BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 36, Problem 2S
How could you detect a plant with a mutation in a gene for an important aquaporin protein?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The following experiment was carreid out at ILC Laboratories to measure the effect of different nutrient solutions on bean root growth. Three nutrient solutions were made:
1.) A solution containing all required nutrients
2.) A solution containing all required nutrients except nitrogen; and
3.) distilled water.
The results recorded for root length and leaf colour were as follows:
Solution 1.) 47 mm; deep green
Solution 2.) 17 mm; pale green-yellow
Solution 3.) 14 mm; pale green-yellow
a.) explain how the solution ranked in relation to the other two;
b.) state the evidence that supports your answer; and
c.) explain why the plant grew the way it did
The figure attached shows an open stoma during a gaseous exchange process in a plant.
A) What is 'y'?
B) Elaborate the gaseous exchange process in plants by considering the influence of 'y' on the turgidity of guard cells.
You place a flaccid plant cell (Ψ = -0.7 MPa) into an environment (beaker) of pure (deionized) water (Ψ = 0 MPa). Compare the initial conditions of the flaccid cell and the environment (beaker of pure water) in terms of:
G) Predict the direction of water movement (into the cell, out of the cell, or no net movement)
H) Predict the change in turgor pressor of the cell (increase turgor pressure or decrease turgor pressure)
I) Predict the fate of the cell (plasmolyzed, turgid, or lysed)
Chapter 36 Solutions
BIOLOGY
Ch. 36.1 - Predict the direction of water movement based on...Ch. 36.1 - Prob. 2LOCh. 36.2 - Prob. 1LOCh. 36.2 - Prob. 2LOCh. 36.3 - Prob. 1LOCh. 36.3 - Prob. 2LOCh. 36.4 - Prob. 1LOCh. 36.4 - Prob. 2LOCh. 36.5 - Prob. 1LOCh. 36.6 - Prob. 1LO
Ch. 36.6 - Prob. 2LOCh. 36 - What would w, s, and p of the cell in figure 36.5a...Ch. 36 - Prob. 2DACh. 36 - Data analysis Comparative analyses of fossil and...Ch. 36 - Prob. 1IQCh. 36 - Which of the following is an active transport...Ch. 36 - The water potential of a plant cell is the a. stun...Ch. 36 - Hydrogen bonding between water molecules results...Ch. 36 - Water movement through cell walls is a....Ch. 36 - Prob. 5UCh. 36 - The formation of an air bubble in the xylem is...Ch. 36 - Prob. 7UCh. 36 - Stomata open when guard cells a. take up...Ch. 36 - Prob. 9UCh. 36 - A plant must expend energy to drive a....Ch. 36 - Which of the following statements is inaccurate?...Ch. 36 - If you could override the control mechanisms that...Ch. 36 - Prob. 3ACh. 36 - If you were able to remove the aquaporins from...Ch. 36 - Prob. 5ACh. 36 - If you fertilize your houseplant too often, you...Ch. 36 - How could you detect a plant with a mutation in a...Ch. 36 - Prob. 3SCh. 36 - Prob. 4SCh. 36 - A carrot is a biennial plant. In the first year of...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A team of researchers investigated the effects of phosphorous availability and light intensity on an angiosperm species. Seeds of the angiosperm were divided into four equal groups. Groups 1 and 2 were exposed to 200 μmol, and Groups 3 and 4 were exposed to 500 μmol. Groups 2 and 4 also received a phosphorous (P) solution. After 20 days, all plants were weighed, and the average dry weight of each group was calculated. The results are in the table below. Group 1(200 μmol, no P) Group 2(200 μmol, + P) Group 3 (500 μmol, no P) Group 4 (500 μmol + P) Average Dry weight (g) 0.8 1.1 1.5 6.2 Describe the effects of light and phosphorous on the growth of the plants in this study. Explain how the metabolic processes associated with the plant kingdom likely influenced these results.arrow_forwardA team of researchers investigated the effects of phosphorous availability and light intensity on an angiosperm species. Seeds of the angiosperm were divided into four equal groups. Groups 1 and 2 were exposed to 200 pmol, and Groups 3 and 4 were exposed to 500 umol. Groups 2 and 4 also received a phosphorous (P) solution. After 20 days, all plants were weighed, and the average dry weight of each group was calculated. The results are in the table below. Group 1(200 pmol, Group 2(200 umol, Group 3 (500 umol, Group 4 (500 pmol no P) no P) +P) Average Dry weight (g) Describe the effects of light and phosphorous on the growth of the plants in this study. Explain how the metabolic processes associated with the plant kingdom likely influenced these results. 10.8 1.5 6.2arrow_forwardDid you find examples of all pigment types in your plant sample? If not, suggest a reason. why the pigment may have been missing. Which of the pigments migrated the farthest? Why did it move further than the other? pigments? Which of the chlorophyll forms is more soluble? How do you know? Why is it important for plants to have more than one pigment?arrow_forward
