Architectural Drafting and Design (MindTap Course List)
7th Edition
ISBN: 9781285165738
Author: Alan Jefferis, David A. Madsen, David P. Madsen
Publisher: Cengage Learning
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Chapter 30, Problem 30.4Q
To determine
The 2×8 floor joist can support the living area of 14' span.
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Please don't explain it. But draw it out for me kindly. And appreciate your time!. All the info is in the images. Thanks!.
Design a simply supported one-way pavement slab for a factored applied moment, Mu = 10 ft-kip. Use f c’ = 5,000 psi and f y = 60,000 psi. The slab is in permanent contact with soil.Hint:• Estimate a minimum slab thickness for deflection control.• Solve for the slab steel based on cover for soil contact
The figures below shows the framing plan and section of a reinforced concrete floor system. Floor beams are shown as dotted lines. The weight of the ceiling and floor finishing is 6 psf, that of the mechanical and electrical systems is 7 psf, and the weight of the partitions is 180 psf. The floor live load is 105 psf. The 7 in. thick slab exterior bay (S-1) is reinforced with #5 rebars @ 10 in. o.c. as the main positive reinforcement at the mid span, and #4 @ 109 in. for the shrinkage and temperature reinforcement. The panel is simply supported on the exterior edge and monolithic with the beam at the interior edge. Check the adequacy of the slab. Use the ACI moment coefficients. fc’ = 6,000 psi and fy = 60,000 psi. The slab is in an interior location. Hint: • Estimate total dead load. Find factored maximum positive bending moment in the end span. • Find design positive moment capacity. • Compare and determine adequacy, including safety and economy.
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Architectural Drafting and Design (MindTap Course List)
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- 1 For an reinforced concrete two-way slab shown in figure under the load (P). (the slab continuous over all edges - all sides are fixed), Determine (By using yield line theory): A- Draw the Yield line Pattern B- Determine the moment m C- Find The required flexural steel to resist the loads causing the slab to collapse if P = 200 KN, f=28 MPa, fy = 420 MPa d = 120 mm. Use 10 mm bars. (Prin = 0.002) +2 m 6 m -8 m 3 marrow_forwardAt a point on the surface of a generator shaft the stresses are σx = -55MPa, σy = 25MPa and Txy = -20MPa as shown in Figure Q1. (a) Using either analytical method or Mohr's circle determine the following: Stresses acting on an element inclined at an angle 0 = 35°, i. ii. iii. The maximum shear stress The principal stresses and B. 25 MPa A 55 MPa 20 MPa Figure 1:Material stress state (b) Consider that the Young's modulus for the material, E = 200kPa and Poisson's ratio, v = 0.25. i. ii. determine associate strains for the material with the stress as shown in Figure 1 determine associate strains for the material with the stress at element oriented at 35° (question 1a(i))arrow_forwardA study reports data on the effects of the drug tamoxifen on change in the level of cortisol-binding globulin (CBG) of patients during treatment. With age = x and ACBG = y, summary values are n = 26, Σx, = 1612, Σ(x, - x)² = 3756.96, Σy, = 281.9, Σ(y, - y)² = 465.34, and Ex,y,= 16,745. (a) Compute a 90% CI for the true correlation coefficient p. (Round your answers to four decimal places.) (b) Test Hop=-0.5 versus H: p< -0.5 at level 0.05. Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. ◇ Reject Ho. There is no evidence that p < -0.5. ○ Fail to reject Ho. There is evidence that p < -0.5. Reject Ho. There is evidence that p < -0.5. Fail to reject Ho. There is no evidence that p < -0.5. (c) In a regression analysis of y on x, what proportion of variation in change of cortisol-binding globulin level could be explained by variation in…arrow_forward
- For the frame and loading shown, determine the reactions at A and C. 24 Last 2 student ID+50 lbs 24 A 3 in. B A=Last 2 student ID+10 Inch B=Last 2 student ID+40 Inch A B Darrow_forwardThe figures below shows the framing plan and section of a reinforced concrete floor system. Floor beams are shown as dotted lines. The weight of the ceiling and floor finishing is 6 psf, that of the mechanical and electrical systems is 7 psf, and the weight of the partitions is 180 psf. The floor live load is 105 psf. The 7 in. thick slab exterior bay (S-1) is reinforced with #5 rebars @ 10 in. o.c. as the main positive reinforcement at the mid span, and #4 @ 109 in. for the shrinkage and temperature reinforcement. The panel is simply supported on the exterior edge and monolithic with the beam at the interior edge. Check the adequacy of the slab. Use the ACI moment coefficients. fc’ = 6,000 psi and fy = 60,000 psi. The slab is in an interior location. Hint: • Estimate total dead load. Find factored maximum positive bending moment in the end span. • Find design positive moment capacity. • Compare and determine adequacy, including safety and economy. C Darrow_forwardFor an reinforced concrete two-way slab shown in figure under the load (P). (the slab continuous over all edges - all sides are fixed), Determine (By using yield line theory): A- Draw the Yield line Pattern B- Determine the moment m C- Find The required flexural steel to resist the loads causing the slab to collapse if P = 200 KN, f=28 MPa, fy = 420 MPa d = 120 mm. Use 10 mm bars. Draw the yield line and (Qmin = 0.002) 2m solve PO 6 m 3 m -8 marrow_forward
- Find the internal torques for segments AB, BC, and CD (in N-m) by drawing the internal torque diagram, the maximum torsional shear on the shaft in MPa, and the relative rotation of section A with respect to section D in degrees.arrow_forwardFor an reinforced concrete two-way slab shown in figure under the load (P). (the slab continuous over all edges - all sides are fixed), Solve by using equilibrium method A- Draw the Yield line Pattern B- Determine the moment m C- Find The required flexural steel to resist the loads causing the slab to collapse if P = 200 kN, f=28 MPa, fy = 420 MPa d = 120 mm. Use 10 mm bars. (Pmin = 0.002) 2 m 6 m -8 m 3 marrow_forwardA double-T simply supported concrete beam its cross section is shown in Figure, is prestressed with 2 tendons each 400 mm². Determine the allowable service load. Use span 12 m, fse = 1300 MPa, fe = 40 MPa, y = 25 kN/m³. = 1200 mm >09 *100* As = 400 +100+ As = 400 400 1400+arrow_forward
- A double-T simply supported concrete beam its cross section is shown in Figure, is prestressed with 2 tendons each 400 mm². Determine the allowable service load. Use span 12 m, fse = 1300 MPa, fc = 40 MPa, y = 25 kN/m³. = 1200 mm >09< *100* As = 400 +100+ As = 400 400 1400+arrow_forwardA prestressed simply supported 15 m span beam with rectangular box section is post-tensioned by straight high tensile steel wires as shown in Figure. The prestressing wires are placed at the center line of the flanges and initially stressed to 850 N/mm². The beam is required to carry a uniformly distributed superimposed load of 4.5 kN/m in addition to its weight. If the concrete stresses are not to exceed 17 MPa in compression and 1 MPa in tension at service stage, calculate the range of the total prestressing wires area required. Ignore prestressing force losses in your answer. (Ye kN/m³). = 24 2As 400 As 80 80; 750arrow_forwardA simply supported rectangular prestressed concrete beam, of span 13 m and its cross section as shown in figure, is carrying a live load equals to 30 kN/m in addition to its weight, compute the following stresses and compare it with ACI allowable stress: a) Bottom fiber stress at support in initial stage. b) Top fiber stress at mid span in final stage. Use y = 24 kN/m³, As = 600 mm², initial stress of the prestressed steel = 1200 MPa, total losses is 20%, fci = 22 MPa, and fo' = 28 MPa 800 mm 3 As 400 mm As 340 mm 340 mmarrow_forward
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