Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
4th Edition
ISBN: 9780134110684
Author: Randall D. Knight (Professor Emeritus)
Publisher: PEARSON
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Chapter 33, Problem 7CQ
Narrow, bright fringes are observed on a screen behind a diffraction grating. The entire experiment is then immersed in water. Do the fringes on the screen get closer together, get farther apart, remain the same, or disappear? Explain.
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Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Ch. 33 - Prob. 1CQCh. 33 - In a double-slit interference experiment, which of...Ch. 33 - FIGURE Q33.3 shows the viewing screen in a...Ch. 33 - FIGURE Q33.3 is the interference pattern seen on a...Ch. 33 - FIGURE Q33.5 shows the light intensity on a...Ch. 33 - FIGURE Q33.6 shows the light intensity on a...Ch. 33 - Narrow, bright fringes are observed on a screen...Ch. 33 - a. Green light shines through a 100-mm-diameter...Ch. 33 - A Michelson interferometer using 800 nm light is...Ch. 33 - Prob. 10CQ
Ch. 33 - Prob. 1EAPCh. 33 - Prob. 2EAPCh. 33 - Prob. 3EAPCh. 33 - Prob. 4EAPCh. 33 - Light of 630 nm wavelength illuminates two slits...Ch. 33 - Prob. 6EAPCh. 33 - Light from a sodium lamp (=589nm) illuminates two...Ch. 33 - A double-slit interference pattern is created by...Ch. 33 - Prob. 9EAPCh. 33 - Light of wavelength 620 nm illuminates a...Ch. 33 - A diffraction grating produces a first-order...Ch. 33 - Prob. 12EAPCh. 33 - The two most prominent wavelengths in the light...Ch. 33 - Prob. 14EAPCh. 33 - Prob. 15EAPCh. 33 - A helium-neon laser (=633nm) illuminates a single...Ch. 33 - Prob. 17EAPCh. 33 - A 050-mm-wide slit is illuminated by light of...Ch. 33 - 19. You need to use your cell phone, which...Ch. 33 - For what slit-width-to-wavelength ratio does the...Ch. 33 - Light from a helium-neon laser ( = 633 nm) is...Ch. 33 - A laser beam illuminates a single, narrow slit,...Ch. 33 - m-wide slits spaced 0.25 mm apart are illuminated...Ch. 33 - Prob. 24EAPCh. 33 - A 0.50-mm-diameter hole is illuminated by light of...Ch. 33 - Prob. 26EAPCh. 33 - Prob. 27EAPCh. 33 - Your artist friend is designing an exhibit...Ch. 33 - Prob. 29EAPCh. 33 - Prob. 30EAPCh. 33 - Prob. 31EAPCh. 33 - A Michelson interferometer uses light from a...Ch. 33 - FIGURE P33.33 shows the light intensity on a...Ch. 33 - FIGURE P33.34 shows the light intensity en a...Ch. 33 - Prob. 35EAPCh. 33 - Prob. 36EAPCh. 33 - Prob. 37EAPCh. 33 - Prob. 38EAPCh. 33 - Prob. 39EAPCh. 33 - Prob. 40EAPCh. 33 - A triple-slit experiment consists of three narrow...Ch. 33 - Because sound is a wave, it’s possible to make a...Ch. 33 - A diffraction grating with 600 lines/mm is...Ch. 33 - Prob. 44EAPCh. 33 - Prob. 45EAPCh. 33 - A chemist identifies compounds by identifying...Ch. 33 - Prob. 47EAPCh. 33 - For your science fair project you need to design a...Ch. 33 - Prob. 49EAPCh. 33 - Prob. 50EAPCh. 33 - Light from a sodium lamp ( =589 nm) illuminates a...Ch. 33 - The wings of some beetles have closely spaced...Ch. 33 - Prob. 53EAPCh. 33 - Prob. 54EAPCh. 33 - A diffraction grating has slit spacing d. Fringes...Ch. 33 - FIGURE P33.56 shows the light intensity on a...Ch. 33 - FIGURE P33.56 shows the light intensity on a...Ch. 33 - FIGURE P33.56 shows the light intensity on a...Ch. 33 - A student performing a double-slit experiment is...Ch. 33 - Scientists shine a laser beam on a 35- m-wide...Ch. 33 - Light from a helium-neon laser ( =633 nm)...Ch. 33 - Prob. 62EAPCh. 33 - Prob. 63EAPCh. 33 - Prob. 64EAPCh. 33 - Scientists use laser range-finding to measure the...Ch. 33 - Prob. 66EAPCh. 33 - Prob. 67EAPCh. 33 - Prob. 68EAPCh. 33 - Prob. 69EAPCh. 33 - Prob. 70EAPCh. 33 - Prob. 71EAPCh. 33 - Prob. 72EAPCh. 33 - Prob. 73EAPCh. 33 - FIGURE CP33.74 shows light of wavelength ?...Ch. 33 - Prob. 75EAP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- (a) What is the distance between the slits of a diffraction grating that produces a first-order maximum for the first Balmer line at an angle of 20.0°? (b) At what angle will the fourth line of the Balmer series appear in first order? (c) At what angle will the second-order maximum be for the first line?arrow_forwardTwo closely spaced wavelengths of light are incident on a diffraction grating. (a) Starting with Equation 37.7, show that the angular dispersion of the grating is given by dd=mdcos (b) A square grating 2.00 cm on each side containing 8 000 equally spaced slits is used to analyze the spectrum of mercury. Two closely spaced lines emitted by this element have wavelengths of 579.065 nm and 576.959 nm. What is the angular separation of these two wavelengths in the second-order spectrum?arrow_forwardIn Figure P27.7 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4?arrow_forward
- In a Youngs double-slit experiment, a set of parallel slits with a separation of 0.100 mm is illuminated by light having a wave- length of 589 nm, and the interference pattern is observed on a screen 4.00 m from the slits, (a) What is the difference in path lengths from each of the slits to the location of a third-order bright fringe on the screen? (b) What is the difference in path lengths from the two slits to the location of the third dark fringe on the screen, away from the center of the pattern?arrow_forwardA beam of monochromatic green light is diffracted by a slit of width 0.550 mm. The diffraction pattern forms on a wall 2.06 m beyond the slit. The distance between the positions of zero intensity on both sides of the central bright fringe is 4.10 mm. Calculate the wavelength of the light.arrow_forwardShow that the distribution of intensity in a double-slit pattern is given by Equation 36.9. Begin by assuming that the total magnitude of the electric field at point P on the screen in Figure 36.4 is the superposition of two waves, with electric field magnitudes E1=E0sintE2=E0sin(t+) The phase angle in in E2 is due to the extra path length traveled by the lower beam in Figure 36.4. Recall from Equation 33.27 that the intensity of light is proportional to the square of the amplitude of the electric field. In addition, the apparent intensity of the pattern is the time-averaged intensity of the electromagnetic wave. You will need to evaluate the integral of the square of the sine function over one period. Refer to Figure 32.5 for an easy way to perform this evaluation. You will also need the trigonometric identity sinA+sinB=2sin(A+B2)cos(AB2)arrow_forward
- Suppose Youngs double-slit experiment is performed in air using red light and then the apparatus is immersed in water. What happens to the interference pattern on the screen? (a) It disappears. (b) The bright and dark fringes stay in the same locations, but the contrast is reduced. (c) The bright fringes are closer together. (d) The bright fringes are farther apart. (e) No change happens in the interference pattern.arrow_forwardA spacer is cut from a playing card of thickness 2.90 104 m and used to separate one end of two rectangular, optically flat. 3.00-cm long glass plates with n = 1.55, as in Figure P24.24. Laser light at 594 nm shine straight down on the top plate. The plates have a length of 3.00 cm. (a) Count the number of phase reversals for the interfering waves. (b) Calculate the separation between dark interference Kinds observed on the lop plate.arrow_forwardWhy is the following situation impossible? A piece of transparent material having an index of refraction n = 1.50 is cut into the shape of a wedge as shown in Figure P36.40. Both the top and bottom surfaces of the wedge are in contact with air. Monochromatic light of wavelength = 632.8 nm is normally incident from above, and the wedge is viewed from above. Let h = 1.00 mm represent the height of the wedge and = 0.500 m its length. A thin-film interference pattern appears in the wedge due to reflection from the top and bottom surfaces. You have been given the task of counting the number of bright fringes that appear in the entire length of the wedge. You find this task tedious, and your concentration is broken by a noisy distraction after accurately counting 5 000 bright fringes. Figure P36.40arrow_forward
- In Figure P36.10 (not to scale), let L = 1.20 m and d = 0.120 mm and assume the slit system is illuminated with monochromatic 500-nm light. Calculate the phase difference between the two wave fronts arriving at P when (a) = 0.500 and (b) y = 5.00 mm. (c) What is the value of for which the phase difference is 0.333 rad? (d) What is the value of for which the path difference is /4? Figure P36.10arrow_forwardSuppose you perform Youngs double-slit experiment with the slit separation slightly smaller than the wavelength of the light. As a screen, you use a large half-cylinder with its axis along the midline between the slits. What interference pattern will you see on the interior surface of the cylinder? (a) bright and dark fringes so closely spaced as to be indistinguishable (b) one central bright fringe and two dark fringes only (c) a completely bright screen with no dark fringes (d) one central dark fringe and two bright fringes only (e) a completely dark screen with no bright fringesarrow_forwardRed light (wavelength 632.8 nm in air) from a Helium-Neon laser is incident on a single slit of width 0.05 mm. The entire apparatus is immersed in water of refractive index 1.333. Determine the angular width of the central peak.arrow_forward
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Spectra Interference: Crash Course Physics #40; Author: CrashCourse;https://www.youtube.com/watch?v=-ob7foUzXaY;License: Standard YouTube License, CC-BY