Physics for Scientists and Engineers with Modern Physics
4th Edition
ISBN: 9780131495081
Author: Douglas C. Giancoli
Publisher: Addison-Wesley
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Chapter 37.11, Problem 1FE
To determine
The energy of the proton.
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What are the (a) energy, (b) magnitude of the momentum, and (c) wavelength of the photon emitted when a hydrogen atom
undergoes a transition from a state with n = 4 to a state with n = 2?
(a) Number
2.55
Units
eV
(b) Number
1.3617
Units
kg-m/s or N-s
(c) Number
4.865976353
Units
This answer has no units
Use the table to determine the energy in eV of the photon emitted when an electron jumps down from the n = 2 orbit to the n = 1 orbit of a hydrogen atom.
Allowed Values of the Hydrogen Electron's Radius and Energy for Low Values of n
n
rn
En
1
0.053 nm
−13.60 eV
2
0.212 nm
−3.40 eV
3
0.477 nm
−1.51 eV
4
0.848 nm
−0.85 eV
eV
An electron in a hydrogen atom makes a transition from the fifth excited state to n = 2.What are the frequency and wavelength of the emitted photon? (h = 4.136 x 10 -15 eV/Hz = 6.63 x 10 -34 J.s, c = 3.0 x 10 8 m/s, 1eV = 1.6 x 10 -19 J)
Chapter 37 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 37.2 - Prob. 1AECh. 37.2 - Prob. 1BECh. 37.4 - Prob. 1CECh. 37.7 - Prob. 1DECh. 37.7 - Prob. 1EECh. 37.11 - Prob. 1FECh. 37 - Prob. 1QCh. 37 - Prob. 2QCh. 37 - Prob. 3QCh. 37 - Prob. 4Q
Ch. 37 - Prob. 5QCh. 37 - Prob. 6QCh. 37 - Prob. 7QCh. 37 - Prob. 8QCh. 37 - Prob. 9QCh. 37 - Prob. 10QCh. 37 - Prob. 11QCh. 37 - Prob. 12QCh. 37 - Prob. 13QCh. 37 - Prob. 14QCh. 37 - Prob. 15QCh. 37 - Prob. 16QCh. 37 - Prob. 17QCh. 37 - Prob. 18QCh. 37 - Prob. 19QCh. 37 - Prob. 20QCh. 37 - Prob. 21QCh. 37 - Prob. 22QCh. 37 - Prob. 23QCh. 37 - Prob. 24QCh. 37 - Prob. 25QCh. 37 - Prob. 26QCh. 37 - Prob. 27QCh. 37 - Prob. 28QCh. 37 - Prob. 1PCh. 37 - Prob. 2PCh. 37 - Prob. 3PCh. 37 - Prob. 4PCh. 37 - Prob. 5PCh. 37 - Prob. 6PCh. 37 - Prob. 7PCh. 37 - Prob. 8PCh. 37 - Prob. 9PCh. 37 - Prob. 10PCh. 37 - Prob. 11PCh. 37 - Prob. 12PCh. 37 - Prob. 13PCh. 37 - Prob. 14PCh. 37 - Prob. 15PCh. 37 - Prob. 16PCh. 37 - Prob. 17PCh. 37 - Prob. 18PCh. 37 - Prob. 19PCh. 37 - Prob. 20PCh. 37 - Prob. 21PCh. 37 - Prob. 22PCh. 37 - Prob. 23PCh. 37 - Prob. 24PCh. 37 - Prob. 25PCh. 37 - Prob. 26PCh. 37 - Prob. 27PCh. 37 - Prob. 28PCh. 37 - Prob. 29PCh. 37 - Prob. 30PCh. 37 - Prob. 31PCh. 37 - Prob. 32PCh. 37 - Prob. 33PCh. 37 - Prob. 34PCh. 37 - Prob. 35PCh. 37 - Prob. 36PCh. 37 - Prob. 37PCh. 37 - Prob. 38PCh. 37 - Prob. 39PCh. 37 - Prob. 40PCh. 37 - Prob. 41PCh. 37 - Prob. 42PCh. 37 - Prob. 43PCh. 37 - Prob. 44PCh. 37 - Prob. 45PCh. 37 - Prob. 46PCh. 37 - Prob. 47PCh. 37 - Prob. 48PCh. 37 - Prob. 49PCh. 37 - Prob. 50PCh. 37 - Prob. 51PCh. 37 - Prob. 52PCh. 37 - Prob. 53PCh. 37 - Prob. 54PCh. 37 - Prob. 55PCh. 37 - Prob. 56PCh. 37 - Prob. 57PCh. 37 - Prob. 58PCh. 37 - Prob. 59PCh. 37 - Prob. 60PCh. 37 - Prob. 61PCh. 37 - Prob. 62PCh. 37 - Prob. 63PCh. 37 - Prob. 64PCh. 37 - Prob. 65PCh. 37 - Prob. 66PCh. 37 - Prob. 67PCh. 37 - Prob. 68PCh. 37 - Prob. 69PCh. 37 - Prob. 70PCh. 37 - Prob. 71PCh. 37 - Prob. 72GPCh. 37 - Prob. 73GPCh. 37 - Prob. 74GPCh. 37 - Prob. 75GPCh. 37 - Prob. 76GPCh. 37 - Prob. 77GPCh. 37 - Prob. 78GPCh. 37 - Prob. 79GPCh. 37 - Prob. 80GPCh. 37 - Prob. 81GPCh. 37 - Prob. 82GPCh. 37 - Prob. 83GPCh. 37 - Prob. 84GPCh. 37 - Prob. 85GPCh. 37 - Prob. 86GPCh. 37 - Prob. 87GPCh. 37 - Prob. 88GPCh. 37 - Prob. 89GPCh. 37 - Prob. 90GPCh. 37 - Prob. 91GPCh. 37 - Prob. 92GPCh. 37 - Prob. 93GPCh. 37 - Show that the wavelength of a particle of mass m...Ch. 37 - Prob. 95GPCh. 37 - Prob. 96GPCh. 37 - Prob. 97GPCh. 37 - Prob. 98GPCh. 37 - Prob. 99GPCh. 37 - Prob. 100GP
