Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 30, Problem 4P
To determine
The modified form of Gauss’s law for magnetism.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A cube of uniformly magnetized material of side length L = 0.050 m has magnetization M = 2000 amperes per meter when sitting on the table. You then place the cube in a uniform, upward pointing magnetic field of strength Bext = 0.0040T. The cube’s magnetization vector is also pointing upward. The magnetization remains at M = 2000 A/m.
(a) From what we’ve said above, must the cube be made from a paramagnetic, diamagnetic, or ferromagnetic material?
(b) When the cube is sitting in the external magnetic field, what is the strength of the magnetic field inside the cube?
(c) When the cube is in the external field, how much work would it take to flip the cube over?
An iron (density ρ) rod with length L, cross sectional area A, spans across two parallel, metal train tracks. The tracks are connected to a power supply and have a potential ∆V across them. Between the tracks are placed magnets such that the B-field points directly upwards with strength B. What is the acceleration of the iron rod be the moment it starts from rest? What will acceleration be as a function of speed as it continues? Assume the contact is frictionless between the tracks and the rod so that no force of friction needs to be overcome. What will the top speed of the rod be under these conditions?
Is the following True or False for the Gauss's Law for magnetic field?
Since there are no magnetic monopoles, magnetic field lines can not start or end anywhere. They always come as loops. That is why magnetic flux through a
closed surface is always zero:
OB dA = 0
O True
O False
Chapter 30 Solutions
Physics for Scientists and Engineers
Ch. 30 - Prob. 1PCh. 30 - Prob. 2PCh. 30 - Prob. 3PCh. 30 - Prob. 4PCh. 30 - Prob. 5PCh. 30 - Prob. 6PCh. 30 - Prob. 7PCh. 30 - Prob. 8PCh. 30 - Prob. 9PCh. 30 - Prob. 10P
Ch. 30 - Prob. 11PCh. 30 - Prob. 12PCh. 30 - Prob. 13PCh. 30 - Prob. 14PCh. 30 - Prob. 15PCh. 30 - Prob. 16PCh. 30 - Prob. 17PCh. 30 - Prob. 18PCh. 30 - Prob. 19PCh. 30 - Prob. 20PCh. 30 - Prob. 21PCh. 30 - Prob. 22PCh. 30 - Prob. 23PCh. 30 - Prob. 24PCh. 30 - Prob. 25PCh. 30 - Prob. 26PCh. 30 - Prob. 27PCh. 30 - Prob. 28PCh. 30 - Prob. 29PCh. 30 - Prob. 30PCh. 30 - Prob. 31PCh. 30 - Prob. 32PCh. 30 - Prob. 33PCh. 30 - Prob. 34PCh. 30 - Prob. 35PCh. 30 - Prob. 36PCh. 30 - Prob. 37PCh. 30 - Prob. 38PCh. 30 - Prob. 39PCh. 30 - Prob. 40PCh. 30 - Prob. 41PCh. 30 - Prob. 42PCh. 30 - Prob. 43PCh. 30 - Prob. 44PCh. 30 - Prob. 45PCh. 30 - Prob. 46PCh. 30 - Prob. 47PCh. 30 - Prob. 48PCh. 30 - Prob. 49PCh. 30 - Prob. 50PCh. 30 - Prob. 51PCh. 30 - Prob. 52PCh. 30 - Prob. 53PCh. 30 - Prob. 54PCh. 30 - Prob. 55PCh. 30 - Prob. 56PCh. 30 - Prob. 57PCh. 30 - Prob. 58PCh. 30 - Prob. 59P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An electron of kinetic energy 2000 eV passes between parallel plates that are 1.0 an apart and kept at a potential difference of 300 V. What is the strength of the uniform magnetic field B that will allow the electron to travel undeflected through the plates? Assume E and B are perpendicular.arrow_forwardAn electron in a TV CRT moves with a speed of 6.0107 m/s, in a direction perpendicular to Earth's field, which has a strength of 5.0105 T. (a) What strength electric field must be applied perpendicular to the Earth’s field to make the election moves in a straight line? (b) If this is done between plates separated by 1.00 cm, what is the voltage applied? (Note that TVs are usually surrounded by a ferromagnetic material to shield against external magnetic fields and avoid the need for such a collection,)arrow_forward(a) A cosmic ray proton moving toward the Earth at 5.00107m/s experiences a magnetic force of 1.701016N. What is the strength of the magnetic field it there is a 45° angle between it and the proton’s velocity? (b) Is the value obtained in part (a) consistent with the known strength of the Earth’s magnetic field on its surface? Discuss.arrow_forward
- Repeat the previous problem, but with the loop lying flat on the ground with its current circulating counterclockwise (when viewed from above) in a location where Earth’s field is north, but at an angle 45.0° below the horizontal and with a strength of 6.0105T.arrow_forwardA circular parallel-plate capacitor whose plates have a radius of (5.640x10^1) cm is being charged with a current of (2.1x10^1) A. What is the magnetic field (9.660x10^0) cm from the center of the plates? Express your result in UT with two significant figures.arrow_forwardPlease help. I don't get this.arrow_forward
- A magnetic dipole m is imbedded at the center of a sphere (radius R) of linear magnetic material (permeability u). Show that the magnetic field inside the sphere (0arrow_forwardAnswer must be in standard form scientific notation with SI units that do not have prefixes except for kg. Provide the answer with the correct amount of significant figures. Thank you so much I greatly appreciate itarrow_forwardConsider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If e = 25.0°, the radius of the arc is 0.700 m, and the current is 2.00 A, what are the magnitude (in nT) and direction of the field produced at P? G magnitude 1.047 Apply the Biot-Savart law. What will be the contributions of the segments of wire along the straight-line sections? Hint: what is ds x f for each segment? nT direction toward the top of the screen X Use the right-hand rule to determine the direction.arrow_forward1. Fig 1, shows a hollow cylindrical conductor of radii a and b which carries a current i uniformly spread over its cores section. a) show the the magnetic field B from points inside the body of the conductor is given by B={uoi/27(b²-a)} {(r2-a)/r}. And check the case when a=0. b) Make a rough plot at the general behavior of B(r) from r=0 to infinite. [r-current Fig. 1arrow_forwardThe angular momentum of a mass distribution where a differential element particle of mass m with velocity v and located at position r is defined in the form L = dmr x v = dvpr x v, p= nm where n is the number of particles per unit volume and m is its mass. If each of the particles has a charge q, with their movement they constitute a current J = nqv Show that the relationship between the magnetic dipole moment and the angular momentum is L m = 2m where the magnetic moment is defined m = dvr x Jarrow_forwardadvanced physics,arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeModern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning