Chemistry: Atoms First V1
Chemistry: Atoms First V1
1st Edition
ISBN: 9781259383120
Author: Burdge
Publisher: McGraw Hill Custom
Question
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Chapter 3, Problem 3.6QP

(a)

Interpretation Introduction

Interpretation:

Kinetic energy should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force.  The SI unit of energy is joule (J).  Energy is in the form of kinetic energy or potential energyKinetic energy is the energy associated with motion.  Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.

(a)

Expert Solution
Check Mark

Answer to Problem 3.6QP

The kinetic energy of a 25-kg mass moving at 61.3 m/s is 4.7 × 104 J.

Explanation of Solution

To find: Determine the kinetic energy of a 25-kg mass moving at 61.3 m/s

Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where m ‒ mass in kilograms; u – velocity in meters per second.  By considering the given problem, m = 25 kg; u = 61.3 m/s.  Substitute the given values in the formula,

Ek = 12(25 kg)(61.3 m/s)2Ek = 4.7 × 104 kg×m2/s2Ek = 4.7 × 104 J

Therefore, the kinetic energy of a 25-kg mass moving at 61.3 m/s is 4.7 × 104 J

(b)

Interpretation Introduction

Interpretation:

Kinetic energy should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force.  The SI unit of energy is joule (J).  Energy is in the form of kinetic energy or potential energyKinetic energy is the energy associated with motion.  Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.

(b)

Expert Solution
Check Mark

Answer to Problem 3.6QP

The kinetic energy of a tennis ball weighing 58.1 g moving at 66.2 mph is 29.7 J

Explanation of Solution

To find: Determine the kinetic energy of a tennis ball weighing 58.1 g moving at 66.2 mph

Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.  By considering the given problem, m = 58.1 g; u = 66.2 mph.  Hence, ‘m’ in g and ‘u’ in mph should be converted into ‘m’ in kilograms and ‘u’ in meters per second.

The mass of the tennis ball in kilograms is

m = 58.1 g × 1 kg1 × 103 gm = 0.0581 kg

The velocity of the tennis ball in meters per second is

u = 66.2 mi1 h × 1.61 km1 mi × 1 × 103 m1 km × 1 h60 min × 1 min60 su = 29.6 m/s

Substitute the given values in the formula,

Ek = 12(0.0581 kg)(29.6 m/s)2Ek = 25.5 kg×m2/s2Ek = 25.5 J

Therefore, the kinetic energy of a tennis ball weighing 58.1 g moving at 66.2 mph is 25.5 J

(c)

Interpretation Introduction

Interpretation:

Kinetic energy should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force.  The SI unit of energy is joule (J).  Energy is in the form of kinetic energy or potential energyKinetic energy is the energy associated with motion.  Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.

(c)

Expert Solution
Check Mark

Answer to Problem 3.6QP

The kinetic energy of a beryllium atom moving at 275 m/s is 5.66 × 10-22 J

Explanation of Solution

To find: Determine the kinetic energy of a beryllium atom moving at 275 m/s

Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.  By considering the given problem, = 9.102 amu; u = 275 m/s.  Hence, ‘m’ in amu should be converted into ‘m’ in kilograms.

The mass of a beryllium atom in kilograms is

= 9.102 amu × 1.661 × 1024 g1 amu × 1 kg1 × 103 g= 1.4969 × 1026 kg

Substitute the given values in the formula,

Ek = 12(1.4969 × 10-26 kg)(275 m/s)2Ek = 5.66 × 10-22 kg×m2/s2Ek = 5.66 × 10-22 J

Therefore, the kinetic energy of a beryllium atom moving at 275 m/s is 5.66 × 10-22 J

(d)

Interpretation Introduction

Interpretation:

Kinetic energy should be calculated in the given statement by using the equation of kinetic energy

Concept Introduction:

Energy is the capacity to do work or transfer heat where work is the movement of a body using some force.  The SI unit of energy is joule (J).  Energy is in the form of kinetic energy or potential energyKinetic energy is the energy associated with motion.  Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.

(d)

Expert Solution
Check Mark

Answer to Problem 3.6QP

The kinetic energy of a neutron moving at 2.000 × 103 m/s is 3.34 × 10-21 J

Explanation of Solution

To find: Determine the kinetic energy of a neutron moving at 2.000 × 103 m/s (d)

Kinetic energy (in joule) is calculated using the formula:

Ek = 12mu2

Where, m ‒ mass in kilograms; u – velocity in meters per second.  By considering the given problem, = 1.67493×1024 g; u = 2.000 × 103 m/s.  Hence, ‘m’ in g should be converted into ‘m’ in kilograms.

The mass of a neutron in kilograms is

= 1.67493 × 1024 g × 1 kg1 × 103 g= 1.67493 × 1027 kg

Substitute the given values in the formula,

Ek = 12(1.67493 × 10-27 kg)(2.000 × 103 m/s)2Ek = 3.34 × 10-21 kg×m2/s2Ek = 3.34 × 10-21 J

Therefore, the kinetic energy of a neutron moving at 2.000 × 103 m/s is 3.34 × 10-21 J

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Chapter 3 Solutions

Chemistry: Atoms First V1

Ch. 3.1 - Prob. 3.1.3SRCh. 3.2 - One type of laser used in the treatment of...Ch. 3.2 - What is the wavelength (in meters) of an...Ch. 3.2 - What is the frequency (in reciprocal seconds) of...Ch. 3.2 - Which of the following sets of waves best...Ch. 3.2 - Prob. 3.2.1SRCh. 3.2 - Prob. 3.2.2SRCh. 3.2 - Prob. 3.2.3SRCh. 3.2 - Prob. 3.2.4SRCh. 3.3 - Calculate the energy (in joules) of (a) a photon...Ch. 3.3 - Calculate the energy (in joules) of (a) a photon...Ch. 3.3 - (a) Calculate the wavelength (in nanometers) of...Ch. 3.3 - Prob. 3.3.1SRCh. 3.3 - Prob. 3.3.2SRCh. 3.3 - Prob. 3.3.3SRCh. 3.3 - Prob. 3.3.4SRCh. 3.3 - Prob. 3.3.5SRCh. 3.4 - Calculate the wavelength (in nanometers) of the...Ch. 3.4 - What is the wavelength (in nanometers) of a photon...Ch. 3.4 - What is the value of ni for an electron that emits...Ch. 3.4 - For each pair of transitions, determine which one...Ch. 3.4 - Prob. 3.4.1SRCh. 3.4 - Prob. 3.4.2SRCh. 3.4 - Prob. 3.4.3SRCh. 3.4 - Prob. 3.4.4SRCh. 3.5 - Calculate the de Broglie wavelength of the...Ch. 3.5 - Calculate the de Broglie wavelength (in...Ch. 3.5 - Use Equation 3.11 to calculate the momentum, p...Ch. 3.5 - Consider the impact of early electron diffraction...Ch. 3.5 - Prob. 3.5.1SRCh. 3.5 - Prob. 3.5.2SRCh. 3.5 - Prob. 3.5.3SRCh. 3.6 - An electron in a hydrogen atom is known to have a...Ch. 3.6 - Prob. 7PPACh. 3.6 - (a) Calculate the minimum uncertainty in the...Ch. 3.6 - Using Equation 3.13, we can calculate the minimum...Ch. 3.6 - Prob. 3.6.1SRCh. 3.6 - Prob. 3.6.2SRCh. 3.7 - What are the possible values for the magnetic...Ch. 3.7 - Prob. 8PPACh. 3.7 - Prob. 8PPBCh. 3.7 - Prob. 8PPCCh. 3.7 - Prob. 3.7.1SRCh. 3.7 - Prob. 3.7.2SRCh. 3.7 - Prob. 3.7.3SRCh. 3.7 - Prob. 3.7.4SRCh. 3.8 - Prob. 3.9WECh. 3.8 - Prob. 9PPACh. 3.8 - Prob. 9PPBCh. 3.8 - Prob. 9PPCCh. 3.8 - Prob. 3.8.1SRCh. 3.8 - Prob. 3.8.2SRCh. 3.8 - Prob. 3.8.3SRCh. 3.8 - Prob. 3.8.4SRCh. 3.9 - Write the electron configuration and give the...Ch. 3.9 - Prob. 10PPACh. 3.9 - Write the electron configuration and give the...Ch. 3.9 - Prob. 10PPCCh. 3.9 - Prob. 3.9.1SRCh. 3.9 - Prob. 3.9.2SRCh. 3.9 - Prob. 3.9.3SRCh. 3.10 - Without referring to Figure 3.26, write the...Ch. 3.10 - Prob. 11PPACh. 3.10 - Prob. 11PPBCh. 3.10 - Consider again the alternate universe and its...Ch. 3.10 - Prob. 3.10.1SRCh. 3.10 - Prob. 3.10.2SRCh. 3.10 - Prob. 3.10.3SRCh. 3.10 - Prob. 3.10.4SRCh. 3 - Define these terms: potential energy, kinetic...Ch. 3 - What are the units for energy commonly employed in...Ch. 3 - A truck initially traveling at 60 km/h is brought...Ch. 3 - Describe the interconversions of forms of energy...Ch. 3 - Prob. 3.5QPCh. 3 - Prob. 3.6QPCh. 3 - Prob. 3.7QPCh. 3 - Prob. 3.8QPCh. 3 - Prob. 3.9QPCh. 3 - (a) How much greater is the electrostatic energy...Ch. 3 - Prob. 3.11QPCh. 3 - Prob. 3.12QPCh. 3 - List the types of electromagnetic radiation,...Ch. 3 - Prob. 3.14QPCh. 3 - Prob. 3.15QPCh. 3 - Prob. 3.16QPCh. 3 - The SI unit of time is the second, which is...Ch. 3 - Prob. 3.18QPCh. 3 - Prob. 3.19QPCh. 3 - Four waves represent light in four different...Ch. 3 - Prob. 3.21QPCh. 3 - Prob. 3.22QPCh. 3 - Prob. 3.23QPCh. 3 - What is a photon? What role did Einsteins...Ch. 3 - A photon has a wavelength of 705 nm. Calculate the...Ch. 3 - The blue color of the sky results from the...Ch. 3 - A photon has a frequency of 6.5 109 Hz. (a)...Ch. 3 - Prob. 3.28QPCh. 3 - Prob. 3.29QPCh. 3 - Prob. 3.30QPCh. 3 - Prob. 3.31QPCh. 3 - A particular form of electromagnetic radiation has...Ch. 3 - Photosynthesis makes use of visible light to bring...Ch. 3 - The retina of a human eye can detect light when...Ch. 3 - Prob. 3.35QPCh. 3 - The binding energy of magnesium metal is 5.86 ...Ch. 3 - What is the kinetic energy of the ejected electron...Ch. 3 - A red light was shined onto a metal sample and the...Ch. 3 - A photoelectric experiment was performed by...Ch. 3 - Which of the following best explains why we see...Ch. 3 - One way to see the emission spectrum of hydrogen...Ch. 3 - How many lines would we see in the emission...Ch. 3 - For a hydrogen atom in which the electron has been...Ch. 3 - Prob. 3.40QPCh. 3 - Prob. 3.41QPCh. 3 - Briefly describe Bohrs theory of the hydrogen atom...Ch. 3 - Explain the meaning of the negative sign in...Ch. 3 - Consider the following energy levels of a...Ch. 3 - Prob. 3.45QPCh. 3 - Calculate the wavelength (in nanometers) of a...Ch. 3 - Calculate the frequency (hertz) and wavelength...Ch. 3 - What wavelength of light is needed to excite the...Ch. 3 - An electron in the hydrogen atom makes a...Ch. 3 - Explain why elements produce their own...Ch. 3 - Some copper-containing substances emit green light...Ch. 3 - Prob. 3.52QPCh. 3 - Prob. 3.53QPCh. 3 - Prob. 3.54QPCh. 3 - Why is Equation 3.11 meaningful only for...Ch. 3 - Prob. 3.56QPCh. 3 - Thermal neutrons are neutrons that move at speeds...Ch. 3 - Protons can be accelerated to speeds near that of...Ch. 3 - Prob. 3.59QPCh. 3 - Prob. 3.60QPCh. 3 - Prob. 3.61QPCh. 3 - Prob. 3.62QPCh. 3 - What are the inadequacies of Bohrs theory?Ch. 3 - What is the Heisenberg uncertainty principle? 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(a) Calculate the binding...Ch. 3 - Scientists have found interstellar hydrogen atoms...Ch. 3 - Ionization energy is the minimum energy required...Ch. 3 - Prob. 3.143QPCh. 3 - Prob. 3.144QPCh. 3 - The cone cells of the human eye are sensitive to...Ch. 3 - (a) An electron in the ground state of the...Ch. 3 - Prob. 3.147QPCh. 3 - Prob. 3.148QPCh. 3 - When an election makes a transition between energy...Ch. 3 - Blackbody radiation is the term used to describe...Ch. 3 - Suppose that photons of red light (675 nm) are...Ch. 3 - In an election microscope, electrons are...Ch. 3 - According to Einsteins special theory of...Ch. 3 - The mathematical equation for studying the...
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