Essential University Physics
4th Edition
ISBN: 9780134988566
Author: Wolfson, Richard
Publisher: Pearson Education,
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 34, Problem 77P
To determine
Find the Compton shift.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Problem 4:
A photon originally traveling along the x axis, with wavelength λ = 0.100 nm is incident on an electron (m = 9.109 x 10-31 kg) that is
initially at rest. The x-component of the momentum of the electron after the collision is 5.0 x 10-24 kg m/s and the y-component of
the momentum of the electron after the collision is -6.0 x 10-24 kg m/s. If the photon scatters at an angle + from its original
direction, what is wavelength of the photon after the collision. h= 6.626 x 10:34 J·s and c = 3.0 x 108 m/s.
A parallel beam of 500-keV photons is normally incident on 0.8 cm sheet of lead (density = 11.4 g/cm³) at a
rate of 2x10 photns/sec. µ/p = 0.16 cm²/g, Hen/p = 0.09 cm²/g, H/p = 0.11 cm²/g
What is the fraction of photons transmitted without interaction?
Choose. +
What fraction of the transmitted energy is due to uncollided photons?
Choose...
What fraction of the initial kinetic energy transferred to the electrons is emitted as
Bremsstrahlung?
Choose...
UV radiation having a wavelength of 84 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case, so you can just use the standard formula KE =12mv2.
The correct answer is 1.87E6 m/s how do I get that?
Chapter 34 Solutions
Essential University Physics
Ch. 34.2 - Prob. 34.1GICh. 34.3 - If you replot Fig. 34.7 for a material with a...Ch. 34.3 - Prob. 34.3GICh. 34.4 - Prob. 34.4GICh. 34.5 - Prob. 34.5GICh. 34.6 - Prob. 34.6GICh. 34 - Prob. 1FTDCh. 34 - Prob. 2FTDCh. 34 - Prob. 3FTDCh. 34 - Prob. 4FTD
Ch. 34 - Prob. 5FTDCh. 34 - Prob. 6FTDCh. 34 - Prob. 7FTDCh. 34 - Prob. 8FTDCh. 34 - Prob. 9FTDCh. 34 - Prob. 10FTDCh. 34 - Prob. 11ECh. 34 - The surface temperature of the star Rigel is 104K....Ch. 34 - Prob. 13ECh. 34 - Prob. 14ECh. 34 - Prob. 15ECh. 34 - Prob. 16ECh. 34 - Prob. 17ECh. 34 - Prob. 18ECh. 34 - Prob. 19ECh. 34 - Prob. 20ECh. 34 - Prob. 21ECh. 34 - Prob. 22ECh. 34 - Prob. 23ECh. 34 - Prob. 24ECh. 34 - Prob. 25ECh. 34 - Prob. 26ECh. 34 - Prob. 27ECh. 34 - Prob. 28ECh. 34 - Prob. 29ECh. 34 - Prob. 30ECh. 34 - Prob. 31ECh. 34 - Prob. 32ECh. 34 - Prob. 33ECh. 34 - Prob. 34ECh. 34 - Prob. 35ECh. 34 - Prob. 36ECh. 34 - Prob. 37ECh. 34 - Prob. 38ECh. 34 - Prob. 39ECh. 34 - Prob. 40ECh. 34 - Prob. 41ECh. 34 - Prob. 42PCh. 34 - Prob. 43PCh. 34 - Prob. 44PCh. 34 - Prob. 45PCh. 34 - Prob. 46PCh. 34 - Prob. 47PCh. 34 - Prob. 48PCh. 34 - Prob. 49PCh. 34 - Prob. 50PCh. 34 - Prob. 51PCh. 34 - Prob. 52PCh. 34 - Prob. 53PCh. 34 - Prob. 54PCh. 34 - Prob. 55PCh. 34 - Prob. 56PCh. 34 - Prob. 57PCh. 34 - Prob. 58PCh. 34 - Prob. 59PCh. 34 - Prob. 60PCh. 34 - Prob. 61PCh. 34 - Prob. 62PCh. 34 - Prob. 63PCh. 34 - Prob. 64PCh. 34 - Prob. 65PCh. 34 - Prob. 66PCh. 34 - Prob. 67PCh. 34 - Prob. 68PCh. 34 - Prob. 69PCh. 34 - Prob. 70PCh. 34 - Prob. 71PCh. 34 - Prob. 72PCh. 34 - Prob. 73PCh. 34 - Prob. 74PCh. 34 - Prob. 75PCh. 34 - Prob. 76PCh. 34 - Prob. 77PCh. 34 - Prob. 78PCh. 34 - Prob. 79PCh. 34 - Prob. 80PCh. 34 - Prob. 81PCh. 34 - Prob. 82PPCh. 34 - Prob. 83PPCh. 34 - Prob. 84PPCh. 34 - Prob. 85PP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Through what potential difference ΔVΔV must electrons be accelerated (from rest) so that they will have the same wavelength as an x-ray of wavelength 0.130 nmnm? Use 6.626×10−34 J⋅sJ⋅s for Planck's constant, 9.109×10−31 kgkg for the mass of an electron, and 1.602×10−19 CC for the charge on an electron. Express your answer using three significant figures. =89.0 V Through what potential difference ΔVΔV must electrons be accelerated so they will have the same energy as the x-ray in Part A? Use 6.626×10−34 J⋅sJ⋅s for Planck's constant, 3.00×108 m/sm/s for the speed of light in a vacuum, and 1.602×10−19 CC for the charge on an electron. Express your answer using three significant figures. Second question is what I need help on! Thanks!arrow_forwardAn electron has a de Broglie wavelength λ = 4.5×10−10 m . h=6.626×10−34 J⋅s, e=1.602×10−19 C, me=9.109×10−31 kg. What is its momentum? (p =h/)arrow_forwardThe frequency of yellow light is 5.08 * 10 ^ 14 * H_{Z} . How much energy does a photon of yellow light carry? (h=6.626*10^ -34 J* s;1 eV=; 1.60*10^ -19 j)arrow_forward
- On average, people in Adelaide have a mass of m=85.5kg and walk at a speed of v=2.12ms−1. If we were to consider such a person to be a particle with mass mm and speed vv, then they would have a de Broglie wavelength of λ≈3.66×10−36m when walking. Explain why the average Adelaidean is not observed to diffract when walking through a doorway.arrow_forwardA) Calculate the de Broglie wavelength of a neutron (mn = 1.67493×10-27 kg) moving at one six hundredth of the speed of light (c/600). Enter at least 4 significant figures. (I got the answer 949.4 pm but it is wrong, please help) B) Calculate the velocity of an electron (me = 9.10939×10-31 kg) having a de Broglie wavelength of 230.1 pm.arrow_forwardA butane torch is a tool in which butane is burned to create a flame. A detector, located at 2meters from the flame, only measures the flux of green photons (λ=500[nm]). At a certain moment a detector measures a photon flux of ϕ(500nm)=3.37⋅1025[s−1⋅m−2]. You may assume that the flame behaves like a black body and that the photon emission is isotropic. What is the temperature of the butane flame in?arrow_forward
- UV radiation having a wavelength of 120 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case, so you can just use the standard formula KE =12??2=12mv2.arrow_forwardA photon with wavelength X scatters off an electron at rest, at an angle with the incident direction. The Compton wavelength of the electron Ac = 0.0024 nm. a) For λ = 0.0006 nm and 0 = 53 degrees, find the wavelength X' of the scattered photon in nanometres. b) Obtain a formula for the energy of the electron Ee after collision, in terms of the universal constants h, c and the variables X, X' and Ac. The answer must be expressed in terms of these variables only. (Please enter an algebraic expression using latex format; do not input any numerical values) c) Using the energy conservation condition, find the value of the electron energy Ee after scattering in units of keV. d) Write an algebraic expression for the electron's momentum pe in terms of its energy Ee, its mass me and the speed of light c. e) What is the de Broglie wavelength of the scattered electron ? Express your answer in terms of Ee, me, and X and c. f) Find the value of the de Broglie wavelength of the scattered electron…arrow_forwardCalculate the kinetic energy (in eV) of a nonrelativistic neutron that has a de Broglie wavelength of 7.9×10-12 m (h = 6.626 × 10-34 J ∙ s, mneutron = 1.675 × 10-27 kg, 1 eV = 1.60 × 10-19 J)arrow_forward
- What is the velocity of an electron emitted by lithium (work function = 2.90 e.v.) if light with a frequency of 4.77x1015 s-1 is absorbed?arrow_forwardA butane torch is a tool in which butane is burned to create a flame. A detector, located at 2meters from the flame, only measures the flux of green photons (λ=500[nm]). At a certain moment, the detector measures a photon flux of ϕ(500nm)=3.37⋅1025[s−1⋅m−2]. For simplicity, assume that the flame behaves like a black body and has a spherical shape with a radius of 15cm, while the detector radius is 5cm. What is the temperature of the butane flame in?arrow_forwardwhat is the speed of an electron that has the same momentum as a photon with a wavelength in vacuum of 488 nm? The mass of an electron is 9.11 × 10^–31 kg.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning