Chapter 4, Problem 43Q

Interpretation Introduction

Interpretation:

The mass of carbon atom in $73$ million metric tons of $C{H}_4$ has to be calculated.

Concept Introduction:

Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is $\text{kg/mol}$. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in $amu$.

  $\text{Molar}\text{mass}\left(\text{g/mol}\right)=\frac{\text{Given}\text{mass}\text{of}\text{substance}\left(\text{g}\right)}{\text{Moles}\text{of}\text{substance}\left(mol\right)}$

Molar mass of $H_{2}O$ can be determined as follows,

$\text{Molar}\text{mass}\text{of}{\text{H}}_{\text{2}}\text{O}=\underset{MassoftwoHydrogen}{\left(\text{2}\text{×}\text{1}\text{g}\right)}\text{+}\underset{massofoneOxygen}{\left(\text{1×}\text{16}\text{g}\right)}=18g/mol$

Mass ratio of a compound with formula AB can be determined as follows,

$\boxed{\text{Mass}\text{ratio}\text{of}\text{A}=\text{100}\text{.0}\text{g}\text{AB}\text{×}\frac{\text{Mass}\text{of}\text{A}}{\text{Mass}\text{of}\text{AB}}}$