FUNDAMENTALS OF PHYSICS (LLF)+WILEYPLUS
11th Edition
ISBN: 9781119459132
Author: Halliday
Publisher: WILEY
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Chapter 40, Problem 17P
To determine
To calculate:
the magnitude of
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F.j = (-e)(-v,k) × (B,i + B.k)
ev Bzj. Solving for B gives
F.
Br
8.50x10 16 N
= 1.13 T. Therefore B = 1.13 Ti – 0.772 Tk. The magnitude o
A group of particles is traveling in a magnetic field of
unknown magnitude and direction. You observe that a
proton moving at 1.70 km/s in the +x-direction
experiences a force of 2.10x10-16 N in the +y-
direction, and an electron moving at 4.70 km/s in the
eve
(1.60x10 19 C)(4700 m/s)
is B = VB? + B =
(1.13 T)² + (-0.772 T)² = 1.37 T.
-z-direction experiences a force of 8.50x10-16 N in
the +y-direction.
Part B
For related problem-solving tips and strategies, you
may want to view a Video Tutor Solution of Magnetic
force on a proton.
What is the direction of the magnetic field? (in the xz-plane)
Express your answer in degrees.
0 = 60.59
° from the -z-direction to the +x-direction
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Magnetization of a water sample.
(a) Calculate the number of particles that contribute to the magnetization of a 2 cm3 sample of water at 37°C in a field strength of 3T. Remember the number of 1H nuclei in the water molecule.
(b) Calculate the magnitude of the magnetization vector M for that sample.
The potential energy of a magnetic moment
in an external magnetic field is given by U =
-u-B. The magnetic moment associated with
the spin of an electron is 5.79 x 10-5 eV/T.
Calculate the difference in energy between
the two possible orientations of an electron in
energy in a magnetic field B = (0.8 T) k.
Answer in units of eV.
%3D
%3D
If these electrons are bombarded with photons
of energy equal to this energy difference, "spin
flip" transitions can be induced.
Find the wavelength of the photons needed
for such transitions. (This phenomenon is
called electron spin resonance.)
Answer in units of cm.
Chapter 40 Solutions
FUNDAMENTALS OF PHYSICS (LLF)+WILEYPLUS
Ch. 40 - Prob. 1QCh. 40 - Prob. 2QCh. 40 - Prob. 3QCh. 40 - Prob. 4QCh. 40 - Prob. 5QCh. 40 - Prob. 6QCh. 40 - Prob. 7QCh. 40 - Figure 40-22 shows three points at which a spin-up...Ch. 40 - Prob. 9QCh. 40 - Prob. 10Q
Ch. 40 - Prob. 11QCh. 40 - Prob. 12QCh. 40 - Prob. 13QCh. 40 - Prob. 14QCh. 40 - Prob. 1PCh. 40 - Prob. 2PCh. 40 - Prob. 3PCh. 40 - Prob. 4PCh. 40 - Prob. 5PCh. 40 - Prob. 6PCh. 40 - Prob. 7PCh. 40 - Prob. 8PCh. 40 - Prob. 9PCh. 40 - Prob. 10PCh. 40 - Prob. 11PCh. 40 - Prob. 12PCh. 40 - SSM What is the acceleration of a silver atom as...Ch. 40 - Prob. 14PCh. 40 - Prob. 15PCh. 40 - Assume that in the SternGerlach experiment as...Ch. 40 - Prob. 17PCh. 40 - Prob. 18PCh. 40 - Prob. 19PCh. 40 - Prob. 20PCh. 40 - Prob. 21PCh. 40 - Prob. 22PCh. 40 - Prob. 23PCh. 40 - Prob. 24PCh. 40 - Prob. 25PCh. 40 - Prob. 26PCh. 40 - Prob. 27PCh. 40 - Show that the number of states with the same...Ch. 40 - Prob. 29PCh. 40 - For a helium atom in its ground state, what are...Ch. 40 - Prob. 31PCh. 40 - Prob. 32PCh. 40 - Prob. 33PCh. 40 - Prob. 34PCh. 40 - Prob. 35PCh. 40 - Prob. 36PCh. 40 - Prob. 37PCh. 40 - Prob. 38PCh. 40 - Prob. 39PCh. 40 - Prob. 40PCh. 40 - Prob. 41PCh. 40 - Prob. 42PCh. 40 - Prob. 43PCh. 40 - Prob. 44PCh. 40 - Prob. 45PCh. 40 - Prob. 46PCh. 40 - Prob. 47PCh. 40 - Prob. 48PCh. 40 - Prob. 49PCh. 40 - Prob. 50PCh. 40 - Prob. 51PCh. 40 - Prob. 52PCh. 40 - Prob. 53PCh. 40 - Prob. 54PCh. 40 - Prob. 55PCh. 40 - Prob. 56PCh. 40 - Prob. 57PCh. 40 - Prob. 58PCh. 40 - Prob. 59PCh. 40 - Prob. 60PCh. 40 - Prob. 61PCh. 40 - Prob. 62PCh. 40 - Prob. 63PCh. 40 - Prob. 64PCh. 40 - Prob. 65PCh. 40 - Prob. 66PCh. 40 - Prob. 67PCh. 40 - Prob. 68PCh. 40 - Prob. 69PCh. 40 - Prob. 70PCh. 40 - Prob. 71PCh. 40 - Prob. 72PCh. 40 - Prob. 73PCh. 40 - Prob. 74PCh. 40 - Prob. 75PCh. 40 - Prob. 76PCh. 40 - Prob. 77PCh. 40 - Prob. 78PCh. 40 - Prob. 79P
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- A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net magnetic moment, but the field aligns 12% of the magnetic moments of the atoms (that is, 12% of the magnetic moments of the loosely bound electrons in the sphere, with one such electron per atom). The magnetic moment of those aligned electrons is the sphere’s intrinsic magnetic moment .What is the sphere’s resulting angular speed v?arrow_forwardThe magnetism of permanent magnets arises because the inherent magnetic moment of electrons causes them to act like little compass needles. Protons also have an inherent magnetic moment, and this is the basis for magnetic resonance imaging (MRI) in medicine.Although a compass needle would prefer to align with a magnetic field, the needle can point in any direction. This isn’t the case for the magnetic moment of a proton. Quantum physics tells us that the proton’s energy must be quantized. There are only two possible energy levels—and thus two possible orientations—for protons in a magnetic field: E1 = -μB magnetic moment aligned with the field E2 = +μB magnetic moment aligned opposite the fieldwhere μ = 1.41 x 10-26 J/T is the known value of the proton’s magnetic moment. FIGURE 28.24 shows the two possible energy states. The magnetic moment, like a compass needle, “wants” to align with the field, so that is the lower-energy state.…arrow_forwardPlease see attached question.arrow_forward
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