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- A mercury atom emits light at many wavelengths, two of which are at (1) 404.7 nm and (2) 435.8 nm . Both of these transitions are to the same final state. Determine the energy of each emitted wavelength (in J). A E1 = 7.908 x 10-19 J and E2 = 6.558 x10-19 J E1 = 4.628 x 10-19 J and E2 = 4.968 x10-19 J E1 = 5.908 x 10-19 J and E2 = 5.558 x10-19J E1 = 4.908 x 10-19 J and E2 = 4.558 x10-19 Jarrow_forwardIn the Hydrogen atom, an electron gains energy and moves from n=2 of energy -3.39 eV to n=3 of energy -1.51 eV. It is unstable and returns from n=3 to n=2. Calculate the frequency and the wavelength of the emitted photon. E = hf and h = 6.63 x 10-34arrow_forwardn = 1 E = -13.6 ev n= 4 E = -0.85 ev n=5 n= 2 E = -0.54 ev E = -3.4 ev n= 3 E = -1.51 ev a) At what wavelength (in meters) does the n = 3 → 2 transition of hydrogen occur?arrow_forward
- Use the table to determine the energy in eV of the photon emitted when an electron jumps down from the n = 3 orbit to the n = 2 orbit of a hydrogen atom. Allowed Values of the Hydrogen Electron's Radius and Energy for Low Values of n n rn En 1 0.053 nm −13.60 eV 2 0.212 nm −3.40 eV 3 0.477 nm −1.51 eV 4 0.848 nm −0.85 eVarrow_forwardb. An electron and a photon has the same wavelength of 0.21 nm. Calculate the momentum and energy (in eV) of the electron and the photon. (Given c =3.00x108 m s-1, h =6.63 x 1034 J s, me=9.11 x 10-31 kg, mp=1.67 x 1027 kg and e=1.60x1019 C)arrow_forwardA hydrogen atom is initially in the n = 6 state. It drops to the n = 2 state, emitting a photon in the process. (a) What is the energy (in ev) of the emitted photon? 3.022 ev (b) What is the frequency (in Hz) of the emitted photon? 7.293e14 v Hz (c) What is the wavelength (in um) of the emitted photon? 41.14 umarrow_forward
- Use the table to determine the energy in eV of the photon absorbed when an electron jumps up from the n = 1 orbit to the n = 3 orbit of a hydrogen atom. Allowed Values of the Hydrogen Electron's Radius and Energy for Low Values of n n rn En 1 0.053 nm −13.60 eV 2 0.212 nm −3.40 eV 3 0.477 nm −1.51 eV 4 0.848 nm −0.85 eVarrow_forwardA photon is absorbed by a hydrogen atom in the ground state. n=3 n=2 n=1 n=7 n=6 n=s n=4 n n 11=3 n=2 n=1 + E = 0 Es=-0.544 eV E4-0.850 eV E3 = -1.51 eV E2 = -3.40 eV E1-13.6 eV Ground state If the electron is boosted from to the n = 2, what was the energy of the photon? Give your answer in electron volts (eV). evarrow_forwardA hydrogen atom emits a photon that has momentum 6.977 × 10-27 kg·m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-19 C.arrow_forward
- A hydrogen atom emits a photon as it makes a transition from the n = 4 state to the n = 3 state. The energies of these two states are –0.9 eV and –1.5 eV, respectively.(a) What is the energy of the photon?(b) What is its frequency?arrow_forwardA hydrogen atom is in its ground state (n, = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the n, = 3 state. (a) What was the photon's energy (in eV)? 12.089 ev (b) Later, the atom returns to the ground state, emitting one or more photons in the process. Which of the following energies describes photons that might be emitted thus? (Select all that apply.) O 13.6 ev O 1.89 eV V 12.1 eV O 10.2 ev There are two ways a hydrogen atom in the n, = 3 state can end up in the ground state. In the first, all of the energy goes into one photon and the electron moves directly into the ground state. (What would be the energy of that photon?) In the other, the electron "descends" in two stages, each accompanied by the emission of a photon. (What would be the energies of those two photons?)arrow_forwardFigure below shows the energy levels of a hydrogen atom. Which transition produces radiation of wavelength 436 nm? (Given: Electron charge, e-1.602x10 19 C) n=00 O ev -0.54 ev n=5 n=4 -0.85 ev -1.51 eV n= 3 -3.39 ev n=1 -13.58 eV On=3 to n = 2 On=4 to n = 2 On=4to n = 1 On=5 to n- 2 Submit Answerarrow_forward
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