Chapter 3.6, Problem 34E

To determine

To make: A table with a column for number m months, a column for the amount you have paid after m month.

Answer to Problem 34E

, The total amount is $\$150+\$420=\$570$ that I have paid and , the total amount is $\$150+\$420=\$570$ that my friend have paid

Explanation of Solution

Given information: My one-time membership fee of $\$150$ and monthly fee of $\$35$ and my friend’s one-time membership fee $\$100$ and mothy fee $\$40$ .

Given m be the number of month ,

Now we make a table with a column for the number of months and a clumn for amount I have paid after m month.

m(months) per month fee($) cumulative amount($)

  $\begin{array}{l}1\text{ 35 35}\\ \text{2 35 70}\\ \text{3 35 105}\\ \text{4 35 140}\\ \text{5 35 175}\\ \text{6 35 210}\\ \text{7 35 245}\\ \text{8 35 280}\\ \text{9 35 315}\\ \text{10 35 350}\\ \text{11 35 385}\\ \text{12 35 420}\end{array}$

I have paid $\$150$ for one-time membership .

Hence, the total amount is $\$150+\$420=\$570$ that I have paid.

Now we make a table with a column for the number of months and a column for amount my friend have paid after m month.

m(months) per month fee($) cumulative amount($)

  $\begin{array}{l}1\text{ 40 40}\\ \text{2 40 80}\\ \text{3 40 120}\\ \text{4 40 160}\\ \text{5 40 200}\\ \text{6 40 240}\\ \text{7 40 280}\\ \text{8 40 320}\\ \text{9 40 360}\\ \text{10 40 400}\\ \text{11 40 440}\\ \text{12 40 480}\end{array}$

Hence, the total amount is $\$100+\$480=\$580$ that my friend have paid.

b.

To determine

To make: A scatter plot of the data from part(a).

Explanation of Solution

scatter :

c.

To determine

To use: the scatter plot.

Explanation of Solution

I have total paid $500 in 10^th number month also my friend have paid $500 .

So, in 9^th number month I have paid less then my friend.

d.

To determine

To check: The answer to part (c)

Explanation of Solution

for me total number of amount in 9^th number month I have paid 315 and my friend paid 360 . in 10^th number month we are equal.