Connect 1 Semester Access Card for General Chemistry: The Essential Concepts
Connect 1 Semester Access Card for General Chemistry: The Essential Concepts
7th Edition
ISBN: 9781259692543
Author: Raymond Chang Dr.; Kenneth Goldsby Professor
Publisher: McGraw-Hill Education
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Chapter 3, Problem 3.60QP

(a)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(a)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (a) is 2N2O52N2O4+O2

Explanation of Solution

To write balanced equation for N2O5N2O4+O2

  • List the atoms of given equation and the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
2N2
5O6
  • Place 1/2 on O2 on the right hand side

N2O5N2O4+12O2

Reactant sideAtomProduct side
2N2
5O5
  • To make whole number multiply by two on both sides

2N2O52N2O4+O2

Reactant sideAtomProduct side
4N4
10O10

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as 2N2O52N2O4+O2

(b)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(b)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (b) is 2KNO3+2KNO2+O2

Explanation of Solution

To write balanced equation for KNO3+KNO2+O2

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1K1
1N1
3O4
  • To tally the oxygen atom on both sides, place 1/2 for oxygen on right hand side and again balance the equation.

KNO3+KNO2+12O2

Reactant sideAtomProduct side
1K1
1N1
3O3
  • To give the equation in simple whole number coefficients, multiply both sides by two.

2KNO3+2KNO2+O2

Reactant sideAtomProduct side
2K2
2N2
6O6

Now, the atom count on both sides of the reaction is same, hence the equation is balanced. The balanced equation is written as 2KNO3+2KNO2+O2

(c)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(c)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (c) is NH4NO3N2O+2H2O

Explanation of Solution

To write balanced equation for NH4NO3N2O+H2O

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
2N2
4H2
3O2
  • Multiply two on water on the right hand side of the equaiton

NH4NO3N2O+2H2O

Reactant sideAtomProduct side
2N2
4H4
3O3

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as NH4NO3N2O+2H2O

(d)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(d)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (d) is NH4NO2+N2+2H2O

Explanation of Solution

To write balanced equation for NH4NO2+N2+H2O

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
2N2
2O1
4H2
  • Multiply water by two on right hand side of the equation.

NH4NO2+N2+2H2O

Reactant sideAtomProduct side
2N2
2O2
4H4

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as NH4NO2+N2+2H2O

(e)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(e)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (e) is 2NaHCO3Na2CO3+H2O+CO2

Explanation of Solution

To write balanced equation for NaHCO3Na2CO3+H2O+CO2

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1Na2
1H2
1C2
3O6
  • Multiply by two on left hand side

2NaHCO3Na2CO3+H2O+CO2

Reactant sideAtomProduct side
2Na2
2H2
2C2
6O6

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as 2NaHCO3Na2CO3+H2O+CO2

(f)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(f)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (f) is P4O106H2O+4H3PO4

Explanation of Solution

To write balanced equation for P4O10H2O+H3PO4

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
4P1
11O4
2H3
  • To balance phosphorus place four on phosphoric acid

P4O10H2O+4H3PO4

Reactant sideAtomProduct side
4P1
11O16
2H12
  • Place six on water to balance the equation further.

    P4O106H2O+4H3PO4

Reactant sideAtomProduct side
4P4
16O16
12H12

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as P4O106H2O+4H3PO4

(g)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(g)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (g) is 2HCl+CaCO3CaCl2+H2O+CO2

Explanation of Solution

To write balanced equation for HCl+CaCO3CaCl2+H2O+CO2

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1Ca1
1Cl2
1C1
3O3
1H2
  • Multiply hydrogen chloride by two on reactant side.

2HCl+CaCO3CaCl2+H2O+CO2

Reactant sideAtomProduct side
1Ca1
2Cl2
1C1
3O3
2H2

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as 2HCl+CaCO3CaCl2+H2O+CO2

(h)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(h)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (h) is 2Al+3H2SO4Al2(SO4)3+3H2

Explanation of Solution

To write balanced equation for Al+H2SO4Al2(SO4)3+H2

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1Al2
1SO43
2H2
  • To tally the Aluminium atom, multiply two on left hand side.

2Al+H2SO4Al2(SO4)3+H2

Reactant sideAtomProduct side
2Al2
1SO43
2H2
  • To balance the SO4 units, mulitply sulphuric acid by three on reactant side

    2Al+3H2SO4Al2(SO4)3+H2

Reactant sideAtomProduct side
2Al2
3SO43
6H2
  • To balance finally, multiply hydrogen by three on product side.

2Al+3H2SO4Al2(SO4)3+3H2

Reactant sideAtomProduct side
2Al2
3SO43
6H6

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as 2Al+3H2SO4Al2(SO4)3+3H2

(i)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(i)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (i) is CO2+2KOHK2CO3+H2O

Explanation of Solution

To write balanced equation for CO2+KOHK2CO3+H2O

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1K2
3O4
1C1
1H2
  • To tally the Potassium and hydrogen atom, multiply potassium hydroxide by two on left hand side.

