Concept explainers
3.64 How many grams of solute are present in each of these
solutions?
(a) 37.2 mL ofO.471 M HBr
(b) 113.0 L of 1.43 M Na2CO3
(c) 212 mL of 6.8 M CH3COOH
(d) 1.3 × 10-4 L of 1.03 M H2S03
(a)
To determine:
The mass in grams of solute for 37.2 mL of 0.471 M
Explanation of Solution
Molar mass of
Molarity is defined as the number of moles of solute (
The solution is 0.471 M, i.e. it contains 0.471 moles of
per 1000 mL solution. Thus, for 37.2 mL solution, the number of moles would be:
Now, number of moles is given by:
(b)
To determine:
The mass in grams of solute for 113.0 L of 1.43 M
Explanation of Solution
Molar mass of
Molarity is defined as the number of moles of solute (
The solution is 1.43 M, i.e. it contains 1.43 moles of
per 1 L solution. Thus, for 113.0 L solution, the number of moles would be:
Now, number of moles is given by:
(c)
To determine:
The mass in grams of solute for 21.2mL of 6.8 M
Explanation of Solution
Molar mass of
Molarity is defined as the number of moles of solute (
The solution is 6.8 M, i.e. it contains 6.8 moles of
per 1000mL solution. Thus, for 21.2mL solution, the number of moles would be:
Now, number of moles is given by:
(d)
To determine:
The mass in grams of solute for
Explanation of Solution
Molar mass of
Molarity is defined as the number of moles of solute (
The solution is 1.03 M, i.e. it contains 1.03 moles of
solution, the number of moles would be:
Now, number of moles is given by:
Therefore, knowing the molarity of a given solution, the number of moles can be calculated. Using the molar mass, the mass of the solute present in the solution can be calculated.
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Chapter 3 Solutions
CHEM FOR ENGNRNG SDNTS (EBOOK) W/ACCES
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