Engineering Economy (17th Edition)
17th Edition
ISBN: 9780134870069
Author: William G. Sullivan, Elin M. Wicks, C. Patrick Koelling
Publisher: PEARSON
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Question
Chapter 4, Problem 143FE
To determine
Calculate the annual value.
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Suppose that under the Plan of Repayment one should pay off the debt in a number of equal end-of-month installments (principal and interest). This is the customary way to pay off loans
on automobiles, house mortgages, etc. A friend of yours has financed $15,000 on the purchase of a new automobile, and the annual interest rate is 6% (0.5% per month).
a. Monthly payments over a 36-month loan period will be how much?
b. How much interest and principal will be paid within three month of this loan?
Suppose a certain manufacturer deposits $3, 000 at the beginning of each 3 month period for 8 years in an account paying 8% interest compounded quarterly. (Round your answers to the nearest cent.) (a) How much (in $) will be in the account at the end of the 8 year period? $ Incorrect: Your answer is incorrect. (b) What is the total amount (in $) of interest earned in this account? $ Incorrect: Your answer is incorrect
Use interest tables. Suppose that $1,000 is invested for 4 years at an interest rate of 12%, compounded quarterly. How much will be in the account at the end of 4 years?
Choose an answer by clicking on one of the letters below, or click on "Review topic" if needed.
A F = $1,000 (F/P,12%,4) = $1,000 (1.574) = $1,574
B F = $1,000 (F/P,12%,16) = $1,000 (6.130) = $6,130
C F = $1,000 (F/P,3%,4) = $1,000 (1.126) = $1,126
D F = $1,000 (F/P,3%,16) = $1,000 (1.605) = $1,605
Chapter 4 Solutions
Engineering Economy (17th Edition)
Ch. 4 - Compare the interest earned by 9,000 for five...Ch. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10P
Ch. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Automobiles of the future will most likely be...Ch. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - A geothermal heat pump can save up to 80% of the...Ch. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - DuPont claims that its synthetic composites will...Ch. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 58PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61PCh. 4 - Prob. 62PCh. 4 - Prob. 63PCh. 4 - Prob. 64PCh. 4 - Prob. 65PCh. 4 - Prob. 66PCh. 4 - Prob. 67PCh. 4 - Prob. 68PCh. 4 - Prob. 69PCh. 4 - Prob. 70PCh. 4 - Prob. 71PCh. 4 - Prob. 72PCh. 4 - Prob. 73PCh. 4 - Prob. 74PCh. 4 - Prob. 75PCh. 4 - Prob. 76PCh. 4 - Prob. 77PCh. 4 - Prob. 78PCh. 4 - Prob. 79PCh. 4 - Prob. 80PCh. 4 - Prob. 81PCh. 4 - Prob. 82PCh. 4 - Prob. 83PCh. 4 - Prob. 84PCh. 4 - Prob. 85PCh. 4 - Prob. 86PCh. 4 - Prob. 87PCh. 4 - Prob. 88PCh. 4 - Prob. 89PCh. 4 - Prob. 90PCh. 4 - Prob. 91PCh. 4 - Prob. 92PCh. 4 - Prob. 93PCh. 4 - Prob. 94PCh. 4 - Prob. 95PCh. 4 - Prob. 96PCh. 4 - Prob. 97PCh. 4 - Prob. 98PCh. 4 - Prob. 99PCh. 4 - Prob. 100PCh. 4 - Prob. 101PCh. 4 - Prob. 102PCh. 4 - Prob. 103PCh. 4 - Prob. 104PCh. 4 - Prob. 105PCh. 4 - Prob. 106PCh. 4 - Prob. 107PCh. 4 - Prob. 108PCh. 4 - Prob. 109PCh. 4 - Prob. 110PCh. 4 - Prob. 111PCh. 4 - Prob. 112PCh. 4 - Prob. 113PCh. 4 - Prob. 114PCh. 4 - Prob. 115PCh. 4 - Prob. 116PCh. 4 - Prob. 117PCh. 4 - Prob. 118PCh. 4 - Prob. 119PCh. 4 - Prob. 120PCh. 4 - Prob. 121PCh. 4 - Prob. 122PCh. 4 - Prob. 123PCh. 4 - Prob. 124PCh. 4 - Prob. 125PCh. 4 - Prob. 126PCh. 4 - Analyze the truth of this statement, assuming you...Ch. 4 - Prob. 128PCh. 4 - Prob. 129SECh. 4 - Prob. 130SECh. 4 - Prob. 131SECh. 4 - Prob. 132SECh. 4 - Prob. 133CSCh. 4 - Prob. 134CSCh. 4 - Prob. 135CSCh. 4 - Prob. 136FECh. 4 - Prob. 137FECh. 4 - Prob. 138FECh. 4 - Prob. 139FECh. 4 - Prob. 140FECh. 4 - Prob. 141FECh. 4 - Prob. 142FECh. 4 - Prob. 143FECh. 4 - Prob. 144FECh. 4 - Prob. 145FECh. 4 - Prob. 146FECh. 4 - Prob. 147FECh. 4 - Prob. 148FECh. 4 - Prob. 149FECh. 4 - Prob. 150FECh. 4 - Prob. 151FECh. 4 - Prob. 152FECh. 4 - Prob. 153FE
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- 4.39. What is the present worth of the following series of payments? (a) $5,000 at the end of each six-month period for 12 years at 9% compounded semiannually. $7,000 at the end of each quarter for 10 years at 8% compounded quarterly. (b) (c) $3,500 at the end of each month for five years at 6% compounded monthly.arrow_forwardQUESTION 1 Muhammad takes out a loan of $ 2,130, at 8% simple interest, for 8 years. How much will he pay back at the end of year 8? QUESTION 2 Calculate the amount of interest on an investment of AED 103,971 at 8% simple interest for 5 years. QUESTION 3 If you deposit today $7,335 in an account for 6 years and at the end accumulate $10,885, how much compound interest rate (rate of return) you earned on this investment ? QUESTION 4 You will deposit 12,025 at 10% simple interest rate for 9 years, and then move the amount you would receive to an investment account at 12 % compound rate for another 3 years. How much money would you have at the end of the entire period ?arrow_forward7. Sarah borrows some money to buy a new car. The car dealership allows her to defer payments for 12 months, and Sarah makes 60 end of month payments thereafter. If the original loan is $15321 and interest is 0.75% per month, how much will Sarah's monthly payment be? • $697 $627 $349 $279 $418arrow_forward
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