Holt Mcdougal Larson Algebra 2: Student Edition 2012

1st Edition

ISBN: 9780547647159

Author: HOLT MCDOUGAL

Publisher: HOLT MCDOUGAL

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Expert Solution & Answer

Chapter 3.6, Problem 59PS

Solution

To state: The comparison between the ages of two elephants, one with a shoulder height of 150 centimeters and the other with a shoulder height of 250 centimeters, biologists have discovered that the shoulder height h (in centimeters) of a male African elephant can be modeled by h=62.5t3+75.8.

The elephant with a shoulder height of 250 cm is about 20 years older than the elephant with a shoulder height of 150 cm.

Given information:

The equation is h=62.5t3+75.8 .

Formula used:

Raise each side of the equation to the same power.

Calculation:

Write the original equation:

h=62.5t3+75.8

Substitute the 150 into the equation,

150=62.5t3+75.8

Subtract 75.8 from both sides of the equation,

150−75.8=62.5t3+75.8−75.874.2=62.5t3

Now divide both sides by 62.5,

74.262.5=62.5t362.51.19≈t3

Cube each side of the equation,

1.193≈t33t≈1.67

Therefore, the age of the elephant with a shoulder height of 150 centimeters is 1.67 years.

Now substitute the 250 into the equation,

250=62.5t3+75.8

Subtract 75.8 from both sides of the equation,

250−75.8=62.5t3+75.8−75.8174.2=62.5t3

Now divide both sides by 62.5,

174.262.5=62.5t362.52.79≈t3

Cube each side of the equation,

2.793≈t33t≈21.65

Therefore, the age of the elephant with a shoulder height of 250 centimeters is 21.65 years.

Chapter 3.6, Problem 58PS

Chapter 3.6, Problem 60PS

Chapter 3 Solutions

Holt Mcdougal Larson Algebra 2: Student Edition 2012

Ch. 3.1 - Prob. 1GP Ch. 3.1 - Prob. 2GP Ch. 3.1 - Prob. 3GP Ch. 3.1 - Prob. 4GP Ch. 3.1 - Prob. 5GP Ch. 3.1 - Prob. 6GP Ch. 3.1 - Prob. 7GP Ch. 3.1 - Prob. 8GP Ch. 3.1 - Prob. 9GP Ch. 3.1 - Prob. 10GP