CO2+2KOHK2CO3+H2O

Reactant sideAtomProduct side
2K2
3O3
1C1
2H2

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as CO2+2KOHK2CO3+H2O

(j)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(j)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (j) is CH4+2O2CO2+2H2O

Explanation of Solution

To write balanced equation for CH4+O2CO2+H2O

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1C1
2O3
4H2
  • Multiply water by two on right hand side

CH4+O2CO2+2H2O

Reactant sideAtomProduct side
1C1
2O4
4H4
  • Multiply oxygen atom by two on reactant side

CH4+2O2CO2+2H2O

Reactant sideAtomProduct side
1C1
4O4
4H4

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as CH4+2O2CO2+2H2O

(k)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(k)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (k) is Be2C+4H2O2Be(OH)2+CH4

Explanation of Solution

To write balanced equation for Be2C+H2OBe(OH)2+CH4

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
2Be1
1C1
2H4
1O2
  • To balance Be, place two on Be(OH)2 on right hand side

Be2C+H2O2Be(OH)2+CH4

Reactant sideAtomProduct side
2Be2
1C1
2H8
1O4
  • Place four on water on the left hand side

    Be2C+4H2O2Be(OH)2+CH4

Reactant sideAtomProduct side
2Be2
1C1
8H8
4O4

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as Be2C+4H2O2Be(OH)2+CH4

(l)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(l)

Expert Solution
Check Mark

Answer to Problem 3.60QP

Explanation of Solution

To write balanced equation for Cu+HNO3Cu(NO3)2+NO+H2O

  • The charge on copper and on nitrogen is not same on both the sides. This equation can be balanced by redox method.
  • Find out and write the redox couples of the reaction. write down it as half reactions.

Oxidation: Cu0Cu(2+)(NO3)2+2e-

Reduction: HN(5+)O3+3eN(2+)O

  • Balance all the atoms on both sides except oxygen and hydrogen.

Oxidation: Cu0+2HNO3Cu(2+)(NO3)2+2e-

Reduction: HN(5+)O3+3eN(2+)O

  • Balance the charge on both the reactions by adding H+

Oxidation: Cu0+2HNO3Cu(2+)(NO3)2+2e-+2H+

Reduction: HN(5+)O3+3e+3H+N(2+)O

  • Balance the oxygen atoms by adding water molecules.

Oxidation: Cu0+2HNO3Cu(2+)(NO3)2+2e-+2H+

Reduction: HN(5+)O3+3e+3H+N(2+)O+2H2O

  • Electron gain must be equivalent to electron lost. This is done by multiplying the coefficients by integers giving lowest common multiple for all the species.

Oxidation: 3Cu0+6HNO33Cu(2+)(NO3)2+6e-+6H+

Reduction: 2HN(5+)O3+6e+6H+2N(2+)O+4H2O

  • Half reactions are added together and the equation is simplified to get the final balanced equation.

3Cu0+8HNO3+6e-+6H+3Cu(2+)(NO3)2+2NO+4H2O+6e-+6H+

  • On simplification,

3Cu+8HNO33Cu(NO3)2+2NO+4H2O

Reactant sideAtomProduct side
3C3
8H8
8N8
24O24

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as 3Cu+8HNO33Cu(NO3)2+2NO+4H2O

(m)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(m)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (m) is S+6HNO3H2SO4+6NO2+2H2O

Explanation of Solution

To write balanced equation for S+HNO3H2SO4+NO2+H2O

  • The charge on copper and on nitrogen is not same on both the sides. This equation can be balanced by redox method.
  • Find out and write the redox couples of the reaction. write down it as half reactions.

Oxidation: S0H2S(6+)O4+6e-

Reduction: HN(5+)O3+eN(4+)O2

  • Balance all the atoms on both sides except oxygen and hydrogen.

    Oxidation: S0H2S(6+)O4+6e-

    Reduction: HN(5+)O3+eN(4+)O2

  • Balance the charge on both the reactions by adding H+

    Oxidation: S0H2S(6+)O4+6e-+6H+

    Reduction: HN(5+)O3+e+H+N(4+)O2

  • Balance the oxygen atoms by adding water molecules.

    Oxidation: S0+4H2OH2S(6+)O4+6e-+6H+

    Reduction: HN(5+)O3+e+H+N(4+)O2+H2O

  • Electron gain must be equivalent to electron lost. This is done by multiplying the coefficients by integers giving lowest common multiple for all the species.

    Oxidation: S0+4H2OH2S(6+)O4+6e-+6H+

    Reduction: HN(5+)O3+e+H+N(4+)O2+H2O

  • Half reactions are added together and the equation is simplified to get the final balanced equation.

