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Chapter 4, Problem 4.37E
Interpretation Introduction

(a)

Interpretation:

The formula weight in atomic mass units for the given binary ionic compound is to be determined.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. A huge amount of heat is required to separate these oppositely charged ions. Therefore, the melting point of ionic solids is high.

Expert Solution
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Answer to Problem 4.37E

The formula weight in atomic mass units for the given binary ionic compound is 61.98u.

Explanation of Solution

The formula weight of binary compounds is the sum of atomic weight of each atom.

The formula weight of Na2O is calculated by the formula,

Formulaweight=(2×atomicweightofNa)+(1×atomicweightofO) …(1)

The atomic weights of Na and O are 22.99u and 16.0u, respectively.

Substitute the atomic weight of Na and O in equation (1).

Formulaweight=(2×22.99u)+(1×16.0u)=(45.98+16.0)u=61.98u

Conclusion

The formula weight in atomic mass units for the given binary ionic compound is 61.98u.

Interpretation Introduction

(b)

Interpretation:

The formula weight in atomic mass units for the given binary ionic compound is to be determined.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. A huge amount of heat is required to separate these oppositely charged ions. Therefore, the melting point of ionic solids is high.

Expert Solution
Check Mark

Answer to Problem 4.37E

The formula weight in atomic mass units for the given binary ionic compound is 71.85u.

Explanation of Solution

The formula weight of binary compounds is the sum of atomic weight of each atom.

The formula weight of FeO is calculated by the formula,

Formulaweight=(1×atomicweightofFe)+(1×atomicweightofO) …(2)

The atomic weights of Fe and O are 55.85u and 16.00u, respectively.

Substitute the atomic weight of Fe and O in equation (2).

Formulaweight=(1×55.85u)+(1×16.00u)=71.85u

Conclusion

The formula weight in atomic mass units for the given binary ionic compound is 71.85u.

Interpretation Introduction

(c)

Interpretation:

The formula weight in atomic mass units for the given binary ionic compound is to be determined.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. A huge amount of heat is required to separate these oppositely charged ions. Therefore, the melting point of ionic solids is high.

Expert Solution
Check Mark

Answer to Problem 4.37E

The formula weight in atomic mass units for the given binary ionic compound is 271.32u.

Explanation of Solution

The formula weight of binary compounds is the sum of atomic weight of each atom.

The formula weight of PbS2 is calculated by the formula,

Formulaweight=(1×atomicweightofPb)+(2×atomicweightofS) …(3)

The atomic weights of Pb and S are 207.2u and 32.06u, respectively.

Substitute the atomic weight of Pb and S in equation (3).

Formulaweight=(1×207.2u)+(2×32.06u)=207.2u+64.12u=271.32u

Conclusion

The formula weight in atomic mass units for the given binary ionic compound is 271.32u.

Interpretation Introduction

(d)

Interpretation:

The formula weight in atomic mass units for the given binary ionic compound is to be determined.

Concept introduction:

Ionic compounds are those compounds that have the strong electrostatic force of attraction between the oppositely charged ions. A huge amount of heat is required to separate these oppositely charged ions. Therefore, the melting point of ionic solids is high.

Expert Solution
Check Mark

Answer to Problem 4.37E

The formula weight in atomic mass units for the given binary ionic compound is 133.28u.

Explanation of Solution

The formula weight of binary compounds is the sum of atomic weight of each atom.

The formula weight of AlCl3 is calculated by the formula,

Formulaweight=(1×atomicweightofAl)+(3×atomicweightofCl) …(4)

The atomic weights of Al and Cl are 26.93u and 35.45u, respectively.

Substitute the atomic weight of Al and Cl in equation (4).

Formulaweight=(1×26.93u)+(3×35.45u)=26.93u+106.35u=133.28u

Conclusion

The formula weight in atomic mass units for the given binary ionic compound is 133.28u.

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Chapter 4 Solutions

Bundle: Chemistry for Today: General, Organic, and Biochemistry, Loose-Leaf Version, 9th + LMS Integrated OWLv2, 4 terms (24 months) Printed Access Card

Ch. 4 - Use the periodic table and predict the number of...Ch. 4 - Prob. 4.12ECh. 4 - Write a symbol for each of the following ions: a.A...Ch. 4 - Write a symbol for each of the following ions: a.A...Ch. 4 - Prob. 4.15ECh. 4 - Identify the element in period 3 that would form...Ch. 4 - Identify the noble gas that is isoelectronic with...Ch. 4 - Identify the noble gas that is isoelectronic with...Ch. 4 - Write equations to represent positive and negative...Ch. 4 - Prob. 4.20ECh. 4 - Write the formula for the ionic compound formed...Ch. 4 - Prob. 4.22ECh. 4 - Classify each of the following as a binary...Ch. 4 - Prob. 4.24ECh. 4 - Prob. 4.25ECh. 4 - Prob. 4.26ECh. 4 - Prob. 4.27ECh. 4 - Prob. 4.28ECh. 4 - Prob. 4.29ECh. 4 - Name the following binary ionic compounds: a. SrS...Ch. 4 - Name the following binary ionic compounds, using a...Ch. 4 - Name the following binary ionic compounds, using a...Ch. 4 - Prob. 4.33ECh. 4 - Prob. 4.34ECh. 4 - Prob. 4.35ECh. 4 - Write formulas for the following binary ionic...Ch. 4 - Prob. 4.37ECh. 4 - Prob. 4.38ECh. 4 - Identify the ions that would occupy lattice sites...Ch. 4 - Identify the ions that would occupy lattice sites...Ch. 4 - Calculate the mass in grams of positive ions and...Ch. 4 - Calculate the mass in grams of positive ions and...Ch. 4 - Prob. 4.43ECh. 4 - Prob. 4.44ECh. 4 - Represent the following reaction using Lewis...Ch. 4 - Prob. 4.46ECh. 4 - Prob. 4.47ECh. 4 - Represent the following molecules by Lewis...Ch. 4 - Draw Lewis structures for the following polyatomic...Ch. 4 - Prob. 4.50ECh. 4 - Prob. 4.51ECh. 4 - Prob. 4.52ECh. 4 - Predict the shape of each of the following...Ch. 4 - Prob. 4.54ECh. 4 - Prob. 4.55ECh. 4 - Prob. 4.56ECh. 4 - Use the periodic table and Table 4.4 to determine...Ch. 4 - Use Table 4.4 and classify the bonds in the...Ch. 4 - Use Table 4.4 and classify the bonds in the...Ch. 4 - Prob. 4.60ECh. 4 - On the basis of the charge distributions you drew...Ch. 4 - Prob. 4.62ECh. 4 - Prob. 4.63ECh. 4 - Prob. 4.64ECh. 4 - Show the charge distribution in the following...Ch. 4 - Prob. 4.66ECh. 4 - Prob. 4.67ECh. 4 - Prob. 4.68ECh. 4 - Prob. 4.69ECh. 4 - Prob. 4.70ECh. 4 - Prob. 4.71ECh. 4 - Prob. 4.72ECh. 4 - Prob. 4.73ECh. 4 - Prob. 4.74ECh. 4 - Prob. 4.75ECh. 4 - The covalent compounds ethyl alcohol and dimethyl...Ch. 4 - Prob. 4.77ECh. 4 - Prob. 4.78ECh. 4 - Prob. 4.79ECh. 4 - Prob. 4.80ECh. 4 - Prob. 4.81ECh. 4 - Prob. 4.82ECh. 4 - Suppose an element from group II(A)(2) and period...Ch. 4 - What would be the mass in grams of 0.200moles of...Ch. 4 - The ampere unit is used to describe the flow of...Ch. 4 - Prob. 4.86ECh. 4 - Prob. 4.87ECh. 4 - Prob. 4.88ECh. 4 - Prob. 4.89ECh. 4 - Prob. 4.90ECh. 4 - Prob. 4.91ECh. 4 - Prob. 4.92ECh. 4 - Prob. 4.93ECh. 4 - Prob. 4.94ECh. 4 - Prob. 4.95ECh. 4 - Noble gases: a.have low boiling points. b.are all...Ch. 4 - Prob. 4.97ECh. 4 - Name the type of bond that is formed when...Ch. 4 - Prob. 4.99ECh. 4 - A atom becomes an ion that possesses a negative...Ch. 4 - When calcium reacts with chlorine to form calcium...Ch. 4 - Prob. 4.102ECh. 4 - Prob. 4.103ECh. 4 - Which molecule below has a nonpolar bond in which...Ch. 4 - What is the correct formula for bismuth (III)...Ch. 4 - Which of the following species will combine with a...Ch. 4 - What type of bond is created when bromine and...Ch. 4 - The parts of an atom directly involved in ionic...Ch. 4 - In forming an ionic bond with an atom of chlorine,...Ch. 4 - In bonding, what would happen between the...Ch. 4 - Which compound contains a bond with no ionic...Ch. 4 - Prob. 4.112ECh. 4 - Which molecule is nonpolar and contains a nonpolar...Ch. 4 - Which of the following is a nonpolar covalent...Ch. 4 - Prob. 4.115ECh. 4 - Prob. 4.116E
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