Electric Motors and Control Systems
2nd Edition
ISBN: 9780073373812
Author: Frank D. Petruzella
Publisher: McGraw-Hill Education
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Chapter 3.3, Problem 5DT
To determine
The procedure to verify the test using an Ohm-meter.
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Question 2 Calculate the amount of DC current required for the magnetic circuit given below to generate a
flux density of 1.0 T in the airgap. The details are
Number of turns, N = 400
The core is made up of steel, the B-H characteristic has been given below
The magnetic core length, le = 500 mm
The airgap length, Ig = 2 mm
The cross-sectional area of the core, Ag = 100 mm²
Neglect leakage and fringing.
Core
Cross-sectional
i(1)
area
as
Air gap
Magnetic path
length
Figure 1
2.0
1.8
B-H Curves for Various Metals
Steel
1.6
1.4
Magnetic
Saturation
1.2
1.0
0.8
Iron
근 0.4
Air
0.2
1000 2000 3000 4000 5000 6000 7000 8000 9000 10000
Magnetic Field Strength - H (A/m)
Figure 2
Flux Density - B (T)
The arc length voltage characteristic of a DC arc is given by the equation V=24+4L where
'V' is the arc voltage in volts and L' is the length in mm. The static volt-ampere
characteristic of the power source is approximated by a straight line with no load voltage of
80V and the short circuit current of 600A. Then the optimum arc length is
(mm).
Chapter 3 Solutions
Electric Motors and Control Systems
Ch. 3.1 - Prob. 1RQCh. 3.1 - a. If 1 MW of electric power is to be transmitted...Ch. 3.1 - Compare the type of AC power normally supplied to...Ch. 3.1 - a. Outline the basic function of a unit...Ch. 3.1 - list three factors taken into account in selecting...Ch. 3.1 - When motors and motor controllers are installed,...Ch. 3.1 - a. What types of conduit raceways are commonly...Ch. 3.1 - Compare the function of a switchboard, panelboard,...Ch. 3.2 - Define the terms primary and secondary as they...Ch. 3.2 - On what basis is a transformer classified as being...
Ch. 3.2 - Explain how the transfer of energy takes place in...Ch. 3.2 - In an ideal transformer, what is the relationship...Ch. 3.2 - A step-down transformer with a Wins ratio of 10:1...Ch. 3.2 - A step-up transformer has a primary current of 32...Ch. 3.2 - What is meant by the term transformer magnetizing,...Ch. 3.2 - Prob. 8RQCh. 3.2 - Prob. 9RQCh. 3.2 - Prob. 10RQCh. 3.2 - The primary of a transformer is rated for 480 V...Ch. 3.2 - A single-phase transformer is rated for 0.5 kVA, a...Ch. 3.3 - Explain the way in which the high-voltage and...Ch. 3.3 - Prob. 2RQCh. 3.3 - Prob. 3RQCh. 3.3 - Prob. 4RQCh. 3.3 - Prob. 5RQCh. 3.3 - Prob. 6RQCh. 3.3 - Prob. 7RQCh. 3.3 - Prob. 8RQCh. 3.3 - Explain the basic difference between the primary...Ch. 3.3 - Prob. 10RQCh. 3.3 - Prob. 11RQCh. 3.3 - Prob. 12RQCh. 3.3 - What important safety precaution should be...Ch. 3.3 - Prob. 14RQCh. 3.3 - The control transformer for an across-the-line...Ch. 3.3 - The two primary windings of a dual-primary control...Ch. 3.3 - Prob. 3TCh. 3.3 - A dry-type general-purpose power transformer is...Ch. 3.3 - A current transformer is to be tested in circuit...Ch. 3.3 - Discuss how electric power might be distributed...Ch. 3.3 - A block of several transformers arc fed from...Ch. 3.3 - How would you proceed with a DC resistance check...Ch. 3.3 - Prob. 5DT
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- Assume that a primary current of 75 amperes flows through the windings of the transformer in question 4. How much current will flow in the secondary winding?arrow_forwardA current transformer has a ratio of 600:5. If three loops of wire are wound through the transformer core, how much primary current is required to produce 5 amperes of current in the secondary winding?arrow_forwardFind the value of the currents I1 and 12. 100 ohm 5V 5V 100 ohm 12 O a. 1=-0.3A, 12=-0.1A O b. 11=0.3A, 12=0.1A Oc. 11=0.05A, 12=0.1A O d. 11=0.1A, 12=0.2Aarrow_forward
- Details is following Fr=6000N Fa=3000N N=2400rpm Find the total life using data in question.arrow_forward10 cm 1.25 100 0.05 em 30 om 6.75 0.30 625 10 cm 00 1000 Magastaing inoway (A Ts 10 cm 30 cm- A two-legged magnetic core with an air gap is shown in Fig.1. The depth of is 5 cm, the length of the airgap is 0.08 cm, and the number of turns on the coil is 800. The magnetization curve of the core material is shown in Fig.2. The magnetic field density in air gap is 0.7 T. What is the total MMFin A-Turns required to magnetize both the iron core and airgap? Nas deasiy B(Tarrow_forwardThe following data were obtained on a 50 kVA 2400/120 V transformer: Open circuit test, instruments on low voltage side: Waltmeter reading = 396 Watts Ammeter reading = 9.65 amperes Voltmeter reading = 120 Volts Short circuit test, instruments on high voltage side: Waltmeter reading = 810 Watts Ammeter reading = 20.8 amperes Voltmeter reading = 92 Volts Find the efficiency when rated kVA is delivered to a load having a power factor of 0.8 lagging.The following data were obtained on a 50 kVA 2400/120 V transformer : Open circuit test, instruments on low voltage side: Waltmeter reading = 396 Watts Ammeter reading = 9.65 amperes Voltmeter reading = 120 Volts Short circuit test, instruments on high voltage side: Waltmeter reading = 810 Watts Ammeter reading = 20.8 amperes Voltmeter reading = 92 Volts Find the efficiency when rated kVA is delivered to a load having a power factor of 0.8 lagging.arrow_forward
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