College Physics
College Physics
2nd Edition
ISBN: 9780134601823
Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan
Publisher: Pearson,
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Chapter 30, Problem 6P

Use Newtonian circular motion concepts to show that the radius r of the circle in which a charged particle spirals while moving perpendicular to a magnetic field is proportional to the particle’s speed V.

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AI answered the problem this way. Is this correct?  The Lorentz force that makes a charged particle move in a circular path in a magnetic field is given by F=qvBF=qvB where qq is the charge of the particle, vv is the speed of the particle, and BB is the magnetic field strength. Since the particle is moving in a circular path, this force must equal the centripetal force, F=mv2rF=rmv2​, where mm is the mass of the particle and rr is the radius of the circular path. Setting the two expressions for FF equal to each other, we get qvB=mv2rqvB=rmv2​ Since we want to find the frequency of the orbit, we need to find the speed vv of the proton. Given that the energy of the proton is 1 MeV, we can write 12mv2=1 MeV21​mv2=1MeV and solve for vv: v=2×1 MeVmv=m2×1MeV​​ where mm is the mass of a proton, which is approximately 1.67×10−27 kg1.67×10−27kg. Substituting this expression for vv into the expression for the Lorentz force, we can solve for the frequency of the orbit. The frequency is related to…
Consider a region where the electric field and the magnetic field are along the +x- and the -y-axes, respectively. If a certain charge is in the region, at what velocity should it move so that it will move in a uniform velocity? (To maintain a uniform velocity, the Lorentz force must be zero) Let E and B be the magnitudes of the electric field and of the magnetic field, respectively. B V = - - B E az V = E V = az 1>
A cosmic ray travels 60 km through the earth’s atmosphere in 400 μs, as measured by experimenters on the ground. How long does the journey take according to the cosmic ray?

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