University Physics (14th Edition)
14th Edition
ISBN: 9780133969290
Author: Hugh D. Young, Roger A. Freedman
Publisher: PEARSON
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Textbook Question
Chapter 37, Problem 37.41E
(a) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980c? (b) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.
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Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980c? (a) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.
(a) Through what potential difference does an electron have to be accelerated, starting from rest, to achieve a speed of 0.980c? (b) What is the kinetic energy of the electron at this speed? Express your answer in joules and in electron volts.
Suppose an electron (q = - e = - 1.6 x 10¬19 C,m=9.1 × 10¬3' kg) is accelerated from rest through a potential
difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures.
The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation:
U =
Assuming all potential energy U is converted to kinetic energy K,
K + U = 0
K = -U
mv and using the formula for potential energy above, we arrive at an equation for speed:
2
Since K=
v = (
1/2
Plugging in values, the value of the electron's speed is:
x 107 m/s
V=
Chapter 37 Solutions
University Physics (14th Edition)
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