Physics (5th Edition)
5th Edition
ISBN: 9780321976444
Author: James S. Walker
Publisher: PEARSON
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Question
Chapter 32, Problem 68GP
To determine
The particle which gets deflected by a greater amount, if the speed of the particles is same.
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Students have asked these similar questions
An alpha particle is whizzing by at a velocity determined by its KE of 5 Mev.
a ) What is the velocity of the alpha particle?
b) What is the magnetic field at the position of a nucleus 2nm away from the alpha particle at angle of 900 to the velocity of the alpha. Alpha particle has charge of 2e but mass of 4 protons.
Particle
Electron
Proton
Neutron
Relative
Charge
-1
+1
0
What is:
Electric Charge (C)
-1.60 x 10-19
+1.60 x 10-19
0
a) The mass defect?
Relative Mass (u)
5.485779 x 10-4
1.007276
1.008665
1u = 1.6605 x 10-27 kg
1eV = 1.60 x 10-19 Joules
The 'cheating' equivalence shortcut
1u- 931.5 MeV
He is the most abundant isotope of helium. Its mass is 6.6447x 10-27kg.
Mass (kg)
b) The binding energy of the nucleus in joules?
9.109390 x 10-31
1.672623 x 10-27
1.674929 x 10-27
c.
OV
proton-
1.8 cm
+270V
A proton is placed between the plates in the figure above. Explain quantitatively
why, when predicting the motion of the proton between the plates, the
gravitational field is not taken into consideration.
EV (8)
Chapter 32 Solutions
Physics (5th Edition)
Ch. 32.1 - Prob. 1EYUCh. 32.2 - A given nucleus can decay by alpha decay, beta...Ch. 32.3 - Prob. 3EYUCh. 32.4 - Prob. 4EYUCh. 32.5 - Prob. 5EYUCh. 32.6 - Prob. 6EYUCh. 32.7 - Prob. 7EYUCh. 32.8 - Prob. 8EYUCh. 32.9 - Prob. 9EYUCh. 32 - Prob. 1CQ
Ch. 32 - Prob. 2CQCh. 32 - Prob. 3CQCh. 32 - Prob. 4CQCh. 32 - Prob. 5CQCh. 32 - Prob. 6CQCh. 32 - Prob. 7CQCh. 32 - Prob. 8CQCh. 32 - Prob. 9CQCh. 32 - Prob. 1PCECh. 32 - Prob. 2PCECh. 32 - Prob. 3PCECh. 32 - Prob. 4PCECh. 32 - Prob. 5PCECh. 32 - Prob. 6PCECh. 32 - Prob. 7PCECh. 32 - Prob. 8PCECh. 32 - Prob. 9PCECh. 32 - Prob. 10PCECh. 32 - Prob. 11PCECh. 32 - Prob. 12PCECh. 32 - Prob. 13PCECh. 32 - Prob. 14PCECh. 32 - Prob. 15PCECh. 32 - Prob. 16PCECh. 32 - Prob. 17PCECh. 32 - Prob. 18PCECh. 32 - Prob. 19PCECh. 32 - Prob. 20PCECh. 32 - Prob. 21PCECh. 32 - Prob. 22PCECh. 32 - Prob. 23PCECh. 32 - Prob. 24PCECh. 32 - Prob. 25PCECh. 32 - Prob. 26PCECh. 32 - Prob. 27PCECh. 32 - Prob. 28PCECh. 32 - Suppose we were to discover that the ratio of...Ch. 32 - A radioactive sample is placed in a closed...Ch. 32 - Radon gas has a half-life of 3.82 d. What is the...Ch. 32 - Prob. 32PCECh. 32 - The number of radioactive nuclei in a particular...Ch. 32 - Prob. 34PCECh. 32 - Prob. 35PCECh. 32 - Prob. 36PCECh. 32 - Prob. 37PCECh. 32 - Prob. 38PCECh. 32 - Prob. 39PCECh. 32 - Prob. 40PCECh. 32 - Prob. 41PCECh. 32 - Prob. 42PCECh. 32 - Prob. 43PCECh. 32 - Prob. 44PCECh. 32 - Prob. 45PCECh. 32 - Prob. 46PCECh. 32 - Prob. 47PCECh. 32 - Prob. 48PCECh. 32 - Prob. 49PCECh. 32 - Prob. 50PCECh. 32 - Prob. 51PCECh. 32 - Prob. 52PCECh. 32 - Prob. 53PCECh. 32 - Prob. 54PCECh. 32 - Prob. 55PCECh. 32 - Consider a fusion reaction in which two deuterium...Ch. 32 - Prob. 57PCECh. 32 - Prob. 58PCECh. 32 - Prob. 59PCECh. 32 - Prob. 60PCECh. 32 - Prob. 61PCECh. 32 - Prob. 62PCECh. 32 - Prob. 63PCECh. 32 - Prob. 64PCECh. 32 - Prob. 65PCECh. 32 - Prob. 66PCECh. 32 - Prob. 67PCECh. 32 - Prob. 68GPCh. 32 - Prob. 69GPCh. 32 - Prob. 70GPCh. 32 - Prob. 71GPCh. 32 - Prob. 72GPCh. 32 - Prob. 73GPCh. 32 - Moon Rocks In one of the rocks brought back from...Ch. 32 - Prob. 75GPCh. 32 - Prob. 76GPCh. 32 - Prob. 77GPCh. 32 - Prob. 78GPCh. 32 - Prob. 79GPCh. 32 - Prob. 80GPCh. 32 - Prob. 81GPCh. 32 - Prob. 82GPCh. 32 - Prob. 83GPCh. 32 - Prob. 84GPCh. 32 - Prob. 85GPCh. 32 - Prob. 86GPCh. 32 - Prob. 87GPCh. 32 - Prob. 88GPCh. 32 - Prob. 89PPCh. 32 - Prob. 90PPCh. 32 - Prob. 91PP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- When a nucleus (decays, does the (particle move continuously from inside the nucleus to outside? That is, does it travel each point along an imaginary line from inside to out? Explain.arrow_forwardA Thomson-type experiment with relativistic electrons. One of the earliest experiments to show that p = mv (rather than p = mv) was that of Neumann. [G. Neumann, Ann. Physik 45:529 (1914)]. The apparatus shown in Figure P4.5 is identical to Thomsons except that the source of high-speed electrons is a radioactive radium source and the magnetic field B is arranged to act on the electron over its entire trajectory from source to detector. The combined electric and magnetic fields act as a velocity selector, only passing electrons with speed v, where v = V/Bd (Equation 4.6), while in the region where there is only a magnetic field the electron moves in a circle of radius r, with r given by p = Bre. This latter region (E = 0, B = constant) acts as a momentum selector because electrons with larger momenta have paths with larger radii. (a) Show that the radius of the circle described by the electron is given by r = (l2 + y2)/2y. (b) Typical values for the Neumann experiment were d = 2.51 104 m, B = 0.0177 T, and l = 0.0247 m. For V = 1060 V, y, the most critical value, was measured to be 0.0024 0.0005 m. Show that these values disagree with the y value calculated from p = mv but agree with the y value calculated from p = mv within experimental error. (Hint: Find v from Equation 4.6, use mv = Bre or mv = Bre to find r, and use r to find y.) Figure P4.5 The Neumann apparatus.arrow_forwardThis problem demonstrates that the binding energy of the electron in the ground state of a hydrogen atom is much smaller than the rest mass energies of the proton and electron. Calculate the mass equivalent in u of the 13.6-eV binding energy of an electron in a hydrogen atom, and compare this with the known mass of the hydrogen atom. Subtract the known mass of the proton from the known mass of the hydrogen atom. Take the ratio of the binding energy of the electron (13.6 eV) to the energy equivalent of the electron’s mass (0.511 MeV). Discuss how your answers confirm the stated purpose of this problem.arrow_forward
- (a) The lifetime of a highly unstable nucleus is 10-20. What is the smallest uncertainty in its decay energy? (b) Compare this with the rest energy of an electron.arrow_forwardUnreasonable Results A frazzled theoretical physicist reckons that all conservation laws are obeyed in the decay of a proton into a neutron, positron, and neutrino (as in (+ decay of a nucleus) and sends a paper to a journal to announce the reaction as a possible end of the universe due to the spontaneous decay of protons. (a) What energy is released in this decay? (b) What is unreasonable about this result? (c) What assumption is responsible?arrow_forwardExplain how an (particle can have a larger range in air than a (particle with the same energy in lead.arrow_forward
- (a) Calculate the velocity of an electron that has a wavelength of 1.00 m. (b) Through what voltage must the electron be accelerated to have this velocity?arrow_forwardIn a few sentences, explain how you know that E(r)=(kQs/r2)r (Eq. 24.3) is consistent with Figure 24.4C. E(r)=(kQs/r2)rarrow_forwardIntegrated Concepts In a Millikan oil-drop experiment using a setup like that in Figure 30.9, a 500-V potential difference is applied to plates separated by 2.50 cm. (a) What is the mass of an oil drop having two extra electrons that is suspended motionless by the field between the plates? (b) What is the diameter of the drop, assuming it is a sphere with the density of olive oil?arrow_forward
- Unreasonable Results (a) What is the binding energy of electrons to a material from which 4.00-eV electrons are ejected by 400-nm EM radiation? (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardUnreasonable Results (a) Assuming it is nonrelativistic, calculate the velocity of an electron with a 0.100-fm wavelength (small enough to detect details of a nucleus). (b) What is unreasonable about this result? (c) Which assumptions are unreasonable or inconsistent?arrow_forwardThe purpose of this problem is to show in three ways that the binding energy at the election in a hydrogen atom is negligible compared with the masses of the proton and electron. (a) Calculate the mass equivalent in u of the 13.6eV binding energy of an electron in a hydrogen atom, and compete this with the mass of the hydrogen atom obtained from Appendix A. (b) Subtract the mass at the proton given in Table 31.2 from the mass at the hydrogen atom given in Appendix A. You will find the difference is equal to the electron’s mass to three digits, implying the binding energy is small in comparison. (c) Take the ratio of the binding energy at the electron (13.6 eV) to the energy equivalent of the electron's mass (0.511 MeV). (d) Discuss how your answers confirm the stated purpose of this problem.arrow_forward
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