FUNDAMENTALS OF PHYSICS (LLF)+WILEYPLUS
11th Edition
ISBN: 9781119459132
Author: Halliday
Publisher: WILEY
expand_more
expand_more
format_list_bulleted
Question
Chapter 41, Problem 28P
To determine
To calculate:
the Fermi energy of gold.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
What is the Fermi energy of gold (a monovalent metal with molar mass 197 g/mol and density 19.3 g/cm3)?
A certain material has a molar mass of 20.0 g/mol, a Fermi energy of 5.00 eV, and 2 valence electrons per atom.What is the density (g/cm3)?
The Fermi energy of aluminum is 11.6 eV; its density and molar mass are 2.70 g/cm3 and 27.0 g/mol, respectively. From these data, determine the number of conduction electrons per atom.
Chapter 41 Solutions
FUNDAMENTALS OF PHYSICS (LLF)+WILEYPLUS
Ch. 41 - Prob. 1QCh. 41 - Prob. 2QCh. 41 - Prob. 3QCh. 41 - Prob. 4QCh. 41 - Prob. 5QCh. 41 - Prob. 6QCh. 41 - Prob. 7QCh. 41 - Prob. 8QCh. 41 - Prob. 9QCh. 41 - Prob. 10Q
Ch. 41 - Prob. 11QCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5PCh. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 12PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 22PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37PCh. 41 - Prob. 38PCh. 41 - Prob. 39PCh. 41 - Prob. 40PCh. 41 - Prob. 41PCh. 41 - Prob. 42PCh. 41 - Prob. 43PCh. 41 - Prob. 44PCh. 41 - Prob. 45PCh. 41 - Prob. 46PCh. 41 - Prob. 47PCh. 41 - Prob. 48PCh. 41 - Prob. 49PCh. 41 - Prob. 50PCh. 41 - Prob. 51PCh. 41 - Prob. 52PCh. 41 - Prob. 53P
Knowledge Booster
Similar questions
- Silver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the density of states (in states>J and states>eV) at the Fermi energy for a block of silver of volume 1.0 cm3?arrow_forwardSodium is a monovalent metal having density 0.971 g/cm3 and a molar mass of 23.0 g/mol. Use this information to calculate (a) the density of charge carriers and (b) the Fermi energy of sodium.arrow_forwardSilver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the Fermi energy (in J and eV) of silver?arrow_forward
- In solid KCI the smallest distance between the centers of a. potassium ion and a chloride ion is 314 pm. Calculate the length of the edge of the unit cell and the density of KCI, assuming it has the same structure as sodium chloride.arrow_forwardThe density of sodium metal at room temperature is 0.95 g/cm³. Assuming that there is one conduction electron per sodium atom, calculate the Fermi energy and Fermi tempera- ture of sodium.arrow_forwardSilicon has a conductivity of 5×10-4 (Q.m)-1 when pure. How many arsenic atoms/m3 are required so that the conductivity of 200 (Q .m)-1. The mobility of electrons is O.13 (m2/V. Sec), mobility of holes is 0.05(m2/V.Sec) O 2.4038*10^16 /m-3 O 9.6153*10^21/m-3 O 4*10^5 /m-3 O 9.4089*10^5 /m-3 O other:arrow_forward
- Copper metal can be well-described by assuming that the electrons inside are free, with a den- sity ne = 8.47 × 1028 m-³. Calculate the Fermi energy EF.arrow_forwardSilver melts at 961°C. At the melting point, what fraction of the conduction electrons are in states with energies greater than the Fermi energy of 5.5 eV?arrow_forwardn=1 11. The ground state energy of a free Fermi gas comprising N particles in a box of volume V in terms of Part = N the Fermi energy Ep is NORT A) NEF B) NEF A) PR B) P₁ = e C) P₁₁ = e D) Pn=f NEF D) NEF E) 2 N 12. For a given macrostate of a system, let P be the probability that the system is in the microstate 14 >. The corresponding Gibbs entropy is given by S-k En PinPn. We can obtain the familiar Boltzmann entropy S = k In from the given Gibbs entropy if the probability distribution is, (♫ is the number of accessible microstates), = hw WEE = Ef- nt & hun) 1 A) E B) E2 2 N ~/M D) E E) Independent of energy E + 2 E) P₁ = 2² = 13.For a system with linear dispersion E(k)= hvk, in three dimensions, the density of states at energy E depends on energy as + 1 h mk + / buk 2n=N M/M. rim Ef = 1/1/₂ n = q S = -x En Pulupn. S = Kenn -* & Plukk € (K) = hvkarrow_forward
- Physics Consider a solid piece of Lithium, Li, which is a metal and has electron density n = 4.70 × 1022 cm−3 . Assuming a free-electron quantum model, i.e., the Sommerfeld model, determine the, Fermi energy, density of states, and number of available states up to an energy of 4 eV for a cubic piece of Li of side 1 mm.arrow_forwardA) Calculate the highest linear density (atoms/m) encountered in Vanadium (V)?B) For Vanadium, calculate the planar density value for the (100) plane?Vanadyum has BBC unit cell. Its atomic weigth and density are 50.94 g/mol and 5.8 g/cm3,respectively.arrow_forwardThe average energy of an electron in a specific metal at 0 K is 2.9 eV. Calculate the value of the Fermi energy in a specific metal. (A) 5.51 eV (В) 2.44 eV (С) 4.83 eV (D) 2.83 eVarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning