Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
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Chapter 40, Problem 34SP
To determine
The wavelength of the monochromatic light, if the width of the single slit of width
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Chapter 40 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Ch. 40 - 40.16 [I] Considering Young’s experiment using...Ch. 40 - Prob. 17SPCh. 40 - Prob. 18SPCh. 40 - Prob. 19SPCh. 40 - Prob. 20SPCh. 40 - 21. Suppose we have Young’s double-slit setup with...Ch. 40 - Prob. 22SPCh. 40 - Prob. 23SPCh. 40 - Prob. 24SPCh. 40 - 40.25 [II] Two sound sources send identical waves...
Ch. 40 - Prob. 26SPCh. 40 - 40.27 [I] A double-slit experiment is done in the...Ch. 40 - 40.28 [I] In Problem 40.27, if the slit-to-screen...Ch. 40 - 40.29 [I] Red light of wavelength 644 nm, from a...Ch. 40 - 40.30 [I] Two flat glass plates are pressed...Ch. 40 - Prob. 32SPCh. 40 - Prob. 33SPCh. 40 - Prob. 34SPCh. 40 - 40.35 [II] Green light of wavelength 500 nm is...Ch. 40 - 40.36 [II] A narrow beam of yellow light of...Ch. 40 - 40.37 [II] Blue light of wavelength m is...Ch. 40 - 40.38 [II] Determine the ratio of the wavelengths...Ch. 40 - 40.39 [II] A spectrum of white light is obtained...Ch. 40 - Prob. 40SPCh. 40 - Prob. 41SP
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- A monochromatic beam of light of wavelength 500 nm illuminates a double slit having a slit separation of 2.00 105 m. What is the angle of the second-order bright fringe? (a) 0.050 0 rad (b) 0.025 0 rad (c) 0.100 rad (d) 0.250 rad (e) 0.010 0 radarrow_forwardA beam of monochromatic green light is diffracted by a slit of width 0.550 mm. The diffraction pattern forms on a wall 2.06 m beyond the slit. The distance between the positions of zero intensity on both sides of the central bright fringe is 4.10 mm. Calculate the wavelength of the light.arrow_forwardIn Figure P36.10 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4? Figure P36.10arrow_forward
- A monochromatic light of unknown wavelength is incident on a slit of width 20 m. A diffraction pattern is seen at a screen 2.5 m away where the central maximum is spread over a distance of 10.0 cm. Find the wavelength.arrow_forwardIn Figure P27.7 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4?arrow_forwardWhen a monochromatic light of wavelength 430 nm incident on a double slit of slit separation 5 m, there are 11 interference fringes in its central maximum. How many interference fringes will be in the central maximum of a light of wavelength 632.8 nm for the same double slit?arrow_forward
- Monochromatic light is incident on a pair of slits that are separated by 0.200 mm. The screen is 2.50 m away from the slits. a. If the distance between the central bright fringe and either of the adjacent bright fringes is 1.67 cm, find the wavelength of the incident light. b. At what angle does the next set of bright fringes appear?arrow_forwardConsider a single-slit diffraction pattern for =589 nm, projected on a screen that is 1.00 m from a slit of width 0.25 mm. How far from the center of the pattern are the centers of the first and second dark fringes?arrow_forwardRed light (wavelength 632.8 nm in air) from a Helium-Neon laser is incident on a single slit of width 0.05 mm. The entire apparatus is immersed in water of refractive index 1.333. Determine the angular width of the central peak.arrow_forward
- Show that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forwardFor 600-nm wavelength light and a slit separation of 0.12 mm, what are the angular positions of the first and third maxima in the double slit interference pattern?arrow_forwardA single slit of width 2100 nm is illuminated normally by a wave of wavelength 632.8 nm. Find the phase difference between waves from the top and one third from the bottom of the slit to a point on a screen at a horizontal distance of 2.0 m and vertical distance of 10.0 cm from the center.arrow_forward
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