Explanation Given information: Radius = 1.2 mm Calculation: According to the question, Let r(t)be the radius of the cross -sectional area of the artery at time t. Then its area will be A ( t ) = π r 2 ( t ) On differentiating with respect to t(time), we get d A d t = π ( 2 r d r d t ) d A d t = 2 π r d r d t ...... ( 1 ) It is given that initially the radius is r 0 = 1.2 mm . Hence, the thickness of the fat deposit will be T ( r ) = 1

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

6th Edition

ISBN: 9781524908102

Author: SMITH KARL J, STRAUSS MONTY J, TODA MAGDALENA DANIELE

Publisher: Kendall Hunt Publishing

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Chapter 3, Problem 85SP

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To find: The rate at which the cross-sectional area of the artery.

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Chapter 3, Problem 84SP

Chapter 3, Problem 86SP

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Chapter 3 Solutions

Calculus: Special Edition: Chapters 1-5 (w/ WebAssign)

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The rate at which the cross-sectional area of the artery.

Solution Summary: The author calculates the rate at which the cross-sectional area of the artery is equal to -1.8pi.

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To find: The rate at which the cross-sectional area of the artery.

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Chapter 3 Solutions