Ch. 3.1 - Prob. 11GP Ch. 3.1 - Prob. 12GP Ch. 3.1 - Prob. 13GP Ch. 3.1 - Prob. 14GP Ch. 3.1 - Prob. 15GP Ch. 3.1 - Prob. 16GP Ch. 3.1 - Prob. 17GP Ch. 3.1 - Prob. 18GP Ch. 3.1 - Prob. 19GP Ch. 3.1 - Prob. 1E Ch. 3.1 - Prob. 2E Ch. 3.1 - Prob. 3E Ch. 3.1 - Prob. 4E Ch. 3.1 - Prob. 5E Ch. 3.1 - Prob. 6E Ch. 3.1 - Prob. 7E Ch. 3.1 - Prob. 8E Ch. 3.1 - Prob. 9E Ch. 3.1 - Prob. 10E Ch. 3.1 - Prob. 11E Ch. 3.1 - Prob. 12E Ch. 3.1 - Prob. 13E Ch. 3.1 - Prob. 14E Ch. 3.1 - Prob. 15E Ch. 3.1 - Prob. 16E Ch. 3.1 - Prob. 17E Ch. 3.1 - Prob. 18E Ch. 3.1 - Prob. 19E Ch. 3.1 - Prob. 20E Ch. 3.1 - Prob. 21E Ch. 3.1 - Prob. 22E Ch. 3.1 - Prob. 23E Ch. 3.1 - Prob. 24E Ch. 3.1 - Prob. 25E Ch. 3.1 - Prob. 26E Ch. 3.1 - Prob. 27E Ch. 3.1 - Prob. 28E Ch. 3.1 - Prob. 29E Ch. 3.1 - Prob. 30E Ch. 3.1 - Prob. 31E Ch. 3.1 - Prob. 32E Ch. 3.1 - Prob. 33E Ch. 3.1 - Prob. 34E Ch. 3.1 - Prob. 35E Ch. 3.1 - Prob. 36E Ch. 3.1 - Prob. 37E Ch. 3.1 - Prob. 38E Ch. 3.1 - Prob. 39E Ch. 3.1 - Prob. 40E Ch. 3.1 - Prob. 41E Ch. 3.1 - 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Prob. 9GP Ch. 3.3 - Prob. 10GP Ch. 3.3 - Prob. 11GP Ch. 3.3 - Prob. 12GP Ch. 3.3 - Prob. 13GP Ch. 3.3 - Prob. 1E Ch. 3.3 - Prob. 2E Ch. 3.3 - Prob. 3E Ch. 3.3 - Prob. 4E Ch. 3.3 - Prob. 5E Ch. 3.3 - Prob. 6E Ch. 3.3 - Prob. 7E Ch. 3.3 - Prob. 8E Ch. 3.3 - Prob. 9E Ch. 3.3 - Prob. 10E Ch. 3.3 - Prob. 11E Ch. 3.3 - Prob. 12E Ch. 3.3 - Prob. 13E Ch. 3.3 - Prob. 14E Ch. 3.3 - Prob. 15E Ch. 3.3 - Prob. 16E Ch. 3.3 - Prob. 17E Ch. 3.3 - Prob. 18E Ch. 3.3 - Prob. 19E Ch. 3.3 - Prob. 20E Ch. 3.3 - Prob. 21E Ch. 3.3 - Prob. 22E Ch. 3.3 - Prob. 23E Ch. 3.3 - Prob. 24E Ch. 3.3 - Prob. 25E Ch. 3.3 - Prob. 26E Ch. 3.3 - Prob. 27E Ch. 3.3 - Prob. 28E Ch. 3.3 - Prob. 29E Ch. 3.3 - Prob. 30E Ch. 3.3 - Prob. 31E Ch. 3.3 - Prob. 32E Ch. 3.3 - Prob. 33E Ch. 3.3 - Prob. 34E Ch. 3.3 - Prob. 35E Ch. 3.3 - Prob. 36E Ch. 3.3 - Prob. 37E Ch. 3.3 - Prob. 38E Ch. 3.3 - Prob. 39E Ch. 3.3 - Prob. 40E Ch. 3.3 - Prob. 41E Ch. 3.3 - Prob. 42E Ch. 3.3 - Prob. 43PS Ch. 3.3 - Prob. 44PS Ch. 3.3 - Prob. 45PS Ch. 3.3 - Prob. 46PS Ch. 3.3 - Prob. 47PS Ch. 3.3 - Prob. 1P Ch. 3.3 - Prob. 2P Ch. 3.3 - Prob. 3P Ch. 3.3 - Prob. 4P Ch. 3.3 - Prob. 1MRPS Ch. 3.3 - Prob. 2MRPS Ch. 3.3 - Prob. 3MRPS Ch. 3.3 - Prob. 4MRPS Ch. 3.3 - Prob. 5MRPS Ch. 3.3 - Prob. 6MRPS Ch. 3.3 - Prob. 7MRPS Ch. 3.3 - Prob. 1DC Ch. 3.3 - Prob. 2DC Ch. 3.3 - Prob. 3DC Ch. 3.4 - Prob. 1GP Ch. 3.4 - Prob. 2GP Ch. 3.4 - Prob. 3GP Ch. 3.4 - Prob. 4GP Ch. 3.4 - Prob. 5GP Ch. 3.4 - Prob. 6GP Ch. 3.4 - Prob. 7GP Ch. 3.4 - Prob. 8GP Ch. 3.4 - Prob. 9GP Ch. 3.4 - Prob. 10GP Ch. 3.4 - Prob. 11GP Ch. 3.4 - Prob. 1E Ch. 3.4 - Prob. 2E Ch. 3.4 - Prob. 3E Ch. 3.4 - Prob. 4E Ch. 3.4 - Prob. 5E Ch. 3.4 - Prob. 6E Ch. 3.4 - Prob. 7E Ch. 3.4 - Prob. 8E Ch. 3.4 - Prob. 9E Ch. 3.4 - Prob. 10E Ch. 3.4 - Prob. 11E Ch. 3.4 - Prob. 12E Ch. 3.4 - Prob. 13E Ch. 3.4 - Prob. 14E Ch. 3.4 - Prob. 15E Ch. 3.4 - Prob. 16E Ch. 3.4 - Prob. 17E Ch. 3.4 - Prob. 18E Ch. 3.4 - Prob. 19E Ch. 3.4 - Prob. 20E Ch. 3.4 - Prob. 21E Ch. 3.4 - Prob. 22E Ch. 3.4 - Prob. 23E Ch. 3.4 - Prob. 24E Ch. 3.4 - 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Prob. 6GP Ch. 3.5 - Prob. 7GP Ch. 3.5 - Prob. 8GP Ch. 3.5 - Prob. 9GP Ch. 3.5 - Prob. 10GP Ch. 3.5 - Prob. 11GP Ch. 3.5 - Prob. 1E Ch. 3.5 - Prob. 2E Ch. 3.5 - Prob. 3E Ch. 3.5 - Prob. 4E Ch. 3.5 - Prob. 5E Ch. 3.5 - Prob. 6E Ch. 3.5 - Prob. 7E Ch. 3.5 - Prob. 8E Ch. 3.5 - Prob. 9E Ch. 3.5 - Prob. 10E Ch. 3.5 - Prob. 11E Ch. 3.5 - Prob. 12E Ch. 3.5 - Prob. 13E Ch. 3.5 - Prob. 14E Ch. 3.5 - Prob. 15E Ch. 3.5 - Prob. 16E Ch. 3.5 - Prob. 17E Ch. 3.5 - Prob. 18E Ch. 3.5 - Prob. 19E Ch. 3.5 - Prob. 20E Ch. 3.5 - Prob. 21E Ch. 3.5 - Prob. 22E Ch. 3.5 - Prob. 23E Ch. 3.5 - Prob. 24E Ch. 3.5 - Prob. 25E Ch. 3.5 - Prob. 26E Ch. 3.5 - Prob. 27E Ch. 3.5 - Prob. 28E Ch. 3.5 - Prob. 29E Ch. 3.5 - Prob. 30E Ch. 3.5 - Prob. 31E Ch. 3.5 - Prob. 32E Ch. 3.5 - Prob. 33E Ch. 3.5 - Prob. 34E Ch. 3.5 - Prob. 35PS Ch. 3.5 - Prob. 36PS Ch. 3.5 - Prob. 37PS Ch. 3.5 - Prob. 38PS Ch. 3.5 - Prob. 39PS Ch. 3.5 - Prob. 40PS Ch. 3.6 - Prob. 1GP Ch. 3.6 - Prob. 2GP Ch. 3.6 - Prob. 3GP Ch. 3.6 - Prob. 4GP Ch. 3.6 - Prob. 5GP Ch. 3.6 - 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Area Between The Curve Problem No 1 - Applications Of Definite Integration - Diploma Maths II; Author: Ekeeda;https://www.youtube.com/watch?v=q3ZU0GnGaxA;License: Standard YouTube License, CC-BY

Solution Summary: The author explains that the shoulder height of a male African elephant can be modeled by h=62.5sqrt[3]t+75.8.

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Chapter 3 Solutions