EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
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Chapter 34, Problem 7Q
Monochromatic red light is incident on a double slit and the interference pattern is viewed on a screen some distance away. Explain how the fringe pattern would change if the red light source is replaced by a blue light source.
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Chapter 34 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
Ch. 34 - Prob. 1QCh. 34 - What is the evidence that light is energy?Ch. 34 - Why is light sometimes described as rays and...Ch. 34 - We can hear sounds around corners but we cannot...Ch. 34 - Can the wavelength of light be determined from...Ch. 34 - Two rays of light from the same source...Ch. 34 - Monochromatic red light is incident on a double...Ch. 34 - If Youngs double-slit experiment were submerged in...Ch. 34 - Compare a double-slit experiment for sound waves...Ch. 34 - Suppose white light falls on the two slits of Fig....
Ch. 34 - Why doesnt the light from the two headlights of a...Ch. 34 - Why are interference fringes noticeable only for a...Ch. 34 - Prob. 14QCh. 34 - Some coated lenses appear greenish yellow when...Ch. 34 - A drop of oil on a pond appears bright at its...Ch. 34 - (II) Derive the law of reflectionnamely, that the...Ch. 34 - (II) Suppose a thin piece of glass is placed in...Ch. 34 - (I) If one slit in Fig. 3412 is covered, by what...Ch. 34 - (II) In a two-slit interference experiment, the...Ch. 34 - (II) (a) What is the smallest thickness of a soap...Ch. 34 - (III) The yellow sodium D lines have wavelengths...
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- Suppose Youngs double-slit experiment is performed in air using red light and then the apparatus is immersed in water. What happens to the interference pattern on the screen? (a) It disappears. (b) The bright and dark fringes stay in the same locations, but the contrast is reduced. (c) The bright fringes are closer together. (d) The bright fringes are farther apart. (e) No change happens in the interference pattern.arrow_forwardWhat is the angular width of the central fringe of the interference pattern of (a) 20 slits separated by d=2.0103 mm? (b) 50 slits with the same separation? Assume that =600 nm.arrow_forwardA beam of monochromatic green light is diffracted by a slit of width 0.550 mm. The diffraction pattern forms on a wall 2.06 m beyond the slit. The distance between the positions of zero intensity on both sides of the central bright fringe is 4.10 mm. Calculate the wavelength of the light.arrow_forward
- Consider a single-slit diffraction pattern for =589 nm, projected on a screen that is 1.00 m from a slit of width 0.25 mm. How far from the center of the pattern are the centers of the first and second dark fringes?arrow_forwardIn Figure P27.7 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4?arrow_forwardMonochromatic light is incident on a pair of slits that are separated by 0.200 mm. The screen is 2.50 m away from the slits. a. If the distance between the central bright fringe and either of the adjacent bright fringes is 1.67 cm, find the wavelength of the incident light. b. At what angle does the next set of bright fringes appear?arrow_forward
- A monochromatic light of unknown wavelength is incident on a slit of width 20 m. A diffraction pattern is seen at a screen 2.5 m away where the central maximum is spread over a distance of 10.0 cm. Find the wavelength.arrow_forwardTwo slits 4.0106 m apart are illuminated by light of wavelength 600 nm. What is the highest order fringe in the interference pattern?arrow_forwardWhen a monochromatic light of wavelength 430 nm incident on a double slit of slit separation 5 m, there are 11 interference fringes in its central maximum. How many interference fringes will be in the central maximum of a light of wavelength 632.8 nm for the same double slit?arrow_forward
- Why is it much more difficult to see interference fringes for light reflected from a thick piece of glass than from a thin film? Would it be easier if monochromatic light were used?arrow_forwardAn effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.30 m apart are powered by a single-function generator producing sine waves at 1200-Hz frequency. A student walks along a line 12.5 m away and parallel to the line between the speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is (a) the wavelength of this sound and (b) the distance between the central maximum and the first maximum (loud) position along this line?arrow_forwardShow that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forward
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