Explanation Given information: Speed rate = 45 mi/hr Let the speed of slower car be v 1 and the other car be 2 v 2 . Formula used: Distance = ( x 2 − x 1 ) 2 + ( y 2 − y 1 ) 2 Calculation: According to the question, Since both cars are moving at constant speeds, we can consider that both cars were at the same time in the origin. Then their positions at time t will be s 1 ( t ) = v 1 t s 2 ( t ) = 2 v 2 t In the above figure, the slower car is moving along the x-axis and the faster travels along the line y = 3 x . At time t, the slower car is at P ( v 1 t , 0 ) and the faster car at Q ( v 1 t , 3 v 1 t )

7th Edition

ISBN: 9781524916817

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Concept explainers

Ratios

A ratio is a comparison between two numbers of the same kind. It represents how many times one number contains another. It also represents how small or large one number is compared to the other.

Trigonometric Ratios

Trigonometric ratios give values of trigonometric functions. It always deals with triangles that have one angle measuring 90 degrees. These triangles are right-angled. We take the ratio of sides of these triangles.

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Chapter 3.4, Problem 58PS

To determine

To find: The speed of the slower car.

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Chapter 3.4, Problem 57PS

Chapter 3.4, Problem 59PS

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Chapter 3 Solutions

Calculus

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The speed of the slower car.

Solution Summary: The author calculates that both cars were at the same time in the origin. The distance between the objects at time t is cd=sqrtleft

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To find: The speed of the slower car.

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Chapter 3 Solutions