EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
EBK GENERAL CHEMISTRY: THE ESSENTIAL CO
7th Edition
ISBN: 8220106637203
Author: Chang
Publisher: YUZU
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Chapter 4, Problem 4.43QP

(a)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(a)

Expert Solution
Check Mark

Explanation of Solution

Te oxidation number of Cl inClF

  • According to the rules, the Inter halogen compounds the Fluorine is always having 1 oxidation state and the sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The F in 1 oxidation state and Cl is in +1 state.

(b)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(b)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of I in IF7

  • According to the rules, the Inter halogen compounds the Fluorine is always having 1 oxidation state and the sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The F in 1 oxidation state and I is,

    7(-1)+1(X)=0-7+(X)=0X=+7

  • The oxidation number of I in IF7 is +7

(c)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(c)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of C in CH4

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of hydrogen is +1.
  • The H in +1 oxidation state and C is,

    4(1+)+1(X)=0(4+)+(X)=0X=-4C=-4

  • The oxidation number of C in CH4 is 4.

(d)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(d)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of C in C2H2

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Hydrogen is +1.
  • The H in +1 oxidation state and C is,

    2(1+)+2(X)=0(2+)+2(X)=02X=-2C=-1

  • The oxidation number of C in C2H2 is 1

(e)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(e)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of C in C2H4

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Hydrogen is +1.
  • The H in +1 oxidation state and C is,

4(1+)+2(X)=0(4+)+2(X)=02X=-4C=-2

  • The oxidation number of C in C2H4 is 2

(f)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(f)

Expert Solution
Check Mark

Explanation of Solution

To give the oxidation number of Cr in K2CrO4

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Oxygen is 2.
  • The O is in 2 and K is in +1 oxidation state and Cr is,

    2(1+)+1(X)+4(-2)=0(2+)+1(X)+(-8)=0X=+6Cr=+6

  • The oxidation number of Cr in K2CrO4 is +6.

(g)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(g)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of Cr in K2Cr2O7

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Oxygen is 2.
  • The O is in 2 and K is in +1 oxidation states and Cr is,

    2(1+)+2(X)+7(-2)=0(2+)+2(X)+(-14)=02X=+12X=+6Cr=+6

  • The oxidation number of Cr in K2Cr2O7 is +6

(h)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(h)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of Mn in KMnO4

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Oxygen is 2.
  • The O is in 2 and K is in +1 oxidation states and Mn is,

    (1+)+1(X)+4(-2)=0(1+)+1(X)+(-8)=0X=+7Mn=+7

  • The oxidation number of Mn in KMnO4 is +7

(i)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(i)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of C in NaHCO3

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the general oxidation state of Hydrogen is +1.
  • The earth metals always having +1 oxidation number only.
  • The O is in 2 and Na is in +1 oxidation states and C is,

    (1+)+(1+)1(X)+3(-2)=0(1+)+(1+)+1(X)+(-6)=0X=-4C=-4

  • The oxidation number of C in NaHCO3 is +4

(j)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(j)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of Li in Li2

  • Acceding to the rule, the oxidation number of atom in the elemental form is zero so Li2 is in elemental form so the oxidation number is zero.
  • The oxidation number of Li in Li2 is 0

(k)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(k)

Expert Solution
Check Mark

Explanation of Solution

To give the oxidation number of I in NaIO3is +5

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and in the oxohalide compounds oxidation number of halide is in positive.
  • The earth metals always having +1 oxidation number only.
  • The O is in 2 and Na is in +1 oxidation states and I is,

    1(1+)+X+3(-2)=0(1+)+X+(-6)=0X=+5I=+5

  • The oxidation number of I in NaIO3 is +5

(l)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(l)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of O in KO2

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the earth metals always having +1 oxidation number only.
  • The K is in +1 oxidation state and O is,

    1(1+)+2X=0(1+)+2X=02X=-1X=-12

  • The oxidation number of O in KO2 is 12

(m)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(m)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of P in PF6-

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is -1 and the general oxidation state of Fluorine is 1.

    6(-1)+X=-1X=(6+)-1X=+5P=+5

  • The oxidation number of P in PF6- is +5.

(n)

Interpretation Introduction

Interpretation:

The oxidation numbers of underlined atoms in given species are should be given.

Concept introduction:

Rules for assigning the Oxidation number

  • The oxidation number of atom in the elemental form is zero.
  • The sum of oxidation numbers of all the atoms present in the molecule is zero.
  • The general oxidation number for oxygen is 2 and hydrogen is +1.
  • The combination of any atoms in group 7 the oxidation number is varied.
  • The Inter halogen compounds the Fluorine is always having 1 oxidation state.
  • In the oxohalide compounds oxidation number of halide is in positive.
  • The general oxidation state of halides is -1.
  • The earth metals always having +1 oxidation number only.

(n)

Expert Solution
Check Mark

Explanation of Solution

The oxidation number of Au in KAuCl4

  • According to the rules, the sum of oxidation numbers of all the atoms present in the molecule is zero and the earth metals always having +1 oxidation number only.
  • Halides are having -1 general oxidation number.
  • The Cl in 1 and K is in +1 oxidation states and Au is,

    1(1+)+1X+4(-1)=0(1+)+1X+(-4)X=3+Au=3+

  • The oxidation number of Au in KAuCl4 is +3

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Chapter 4 Solutions

EBK GENERAL CHEMISTRY: THE ESSENTIAL CO

Ch. 4.5 - Prob. 1PECh. 4.5 - Prob. 2PECh. 4.5 - Prob. 3PECh. 4.5 - Prob. 1RCCh. 4.6 - Prob. 1PECh. 4.6 - Prob. 1RCCh. 4.6 - Prob. 2PECh. 4.6 - Prob. 3PECh. 4 - Prob. 4.1QPCh. 4 - Prob. 4.2QPCh. 4 - Prob. 4.3QPCh. 4 - 4.4 What is the difference between the following...Ch. 4 - 4.5 Water is an extremely weak electrolyte and...Ch. 4 - Prob. 4.6QPCh. 4 - Prob. 4.7QPCh. 4 - 4.8 Which of the following diagrams best...Ch. 4 - Prob. 4.9QPCh. 4 - Prob. 4.10QPCh. 4 - Prob. 4.11QPCh. 4 - Prob. 4.12QPCh. 4 - Prob. 4.13QPCh. 4 - Prob. 4.14QPCh. 4 - Prob. 4.15QPCh. 4 - Prob. 4.16QPCh. 4 - Prob. 4.17QPCh. 4 - Prob. 4.18QPCh. 4 - Prob. 4.19QPCh. 4 - Prob. 4.20QPCh. 4 - 4.21 Write ionic and net ionic equations for the...Ch. 4 - Prob. 4.22QPCh. 4 - Prob. 4.23QPCh. 4 - Prob. 4.24QPCh. 4 - Prob. 4.25QPCh. 4 - Prob. 4.26QPCh. 4 - Prob. 4.27QPCh. 4 - Prob. 4.28QPCh. 4 - Prob. 4.29QPCh. 4 - Prob. 4.30QPCh. 4 - Prob. 4.31QPCh. 4 - Prob. 4.32QPCh. 4 - Prob. 4.33QPCh. 4 - Prob. 4.34QPCh. 4 - Prob. 4.35QPCh. 4 - Prob. 4.36QPCh. 4 - Prob. 4.37QPCh. 4 - Prob. 4.38QPCh. 4 - 4.39 For the complete redox reactions given here,...Ch. 4 - Prob. 4.40QPCh. 4 - Prob. 4.41QPCh. 4 - Prob. 4.42QPCh. 4 - Prob. 4.43QPCh. 4 - Prob. 4.44QPCh. 4 - Prob. 4.45QPCh. 4 - Prob. 4.46QPCh. 4 - Prob. 4.47QPCh. 4 - Prob. 4.48QPCh. 4 - Prob. 4.49QPCh. 4 - Prob. 4.50QPCh. 4 - Prob. 4.51QPCh. 4 - Prob. 4.52QPCh. 4 - Prob. 4.53QPCh. 4 - Prob. 4.54QPCh. 4 - Prob. 4.55QPCh. 4 - Prob. 4.56QPCh. 4 - Prob. 4.57QPCh. 4 - Prob. 4.58QPCh. 4 - Prob. 4.59QPCh. 4 - Prob. 4.60QPCh. 4 - Prob. 4.61QPCh. 4 - Prob. 4.62QPCh. 4 - Prob. 4.63QPCh. 4 - Prob. 4.64QPCh. 4 - Prob. 4.65QPCh. 4 - Prob. 4.66QPCh. 4 - Prob. 4.67QPCh. 4 - Prob. 4.68QPCh. 4 - Prob. 4.69QPCh. 4 - 4.70 Distilled water must be used in the...Ch. 4 - 4.71 If 30.0 mL of 0.150 M CaCl2 is added to 15.0...Ch. 4 - Prob. 4.72QPCh. 4 - Prob. 4.73QPCh. 4 - Prob. 4.74QPCh. 4 - Prob. 4.75QPCh. 4 - Prob. 4.76QPCh. 4 - Prob. 4.77QPCh. 4 - Prob. 4.78QPCh. 4 - Prob. 4.79QPCh. 4 - Prob. 4.80QPCh. 4 - Prob. 4.81QPCh. 4 - Prob. 4.82QPCh. 4 - Prob. 4.83QPCh. 4 - Prob. 4.84QPCh. 4 - Prob. 4.85QPCh. 4 - Prob. 4.86QPCh. 4 - Prob. 4.87QPCh. 4 - Prob. 4.88QPCh. 4 - Prob. 4.89QPCh. 4 - Prob. 4.90QPCh. 4 - Prob. 4.91QPCh. 4 - Prob. 4.92QPCh. 4 - Prob. 4.93QPCh. 4 - 4.74 The molecular formula of malonic acid is...Ch. 4 - Prob. 4.95QPCh. 4 - Prob. 4.96QPCh. 4 - Prob. 4.97QPCh. 4 - Prob. 4.98QPCh. 4 - Prob. 4.99QPCh. 4 - Prob. 4.100QPCh. 4 - Prob. 4.101QPCh. 4 - Prob. 4.102QPCh. 4 - 4.103 These are common household compounds: table...Ch. 4 - Prob. 4.104QPCh. 4 - Prob. 4.105QPCh. 4 - Prob. 4.106QPCh. 4 - 4.107 A number of metals are involved in redox...Ch. 4 - Prob. 4.108QPCh. 4 - Prob. 4.109QPCh. 4 - Prob. 4.110QPCh. 4 - Prob. 4.111QPCh. 4 - Prob. 4.112QPCh. 4 - Prob. 4.114SPCh. 4 - Prob. 4.115SPCh. 4 - Prob. 4.116SPCh. 4 - Prob. 4.117SPCh. 4 - Prob. 4.118SP
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How to Calculate Oxidation Numbers Introduction; Author: Tyler DeWitt;https://www.youtube.com/watch?v=-a2ckxhfDjQ;License: Standard YouTube License, CC-BY