EBK PHYSICS FOR SCIENTISTS & ENGINEERS
5th Edition
ISBN: 9780134296074
Author: GIANCOLI
Publisher: VST
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 33, Problem 52P
(II) The closely packed cones in the fovea of the eve have a diameter of about 2 µm. For the eye to discern two images on the fovea as distinct, assume that the images must be separated by at least one cone that is not excited. If these images are of two point-like objects at the eye’s 25-un neat point, how far apart are these barely resolvable objects? Assume the diameter of the eye (cornea-to-fovea distance) is 2.0 cm.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
What is the smallest thing we can see? O smallest object that we can process with our eyes is limited to the size of the photoreceptor cells in the retina. In order for us to to distinguish any detail in an object, its image cannot be smaller cannot be smaller than a single retinal cell. Although the size depends on the type of cell (cone or rod), a diameter of of a few microns (mm) is common near the center of the eye. We should model the eye as a sphere 2.50 cm in diameter with a single slender lens in front and the retina behind, with photoreceptor cells 5.0 mm in diameter. (a) What is the smallest object object that you can perceive at a point near 25 cm? What angle is subtended by this object in the eye? Express your answer in units of minutes (1° 60 min) and compare it with the typical experimental value of about 1.0 min. (Note: there are other limitations, but we will ignore them here).
For a thin spherical lens, the focal length of red light compared to the focal
length of blue light is:
O greater
the same
O less
In X-ray imaging, to achieve a well-defined small area of X-ray beam, the anode of the X-ray tube is usually bevelled. By assuming that the bevel angle is 15° and the distance between the X-ray source and the patient is 30 cm,
(i) Determine the width of actual focal spot needed to achieve the effective focal spot of 1 mm.
(ii) Calculate the coverage of the X-ray beam
Chapter 33 Solutions
EBK PHYSICS FOR SCIENTISTS & ENGINEERS
Ch. 33 - Where must the film be placed if a camera lens is...Ch. 33 - A photographer moves closer to his subject and...Ch. 33 - Use ray diagrams to show that a real image formed...Ch. 33 - Light rays are said to be reversible. Is this...Ch. 33 - A cat with its tail in the air stands facing a...Ch. 33 - An underwater lens consists of a carefully shaped...Ch. 33 - (III) A bright object is placed on one side of a...Ch. 33 - (II) A diverging lens with a focal length of 14 cm...Ch. 33 - (II) Suppose that a correct exposure is 1250S at f...Ch. 33 - (I) A human eyeball is about 2.0 cm long and the...
Ch. 33 - (II) Reading glasses of what power are needed for...Ch. 33 - (II) The closely packed cones in the fovea of the...Ch. 33 - (II) Sherlock Holmes is using an...Ch. 33 - (II) A converging lens of focal length = 12 cm is...Ch. 33 - (III) Given two 12-cm-focal-length lenses, you...Ch. 33 - A small object is 25.0 cm from a diverging lens as...Ch. 33 - Two converging lenses are placed 30.0 cm apart....
Additional Science Textbook Solutions
Find more solutions based on key concepts
17. A tiny plane mirror can produce an image similar to a pinhole camera. Explain how.
College Physics
Write each number in decimal form.
43. 5.5 × 10–11
Applied Physics (11th Edition)
62. Can an electron at rest in a magnetic field be set into motion by the magnetic field? What if the electron ...
Conceptual Physical Science (6th Edition)
Using the definitions in Eqs. 1.1 and 1.4, and appropriate diagrams, show that the dot product and cross produc...
Introduction to Electrodynamics
41. A 0.300 kg oscillator has a speed of 95.4cm/s when its displacement is 3.00cm and 71.4 cm/s when its displ...
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
72. A Thomson's gazelle can run at very high speeds, but its acceleration is relatively modest. A reasonable mo...
College Physics: A Strategic Approach (4th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Suppose a certain person’s visual acuity is such that he can see objects clearly that form an image 4.00mhigh on his retina. What is the maximum distance at which he can read the 75.0-cm-high letters on the side of an airplane?arrow_forwardThe headlights of a car are 1.3 m apart. What is the maximum distance at which the eye can resolve these two headlights? Take the pupil diameter to be 0.40 cm.arrow_forwardSuppose a man stands in front of a mm-or as show below. His eyes are 1.65 m above the floor and the top of his head is 0.13 m higher. Find the height above the floor of the top and bottom of the smallest minor in which he can see both the top of his head and his feet. How is this distance related to the man’s height?arrow_forward
- If the light source in the preceding problem is changed, the angular position of the third maximum is found to be 0.57°. What is the wavelength of light being used now?arrow_forwardIn Section 9.6, we described how the speed of light varies with wavelength (or frequency) for transparent solids. But the speed of light in matter is also a function of temperature and pressure. This dependence is most marked for gases and is instrumental in producing such things as mirages and atmospheric refraction, the latter phenomenon being the displacement of an astronomical object (like the Sun or another star) from its true position because of the passage of its light through the atmosphere. Because Earth’s atmosphere is a gaseous mixture and easily compressed, its density is highest near Earth’s surface and gradually declines with altitude. (Refer to the discussion in Section 4.4 and Figure 4.29.) Thus, the speed of light in the atmosphere is lowest near the surface and gradually gets higher, approaching c as one goes farther and farther into space. Using this fact and the law of refraction, sketch the path a light ray from the Sun would follow upon entering Earth’s atmosphere, and predict the apparent position of the Sun relative to its true position (Figure 9.85). What does this tell you about the actual location of the Sun’s disk relative to your local horizon when you see it apparently setting brilliantly in the west in the evening?arrow_forwardCheck Your Understanding in Example 1.6, we had n1n2. If n2were decreased such thatn1n2and the speed of light in medium 2 is faster than in medium 1, what would happen to the length of AA’ ? What would happen to the wave front A’B and the direction of the refracted ray?arrow_forward
- (i) klhich of the following results when a moves from wave a medium of low refractive index to a medium of higher refractive index. klave 7. Speed decrease Klave length increase bends towards normal - bends away from normal - total internal refraction. - total internal reflection rays experience are - Answer can be more than 1. refracted by exactly 90°arrow_forward(5) For water, n = 1.333. A fish is 80 cm below the surface of a pond. How far below the surface of the water does the fish appear to be (in cm), to an observer outside the water and almost directly above the fish?arrow_forwardThe normal human eye has maximum visual acuity with a pupil size of about 3 mm. For larger pupils, acuity decreases due to increasing aberrations; for smaller pupils, acuity decreases due to increasing effects of diffraction. Ifyour pupil diameter is 2.0 mm, as it would be in fairly bright light, what is the smallest diameter circle that you can barely see as a circle, rather than just a dot, if the circle is at your near point, 25 cm from your eye? Assume the light’s wavelength in air is 600 nm and the index of refraction inside theeye is 1.33.arrow_forward
- If a diverging lens has a focal length of 10 cm, at which object distance will an image smaller than object be formed on the screen? O 5 cm 10 cm None. The lens will not form such an image. All object distances are valid.arrow_forward(i) Derive the expression for a critical incident angle and a mumerical aperture for a given step indexed fiber. (ii) Calculate the critical propagation angle and critical incident angle of an optical fiber of core refractive index, n = 1.52 and cladding refractive index n2 1.50. Given that the fiber is kept in %3D water.arrow_forward(iv) For diagram #iii, suppose the focal length is 5 cm and the object is placed 7 cm from the lens. Find the exact location and magnification of the image. Does this agree with your expectation from the ray diagram?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
Convex and Concave Lenses; Author: Manocha Academy;https://www.youtube.com/watch?v=CJ6aB5ULqa0;License: Standard YouTube License, CC-BY