Concept explainers
Find the mesh currents in the circuit of Figure 3.98 using MATLAB.
Answer to Problem 53P
The value of currents
Explanation of Solution
Given data:
Refer to Figure 3.98 in the textbook for mesh analysis.
Calculation:
From Figure 3.98, write the expression for current
Apply Kirchhoff’s voltage law to loop 1 with current
Apply Kirchhoff’s voltage law to loop 2 with current
Substitute equation (1) in (3).
Apply Kirchhoff’s voltage law to loop 3 with current
Substitute equation (1) to (5).
Apply Kirchhoff’s voltage law to loop 5 with current
Substitute equation (1) to (7).
MATLAB code:
Write the MATLAB code to solve the equations (2), (4), (6), and (8) as follows in MATLAB code editor, and save it as “node353”, and then run the code. The result will shows in main command window.
syms i1 i2 i3 i5
eq1 = 4*i1 -3*i2 -1*i3 +0*i5 == 0.012;
eq2 = -3*i1 +7*i2 +0*i3 +0*i5 == -0.012;
eq3 = -1*i1 +0*i2 +15*i3 -6*i5 == -0.024;
eq4 = 0*i1 +0*i2 -3*i3 +8*i5 == -0.012;
sol = solve([eq1, eq2, eq3, eq4], [i1, i2, i3, i5]);
val1 = sol.i1;
val2 = sol.i2;
val3 = sol.i3;
val4 = -0.003;
val5 = sol.i5;
i1= sprintf('%.7f A',val1)
i2= sprintf('%.7f A',val2)
i3= sprintf('%.7f A',val3)
i4= sprintf('%.3f A',val4)
i5= sprintf('%.7f A',val5)
The output in command window:
i1 = '0.0016196 A'
i2 = '-0.0010202 A'
i3 = '-0.0024612 A'
i4 = '-0.003 A'
i5 = '-0.0024230 A'
Convert obtained value of currents in milli amperes (mA).
Conclusion:
Therefore, the value of currents
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