Chemistry (Instructor's)
10th Edition
ISBN: 9781305957787
Author: ZUMDAHL
Publisher: CENGAGE L
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Chapter 4, Problem 24Q
A student had 1.00 L of a 1.00-M acid solution. Much to the surprise of the student, it took 2.00 L of 1.00 M NaOH solution to react completely with the acid. Explain why it took twice as much NaOH to react with all of the acid.
In a different experiment, a student had 10.0 mL of 0.020 M HCI. Again, much to the surprise of the student, it took only 5.00 mL of 0.020 M strong base to react completely with the HCl. Explain why it took only half as much strong base to react with all of the HCl.
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Chapter 4 Solutions
Chemistry (Instructor's)
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Ch. 4 - You have a solution of table salt in water. What...Ch. 4 - You have a sugar solution (solution A) with...Ch. 4 - You add an aqueous solution of lead nitrate to an...Ch. 4 - Order the following molecules from lowest to...Ch. 4 - Why is it that when something gains electrons, it...Ch. 4 - Consider separate aqueous solutions of HCl and...Ch. 4 - Prob. 8ALQCh. 4 - On the basis of the general solubility rules given...Ch. 4 - Prob. 11ALQCh. 4 - The exposed electrodes of a light bulb are placed...Ch. 4 - The equation Ag(aq) + Cu(s) Cu2(aq) + Ag(s) has...Ch. 4 - In balancing oxidation-reduction reactions, why is...Ch. 4 - Differentiate between what happens when the...Ch. 4 - A typical solution used in general chemistry...Ch. 4 - Prob. 19QCh. 4 - A student wants to prepare 1.00 L of a 1.00-M...Ch. 4 - List the formulas of three soluble bromide salts...Ch. 4 - When 1.0 mole of solid lead nitrate is added to...Ch. 4 - What is an acid and what is a base? 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Solution...
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