Calculate the moist unit weight of soil.

Question

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Answer 1

Question

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

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Answer 2

Question

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

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Answer 3

Question

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

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Answer 4

Question

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

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Answer 5

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

Answer 6

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

Answer 7

Chapter 3, Problem 3.7P

(a)

To determine

Calculate the moist unit weight of soil.

Answer 8

(a)

Expert Solution

Answer to Problem 3.7P

The moist unit weight of soil is $125 lb/ft3_$ .

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Calculate the moist unit weight of the soil $(γ)$ using the relation.

$γ=WV$

Substitute $12.5 lb$ for W and $0.1 ft3$ for V.

$γ=12.50.1=125 lb/ft3$

Hence, the moist unit weight of soil is $125 lb/ft3_$ .

Answer 13

(b)

To determine

Calculate the dry unit weight of soil.

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

Answer 14

(b)

To determine

Calculate the dry unit weight of soil.

Answer 15

(b)

Expert Solution

Answer to Problem 3.7P

The dry unit weight of soil is $109.64 lb/ft3_$ .

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil is $125 lb/ft3$ .

Calculate the dry unit weight of the soil $(γd)$ using the relation.

$γd=γ1+w$

Substitute $125 lb/ft3$ for $γ$ and $14%$ for w.

$γd=1251+14100=1251.14=109.64 lb/ft3$

Hence, the dry unit weight of soil is $109.64 lb/ft3_$ .

Answer 20

(c)

To determine

Calculate the void ratio of soil.

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

Answer 21

(c)

To determine

Calculate the void ratio of soil.

Answer 22

(c)

Expert Solution

Answer to Problem 3.7P

The void ratio of soil is $0.54_$ .

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (b).

The dry unit weight of soil is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the void ratio $(e)$ using the relation.

$e=Gsγwγd−1$

Substitute $2.71$ for $Gs$ , $109.64 lb/ft3$ for $γd$ , and $62.4 lb/ft3$ for $γw$ .

$e=2.71×62.4109.64−1=169.104109.64−1=1.54−1=0.54$

Hence, the void ratio of soil is $0.54_$ .

Answer 27

(d)

To determine

Calculate the porosity of soil.

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

Answer 28

(d)

To determine

Calculate the porosity of soil.

Answer 29

(d)

Expert Solution

Answer to Problem 3.7P

The porosity of soil is $0.35_$ .

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the void ratio $(e)$ using the relation.

$n=e1+e$

Substitute $0.54$ for e.

$n=0.541+0.54=0.541.54=0.35$

Hence, the porosity of soil is $0.35_$ .

Answer 34

(e)

To determine

Calculate the degree of saturation.

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

Answer 35

(e)

To determine

Calculate the degree of saturation.

Answer 36

(e)

Expert Solution

Answer to Problem 3.7P

The degree of saturation is $70.2%_$ .

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (c).

The void ratio of soil is $0.54$ .

Calculate the degree of saturation $(S)$ using the relation.

$S=wGse$

Substitute $14%$ for w, $2.71$ for $Gs$ , and $0.54$ for e.

$S=14100×2.710.54=0.37940.54=0.702×100%=70.2%$

Hence, the degree of saturation is $70.2%_$ .

Answer 41

(f)

To determine

Calculate the volume of water.

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

Answer 42

(f)

To determine

Calculate the volume of water.

Answer 43

(f)

Expert Solution

Answer to Problem 3.7P

The volume of water is $0.024 ft3_$ .

Answer 44

(f)

Expert Solution

Answer 45

(f)

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

Given information:

The volume $(V)$ of the soil is $0.1 ft3$ .

The moist mass $(W)$ of the soil is $12.5 lb$ .

The moisture content $(w)$ is $14%$ .

The specific gravity of the soil solids $(Gs)$ is $2.71$ .

Calculation:

Refer to part (a).

The moist unit weight of soil $(γ)$ is $125 lb/ft3$ .

Refer to part (b).

The dry unit weight of soil $(γd)$ is $109.64 lb/ft3$ .

Consider the unit weight of water $(γw)$ is $62.4 lb/ft3$ .

Calculate the volume of water $(Vw)$ using the relation.

$Vw=(γ−γd)Vγw$

Substitute $125 lb/ft3$ for $γ$ , $109.64 lb/ft3$ for $γd$ , $62.4 lb/ft3$ for $γw$ , and $0.1 ft3$ for V.

$Vw=(125−109.64)×0.162.4=1.53662.4=0.024 ft3$

Therefore, the volume of water is $0.024 ft3_$ .

Answer 48

Ch. 3 - Prob. 3.1P Ch. 3 - Prob. 3.2P Ch. 3 - Prob. 3.3P Ch. 3 - Prob. 3.4P Ch. 3 - Prob. 3.5P Ch. 3 - Prob. 3.6P Ch. 3 - Prob. 3.7P Ch. 3 - Prob. 3.8P Ch. 3 - Prob. 3.9P Ch. 3 - Prob. 3.10P

Calculate the moist unit weight of soil.

Concept explainers

Calculate the moist unit weight of soil.

Answer to Problem 3.7P

Explanation of Solution

Calculate the dry unit weight of soil.

Answer to Problem 3.7P

Explanation of Solution

Calculate the void ratio of soil.

Answer to Problem 3.7P

Explanation of Solution

Calculate the porosity of soil.

Answer to Problem 3.7P

Explanation of Solution

Calculate the degree of saturation.

Answer to Problem 3.7P

Explanation of Solution

Calculate the volume of water.

Answer to Problem 3.7P

Explanation of Solution

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