Solid Waste Engineering
3rd Edition
ISBN: 9781305635203
Author: Worrell, William A.
Publisher: Cengage Learning,
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Chapter 4, Problem 4.16P
To determine
Size of motor used for this shredder
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- 1. In the bulk unit weight experiment why should the aggregate be placed in layers and then rodded instead of filling up the container and then rodding it.arrow_forwardThe following are the results in the test for specific gravity of fine aggregates:Mass of Oven-dried specimen in air = 502gMass of Pycnometer filled with water, to calibration mark = 640gMass of Saturated Surface Dry Specimen = 510gMass of Pycnometer filled with specimen and water to calibration mark = 950gCalculate the absorption, apparent specific gravity, bulk specific gravity in SSD condition, and bulk specific gravity in OD conditionarrow_forwardDetermine the effective particle size. Find the uniformity coefficient. Compute the coefficient of gradation. Solve the sorting coefficient. Calculate the suitability number.arrow_forward
- Sand particles does have liquid limit ? Justify your answerarrow_forwardReview ASTM D75 and summarize the following:a. Sampling aggregates from conveyer belts.b. Sampling aggregates from stockpiles.c. Sampling aggregates from roadway bases and subbases.d. If the nominal maximum aggregate size is 3/4 in., what is the minimum sample size that needs to be obtained?arrow_forwardIf needed assume the unit weight of water to be 62.4 lb/ft3 a) A HMAC sample has the following volumetric properties (i) VMA = 0.1865 ft3and (ii)Volume of air = 0.0452 ft3 Compute %VFA. b) A HMAC sample has 140 lbs of aggregate with a bulk specific gravity of 2.65 and aneffective specific gravity of 2.71. Based on this information the volume of the absorbedasphalt is ________________ft3A compacted sample of hot mix asphalt concrete sample has a unit weight of 135 lb/ft3.c) The sample has an asphalt content of 5% (by weight). Assume no absorbed asphalt.The bulk specific gravity of the aggregate is 2.65, and specific gravity for the asphaltcement is 1.05. Based on this information compute VMA for this mixture.arrow_forward
- A sample of a dry course-grained material of 500 grams was shaken through a nest of sieves and the following results are obtained: Sieve No. Opening (mm) 4.75 Mas Retained (grams) 0.0 14.8 4 10 2.00 20 0.85 98.0 40 0.425 90.1 100 0.15 181.9 200 0.075 108.8 Pan 6.4 1. Determine the effective size (mm). 2. Determine the uniformity coefficient. 3. Determine the coefficient of curvature.arrow_forwardA steel block of size 300 mm X 150 mm X 100 mm subjected to load of 300 kN (tension) on 150 mm X 100 mm face, 500 kN (compression) on 300 mm X 150 mm face and 100 kN (tension) on 300 mm X 100 mm face. Determine change in volume if poisons ratio is 0.25, E = 2 X 10^5 MPaarrow_forwardCalculate the sieve analysis shown in Table P5.19 and plot on a semilog gradation paper. What is the maximum size? What is the nominal maximum size?arrow_forward
- 1. Why do you think there is a need to agitate the aggregates inside the cylinder mold by rodding? 2. Determine the unit weight of the aggregates from the video. a. Dry Loose Unit Weight of the Fine Aggregate b. Dry Rodded Unit Weight of the Fine Aggregate c. Dry Loose Unit Weight of the Coarse Aggregate d. Dry Rodded Unit Weight of the Coarse Aggregate 3. A coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0094m³ %3D b. Weight of empty bucket = 8,391 g c. Weight of bucket filled with dry rodded coarse aggregate = 25,355 g %3D Calculate the dry-rodded unit weight. 4. Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0142m³ %3D b. Weight of empty bucket = 9,207 g c. Weight of bucket filled with dry rodded coarse aggregate: i. Trial 1= 34,745 g ii. Trial 2 = 34,065 g…arrow_forward4. MECHANICAL SEPARATION A sieve analysis gives the following results: Sieve size (mm) Wt. retained (g) 1.000 0 0.500 64 0.250 0.125 0.063 324 240 48 24 Through 0.063 Plot a cumulative size analysis and a size-distribution analysis, and estimate the weights, per 1000 kg of powder, which would lie in the size ranges 0.150 to 0.200 mm and 0.250 to 0.350 mm.arrow_forward5. Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $750,000, an operating cost of $60,000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,350,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a future worth analysis at an interest rate of 12% per year?arrow_forward
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ISBN:9781305635203
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