Chapter 30, Problem 51A

To determine

To calculate:

The isotopic symbol used in nuclear equation of zinc atom composed of $30$ protons and $34$ neutrons.

Answer to Problem 51A

The answer is $Zn$ .

Explanation of Solution

Given:

For a Zinc $\left(Zn\right)$ atom:

Number of protons $=30$

Number of neutrons $=34$

Formula Used:

Formula to calculate isotopic symbol is given by,

  $X$

Where,

  $A$ : Atomic Mass Number of Protons $+$ Neutrons.

  $Z$ : Atomic Number of protons

Calculation:

For a Zinc $\left(Zn\right)$ atom,

Formula to calculate isotopic symbol is given by,

  $X$

For Zinc the isotopic symbol is given as,

  $Zn$

Substitute all the values in then formula,

Number of protons and neutrons $=A=30+34=64$

Number of protons $=Z=30$

The isotopic symbol is thus written as,

  $Zn$

Conclusion:

The isotopic symbol used in nuclear equation of zinc atom composed of $30$ protons and $34$ neutrons is $Zn$ .