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Chapter 40, Problem 10P
To determine

Show that A=2L using normalization condition on ψ.

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The wave function for a quantum particle confined to moving in a one-dimensional box located between x = 0 and x = L is                                                        ψ(x) = A sin (nπx/L)Use the normalization condition on ψ to show that                                                               A = √2/L
An electron is trapped in an infinitely deep one-dimensional well of width 0,251 nm. Initially the electron occupies the n=4 state. Suppose the electron jumps to the ground state with the accompanying emission of photon. What is the energy of the photon?
An electron is confined to move in the xy plane in a rectangle whose dimensions are Lx and Ly. That is, the electron is trapped in a two dimensional potential well having lengths of Lx and Ly. In this situation, the allowed energies of the electron depend on two quantum numbers nx and ny and are given by                                             E = h2/8me (nx2/Lx2 + ny2/Ly2)Using this information, we wish to find the wavelength of a photon needed to excite the electron from the ground state to the second excited state, assuming Lx = Ly = L. (a) Using the assumption on the lengths, write an expression for the allowed energies of the electron in terms of the quantumnumbers nx and ny. (b) What values of nx and ny correspond to the ground state? (c) Find the energy of the ground state. (d) What are the possible values of nx and ny for the first excited state, that is, the next-highest state in terms of energy? (e) What are the possible values of nx and ny for thesecond excited state?…
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