Concept explainers
A proton travels at 100 m/s in and parallel to a 2.00-T magnetic field. What is the magnitude of the force on the proton?
The magnitude of the force on the proton, which travels at a speed of
Answer to Problem 14SP
Solution:
Explanation of Solution
Given data:
The velocity of the proton is
Themagnitude of the magnetic field acting on the proton is
Formula used:
The expression for a force acting on a charge moving in a magnetic field is written as
Here,
Explanation:
Recall the expression fora force acting on a charge moving in a magnetic field:
Since the charge is travelling parallel to the magnetic field, the angle between the velocity of the charge and the direction of the magnetic field becomes
Substitute
The charge on the proton is
Conclusion:
Hence, the magnitude of the force acting on the proton is
Want to see more full solutions like this?
Chapter 30 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
- A proton travels with a speed of 3.00 106 m/s at an angle of 37.0 with the direction of a magnetic field of 0.300 T in the +y direction. What are (a) the magnitude of the magnetic force on the proton and (b) its acceleration?arrow_forwardThe magnitude of the magnetic field 50 cm from a long, thin, straight wire is 8.0T . What is the current through the long wire?arrow_forwardA toroid has 250 trims of wire and carries a current of 20 A. Its inner and outer radii are 8.0 and 9.0 cm. What are the values of its magnetic field at r = 8.1, 8.5, and 8.9 cm?arrow_forward
- A cosmic-ray electron moves at 7.5 × 106 m/sinches perpendicular to Earth’s magnetic field at an altitude queer the field strength is 1.0 × 105T. What is the radius of the circular path the electron follows?arrow_forwardAn electron is projected into a uniform magnetic field (0.5i+0.8k)T with a velocity of (3.0i+4.0j)106 m/s . What is the magnetic force on the electron?arrow_forwardAn electron is accelerated through 2.40 103 V from rest and then enters a uniform 1.70-T magnetic field. What are (a) the maximum and (b) the minimum values of the magnetic force this particle experiences?arrow_forward
- An electron moving at 4.00103 m/s in a 1.25-T magnetic field experiences a magnetic force of 1.401016 N. What angle does the velocity of the electron make with the magnetic field? There are two answers.arrow_forward(a) A cosmic ray proton moving toward the Earth at 5.00107m/s experiences a magnetic force of 1.701016N. What is the strength of the magnetic field it there is a 45° angle between it and the proton’s velocity? (b) Is the value obtained in part (a) consistent with the known strength of the Earth’s magnetic field on its surface? Discuss.arrow_forwardElectrons in Earths upper atmosphere have typical speeds near 6.00 105 m/s. (a) Calculate the magnitude of Earths magnetic field if an electrons velocity is perpendicular to the magnetic field and its circular path has a radius of 7.00 102 m. (b) Calculate the number of times per second that an electron circles around a magnetic field line.arrow_forward
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning