In Problems 11 and 12 evaluate the determminants.
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- 2. Find the general solution to d²y dr? dy +4 + 3y = e* drarrow_forward2. x + y – z = 2 2x + 2y - 2z = 6 5x + y – 3z = 8arrow_forward9. What is the solution of (x? +2xy – 4y² )dx - (x? – 8xy – 4y? )dy =0 ? a. x? - 4y? = c(x-y) b. x? +2y? = c(x+2y) c. x? +2y? = c(x -2y) d. x? + 4y? - c (x +у) %3Darrow_forward
- SIDE B 5. 4. 3. 1. 2. 2x + 3y = 23 −2x + y = 13 x + 4y = 19 −3x + 2y = −1 2x + 3y = 1 x + 2y = 0 6x + 7y = 28 - 2x − y = −4 4x + 3y = −13 −7x + 2y = 1arrow_forwardthe first outcome is one of X and Y the second outcome is one of A and B if the first outcome is X, and one of A, B, and C if the first outcome is Y. Pr[X]=0.4Pr[X]=0.4Pr[Y]=0.6Pr[Y]=0.6Pr[A|X]=0.5Pr[A|X]=0.5Pr[B|X]=0.5Pr[B|X]=0.5Pr[A|Y]=0.3Pr[A|Y]=0.3Pr[B|Y]=0.2Pr[B|Y]=0.2Pr[C|Y]=0.5 (1) Pr[A]= (2) Pr[X|A]=Pr[X|A]= (3) Pr[Y|B]= (4) Pr[B|Y]=arrow_forward9. What is the solution of (x? +2xy – 4y? )dx - (x² – 8xy – 4y² )dy =0 ? a. x? - 4y? = c(x-y) b. x? +2y? = c(x +2y) c. x? +2y? = c(x - 2y) d. x? + 4y? = c(x +y)arrow_forward
- Find two different particular solutions for 3x + 4y = 2 о (2, —1) аnd (0, 1) O (0, ) and (2, –5) о (-3, 2) аnd (5, 4) О (2, —1) аnd (0, %3)arrow_forward1. y(5) − y(4) +4y(³³) – 4y" = 0arrow_forward. Find the general solution of (x + 3y – 4)dx + (2x + 6y – 8)dy = 0 %3D *+y = C b. 2x + y = C c. x + 2y = C d. x - 2y %3D Сarrow_forward
- 23.The following problem illustrates a danger that occurs because of round-off error when nearly equal numbers are subtracted and the difference is then multiplied by a large number. Evaluate the quantity 1000⋅∣∣∣6.01018.042.0046.000∣∣∣1000·6.01018.0402.00416.000 in the following ways: a.First round each entry in the determinant to two digits.arrow_forward3. Find the general solution of 2x + 2xy %3D dx y+ 2x"y A. 1+ 2x2 = C(1 + y?) B. 1+ 2x? = C(1 - y?) C. 1- 2x? = C(1 - y?) %3! %3D D. 1- 2x? C(1 + y*) %3!arrow_forward5. (BH) Calculate det B, where 0. 4 1 -2 4 1 B = 1 -1 1 -1 0 7arrow_forward
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