Chapter 4, Problem 73A

How many electrons, protons, and neutrons arecontained in each atom?
a. ${}_{55}^{132}Cs$   c. ${}_{69}^{163}Tm$

b. ${}_{27}^{59}Co$  d. ${}_{30}^{70}Zn$

Interpretation Introduction

Interpretation:

The number of electrons, protons and neutrons of Cs atom is to be calculated

Concept introduction:

The number of protons in an atom is mentioned as atomic number.

$\text{Atomic number = Number of protons}$

$\text{Number of protons = Number of electrons ( All atoms are neutral)}$

$\text{X}$

Where, $\text{A = Mass number}$

$\text{Z = Atomic number}$

$\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)$

Answer to Problem 73A

$\text{C}\text{s}$

$\begin{array}{l}\text{Number of proton = 55}\hfill \\ \text{Number of electrons = 55}\hfill \\ \text{Number of neutrons = 77}\hfill \end{array}$

Explanation of Solution

$\text{C}\text{s}$

$\begin{array}{l}\text{Atomic number = 55}\hfill \\ \text{Number of protons = Atomic number}\hfill \\ \text{}\text{ = 55}\hfill \end{array}$

$\begin{array}{l}\text{Number of electrons = Number of protons}\hfill \\ \text{}\text{ = 55}\hfill \end{array}$

$\begin{array}{l}\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)\hfill \\ \text{ = 132 – 55}\hfill \\ \text{ = 77}\hfill \end{array}$

Interpretation Introduction

(b)

Interpretation:

The number of electrons, protons and neutrons of Co atom is to be calculated

Concept introduction:

The number of protons in an atom is mentioned as atomic number.

$\text{Atomic number = Number of protons}$

$\text{Number of protons = Number of electrons ( All atoms are neutral)}$

$\text{X}$

Where, $\text{A = Mass number}$

$\text{Z = Atomic number}$

$\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)$

Answer to Problem 73A

$\text{C}\text{o}$

$\begin{array}{l}\text{Number of proton = 27}\\ \text{Number of electron = 27}\\ \text{Number of neutron = 32}\end{array}$

Explanation of Solution

$\text{C}\text{o}$

$\begin{array}{l}\text{Atomic number = 27}\hfill \\ \text{Number of protons = Atomic number}\hfill \\ \text{}\text{ = 27}\hfill \end{array}$

$\begin{array}{l}\text{Number of electrons = Number of protons}\hfill \\ \text{ = 27}\hfill \end{array}$

$\begin{array}{l}\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)\hfill \\ \text{ = 59 – 27}\hfill \\ \text{ = 32}\hfill \end{array}$

Interpretation Introduction

Interpretation:

The number of electrons, protons and neutrons of Tm atom is to be calculated

Concept introduction:

The number of protons in an atom is mentioned as atomic number.

$\text{Atomic number = Number of protons}$

$\text{Number of protons = Number of electrons ( All atoms are neutral)}$

$\text{X}$

Where, $\text{A = Mass number}$

$\text{Z = Atomic number}$

$\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)$

Answer to Problem 73A

$\text{T}\text{m}$

$\begin{array}{l}\text{Number of proton = 69}\hfill \\ \text{Number of electrons = 69}\hfill \\ \text{Number of neutrons = 94}\hfill \end{array}$

Explanation of Solution

$\text{T}\text{m}$

$\begin{array}{l}\text{Atomic number = 69}\hfill \\ \text{Number of protons = Atomic number}\hfill \\ \text{}\text{ = 69}\hfill \end{array}$

$\begin{array}{l}\text{Number of electrons = Number of protons}\hfill \\ \text{ = 69}\hfill \end{array}$

$\begin{array}{l}\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)\hfill \\ \text{ = 163 – 69}\hfill \\ \text{ = 94}\hfill \end{array}$

Interpretation Introduction

Interpretation:

The number of electrons, protons and neutrons of Zn atom is to be calculated

Concept introduction:

The number of protons in an atom is mentioned as atomic number.

$\text{Atomic number = Number of protons}$

$\text{Number of protons = Number of electrons ( All atoms are neutral)}$

$\text{X}$

Where, $\text{A = Mass number}$

$\text{Z = Atomic number}$

$\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)$

Answer to Problem 73A

$\text{Z}\text{n}$

$\begin{array}{l}\text{Number of proton = 30}\hfill \\ \text{Number of electrons = 30}\hfill \\ \text{Number of neutrons = 40}\hfill \end{array}$

Explanation of Solution

$\text{Z}\text{n}$

$\begin{array}{l}\text{Atomic number = 30}\hfill \\ \text{Number of protons = Atomic number}\hfill \\ \text{}\text{ = 30}\hfill \end{array}$

$\begin{array}{l}\text{Number of electrons = Number of protons}\hfill \\ \text{ = 30}\hfill \end{array}$

$\begin{array}{l}\text{Number of neutrons = Mass number }\left(\text{A}\right)\text{ – Atomic number }\left(\text{Z}\right)\hfill \\ \text{ = 70 – 30}\hfill \\ \text{ = 40}\hfill \end{array}$