- If you wanted to study the effects of soil moisture and light intensity on the growth of soybeans and required a high ability to regulate these independent variables, what type of experiment would you choose?arrow_forwardIn this field of sunflowers, variation exists. Some flowers are tall, others short, and finally some plants are an intermediate height. The tallest plants shade the shorter; the taller plants are pollinated first. Over time, we might expect this field of sunflowers to be mostly tall. According to this scenario, we would classify the production of the sunflowers in what area of this Venn diagram? A) A. Reactivate B) B. Reactivate C) C. D) D. Reactivatearrow_forwardImagine an experiment where I am testing the effects of salt on the growth of corn plants. I set up several treatments where some plants get no salt, some are watered with a 0.05% salt solution, and some are watered with a 0.1% salt solution. I use the same species of plants, the same soil, and the same total amounts of water in my experiment. Every other day I record the height of the plants in cm. What is the independent variable in my experiment? What is the dependent variable in my experiment? What is the control treatment in my experiment? What are three controlled variables in my experiment?arrow_forward
- SimpLENI will be competing in a Lugaw Cooking Competition in May. She will be using onions as a special ingredient and garnish in her recipe. She then planted onions in two soil treatments labelled as ANGAT and UNITY. After a week, SimpLENI noticed that her onions in ANGAT increased in number compared to that of onions in UNITY. She then hypothesized that the soil treatments affected the cellular division in the roots of onions contributing to the difference in yield. To prove this, SimpLENI prepared longitudinal sections of onion root tips. Support SimpLENI in her experiment and win the competition by answering the following questions:arrow_forwardAn experiment is conducted to determine the effect of classical music on the growth rate of marigolds (flowers). Two groups of plants are grown from seed in identical soil types, exposed to identical light conditions, and given the same nutrients. Group A is in a quiet atmosphere. The plants in group B provided with the same atmosphere, except that classical music is played for twelve hours daily in this area. The scientist measures the plants in both groups each day and records the data. In experimental design, Group A is known as.* experimental group control group non-experimental group O quasi-experimental grouparrow_forwardWhich of the following explains why pea plants in high soil nitrogen conditions have so few rhizobial nodules on their roots? When there is already high soil nitrogen there is a very large cost to having rhizobial nodules. The rhizobia bacteria in the nodules fix nitrogen when there isn't enough in the soil, so when there is already high soil nitrogen there is no advantage for the pea plant to expend the extra energy housing the rhizobia. The rhizobia bacteria in the nodules use nitrogen when there isn't enough in the soil, so in conditions of high soil nitrogen the plant tries to exclude the rhizobia to keep the nitrogen for itself. When there is already high soil nitrogen there is no benefit to the plant to having rhizobial nodules, which can rob the plant of the high nitrogen supplies so that the rhizobia bacteria do not have to fix the nitrogen themselves.arrow_forward
- How does copper contamination in soil affect plant growth in an endangered plant?You haveOne greenhouse with three tables100 seeds (10 each from 10 plants: assume each seed is viable)unlimited pots, soil, copper, etc.ConsiderHow will you set up your experiment?How many samples (per treatment, per measurement)?What will you measure (leaf area, number of leaves, shoot height, shoot biomass)?arrow_forwardYou are interested in the effect of both soil copper concentration and pH on the growth of plantsand decide to conduct a greenhouse study. You have 60 seedlings (same variety) in individualpots; assume the environment is homogeneous. You decide to test 4 levels of copper and 3 levelsof pH. Considering the classic experimental designs (arrangements), what might be anappropriate setup for your study?arrow_forwardTo test the technique's efficacy, leaf and stem explants were sterilised using a surface sterilisation protocol. Before being treated with 50 percent Clorox for 20 minutes, all explants were properly cleansed with distilled water. After that, the explants were washed with distilled water before being cultivated on Murashige and Skoog (MS) basal medium plates.For each type of explant, a total of five plates were created, each with ten explants. Table shows the findings obtained after a week. Discuss and draw conclusions from the findings.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Anatomy & Physiology (11th Edition)BiologyISBN:9780134580999Author:Elaine N. Marieb, Katja N. HoehnPublisher:PEARSONBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxAnatomy & PhysiologyBiologyISBN:9781259398629Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa StouterPublisher:Mcgraw Hill Education,
- Molecular Biology of the Cell (Sixth Edition)BiologyISBN:9780815344322Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter WalterPublisher:W. W. Norton & CompanyLaboratory Manual For Human Anatomy & PhysiologyBiologyISBN:9781260159363Author:Martin, Terry R., Prentice-craver, CynthiaPublisher:McGraw-Hill Publishing Co.Inquiry Into Life (16th Edition)BiologyISBN:9781260231700Author:Sylvia S. Mader, Michael WindelspechtPublisher:McGraw Hill Education
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
How do Plants Handle Stress?; Author: Alex Dainis;https://www.youtube.com/watch?v=TYsnveEHqec;License: Standard Youtube License