Concept explainers
(a)
The image distances for given object distances.
(a)
Explanation of Solution
Given:
The object distances are,
The radius of curvature is
Formula used:
Write expression for mirror equation.
Here,
Substitute
Solve above expression for
Calculation:
Substitute
Substitute
Substitute
Substitute
Substitute
Conclusion:
Thus, the image distance is
(b)
The magnification of each given object distance.
(b)
Explanation of Solution
Given:
The object distances are,
The radius of curvature is
Formula used:
Write expression for magnification for mirror.
Calculation:
Substitute
Substitute
Substitute
Substitute
Substitute
Conclusion:
Thus, the magnification for first case is
Want to see more full solutions like this?
Chapter 32 Solutions
Physics for Scientists and Engineers
- A lamp of height S cm is placed 40 cm in front of a converging lens of focal length 20 cm. There is a plane mirror 15 cm behind the lens. Where would you find the image when you look in the mirror?arrow_forwardThe left face of a biconvex lens has a radius of curvature of magnitude 12.0 cm, and the right face has a radius of curvature of magnitude 18.0 cm. The index of refraction of the glass is 1.44. (a) Calculate the focal length of the lens for light incident from the left. (b) What If? After the lens is turned around to interchange the radii of curvature of the two faces, calculate the focal length of the lens for light incident from the left.arrow_forwardA thin plastic lens with index of refraction n = 1.67 has radii of curvature given by R1 = 12 0 cm and R2 = 40.0 cm. Determine (a) the focal length of the lens, (b) whether the lens Ls converging or diverging and the image distances for object distances of (c) infinity, (d) 8,00 cm, and (e) 50.0 cm.arrow_forward
- Two thin lenses of focal lengths f1 = 15.0 and f2 = 10.0 cm, respectively, are separated by 35.0 cm along a common axis. The f1 lens is located to the left of the f2 lens. An object is now placed 50.0 cm to the left of the f1 lens, and a final image due to light passing though both lenses forms. By what factor is the final image different in size from the object? (a) 0.600 (b) 1.20 (c) 2.40 (d) 3.60 (e) none of those answersarrow_forwardA point source of light is 50 cm in front of a converging lens of focal length 30 cm. A concave mirror with a focal length of 20 cm is placed 25 cm behind the lens. Where does the final image form, and what are its orientation and magnification?arrow_forwardA thin plastic lens with index of refraction n = 1.67 has radii of curvature given by R1 = 12 0 cm and R2 = 40.0 cm. Determine (a) the focal length of the lens, (b) whether the lens Ls converging or diverging and the image distances for object distances of (c) infinity, (d) 8,00 cm, and (e) 50.0 cm.arrow_forward
- A diverging lens has a focal length of magnitude 20.0 cm (a) Locate the images for object distances of (i) 40.0 cm. (ii) 20.0 cm, and (iii) 10.0 cm. For each case, state whether the image is (b) real or virtual and (c) upright or inverted. (d) For each case, Find the magnification.arrow_forwardA 7.5x binocular produces an angular magnification of 7.50, acting like a telescope. (Mirrors are used to make the image upright.) If the binoculars have objective lenses with a 75.0 cm focal length, what is the focal length of the eyepiece lenses?arrow_forwardThe disk of the Sun subtends an angle of 0.533 at the Earth. What are (a) the position and (b) the diameter of the solar image formed by a concave spherical mirror with a radius of curvature of magnitude 3.00 m?arrow_forward
- A converging lens has a focal length of 10.0 cm. Locate the object if a real image is located at a distance from the lens of (a) 20.0 cm and (b) 50.0 cm. What If? Redo the calculations if the images are virtual and located at a distance from the lens of (c) 20.0 cm and (d) 50.0 cm.arrow_forwardA convex mirror with a radius of curvature of 25.0 cm is used to form an image of an arrow that is 10.0 cm away from the mirror. If the arrow is 2.00 cm tall and inverted (pointing below the optical axis), what is the height of the arrows image?arrow_forwardThe contact-lens prescription for a nearsighted person is —4.00 D and the person has a far point of 22.5 cm. What is the power of the tear layer between the cornea and the lens if the correction is ideal, taking the tear layer into account?arrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStaxPhysics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning