. 4 - Prob. 4SICh. 4 - Prob. 5SICh. 4 - Prob. 6SICh. 4 - Prob. 7SICh. 4 - Prob. 8SICh. 4 - Prob. 9SICh. 4 - Prob. 10SICh. 4 - Prob. 11SICh. 4 - Prob. 12SI
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- A combinational circuit has three inputs (C,,1o) and two outputs (0, 0). The function is implemented as the following: If C = 0, then 0,0, becomes I, lg. If C = 1, then 0,0, becomes (1,1)+1. For example, if C = 1 and I,l, is 01, 0,0, becomes 10. Note that, if 14 1, is 11 and = 1 , then the output value wraps around 00, without any overflow. The Boolean expression for 01 and 00 and in sum of minterms form are: Select one O . None of the above. . 0Σ(13,5,6) 0, Σ(2.3,4,5) ο. 0, Σ(2,3,5,6) 00-Σ(1,3,4,6) o10,Σ(1,3,5,6) 0,Σ2,3,4,5 ) %3D d.arrow_forwardPlease see attachment.arrow_forwardPlease see question attached.arrow_forward
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