S0+6HN(5+)O3+4H2O+6e-+6H+H2S(6+)O4+6N(4+)O2+6H2O+6e-+6H+

  • On simplification,

S+6HNO3H2SO4+6NO2+2H2O

Reactant sideAtomProduct side
1S1
6H6
6N6
18O18

Now, the atom count on both sides of the reaction are same, hence the equation is balanced. The balanced equation is written as S+6HNO3H2SO4+6NO2+2H2O

(n)

Interpretation Introduction

Interpretation: The given set chemical equations has to be balanced

Concept Introduction:

  • Chemical equation is the symbolic representation of a chemical reaction using the symbols of elements. Chemical equation must be balanced on both sides (reactant side and product side) of the reaction. A balanced equation alone obeys the "Law of conservation of mass"
  • Balancing a chemical equation is based on "trial-and-error" method.
  • For each step during balancing of chemical equation, the atoms involved in reaction are listed out. Then the number of atoms on both sides of the reaction (reactant side and product side) is checked for tally.
  • Suitable numerals are placed as coefficients before the element or compound on either side of reaction wherever necessary.
  • Placing of coefficients are allowed for balancing equation, whereas changing the subscripts of elements or compounds are not allowed.
  • Always place coefficients for compounds first rather than placing it for elements.
  • Polyatomic ions can be treated as single unit on both sides rather than considering their constituents individually.
  • While balancing the equation, the numerals used must be simple whole number.
  • Balancing the equation can be done by redox method too. This is done by balancing the oxidation number of the atoms involved in equation.

To write: The balanced chemical equation for the given set of reactions

(n)

Expert Solution
Check Mark

Answer to Problem 3.60QP

The balanced chemical equation for (n) is 2NH3+3CuO3Cu+N2+3H2O

Explanation of Solution

To write balanced equation for NH3+CuOCu+N2+H2O

  • List the atoms of given equation and also the number of each atoms present on both sides of the reaction. Check for the number of atoms available on both sides
Reactant sideAtomProduct side
1N2
1Cu1
1O1
3H2
  • Multiply ammonia by two on the reactant side

2NH3+CuOCu+N2+H2O

Reactant sideAtomProduct side
2N2
1Cu1
1O1
6H2
  • To balance hydrogen, place three on water

    2NH3+CuOCu+N2+3H2O

Reactant sideAtomProduct side
2N2
1Cu1
1O3
6H6
  • Finally place three on CuO  and on copper to balance on both the sides.

    2NH3+3CuO3Cu+N2+3H2O

Reactant sideAtomProduct side
2N2
3Cu3
3O3
6H6

Now, the atom count on both sides of the reaction is same, hence the equation is balanced. The balanced equation is written as 2NH3+3CuO3Cu+N2+3H2O

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Chapter 3 Solutions

Connect 1 Semester Access Card for General Chemistry: The Essential Concepts

Ch. 3.4 - Review of Concepts Explain how the mass...Ch. 3.5 - Practice Exercise Calculate the percent...Ch. 3.5 - Prob. 2PECh. 3.5 - Practice Exercise Calculate the number of grams of...Ch. 3.5 - Prob. 1RCCh. 3.6 - Practice Exercise A sample of a compound...Ch. 3.6 - Prob. 1RCCh. 3.7 - Prob. 1PECh. 3.7 - Prob. 1RCCh. 3.8 - Prob. 1PECh. 3.8 - Prob. 2PECh. 3.8 - Prob. 1RCCh. 3.9 - Prob. 1PECh. 3.9 - Consider the following reaction: Starting with...Ch. 3.10 - Prob. 1PECh. 3.10 - Can the percent yield ever exceed the theoretical...Ch. 3 - Prob. 3.1QPCh. 3 - Prob. 3.2QPCh. 3 - Prob. 3.3QPCh. 3 - Prob. 3.4QPCh. 3 - Prob. 3.5QPCh. 3 - 3.6 The atomic masses of and are 6.0151 amu and...Ch. 3 - Prob. 3.7QPCh. 3 - Prob. 3.8QPCh. 3 - Prob. 3.9QPCh. 3 - 3.10 What is the molar mass of an atom? What are...Ch. 3 - Prob. 3.11QPCh. 3 - Prob. 3.12QPCh. 3 - Prob. 3.13QPCh. 3 - Prob. 3.14QPCh. 3 - Prob. 3.15QPCh. 3 - Prob. 3.16QPCh. 3 - 3.17 What is the mass in grams of a single atom of...Ch. 3 - Prob. 3.18QPCh. 3 - Prob. 3.19QPCh. 3 - Prob. 3.20QPCh. 3 - Prob. 3.21QPCh. 3 - Prob. 3.22QPCh. 3 - Prob. 3.23QPCh. 3 - Prob. 3.24QPCh. 3 - Prob. 3.25QPCh. 3 - Prob. 3.26QPCh. 3 - Prob. 3.27QPCh. 3 - Prob. 3.28QPCh. 3 - Prob. 3.29QPCh. 3 - Prob. 3.30QPCh. 3 - Prob. 3.31QPCh. 3 - Prob. 3.32QPCh. 3 - Prob. 3.33QPCh. 3 - Prob. 3.34QPCh. 3 - Prob. 3.35QPCh. 3 - Prob. 3.36QPCh. 3 - Prob. 3.37QPCh. 3 - Prob. 3.38QPCh. 3 - Prob. 3.39QPCh. 3 - Prob. 3.40QPCh. 3 - Prob. 3.41QPCh. 3 - Prob. 3.42QPCh. 3 - Prob. 3.43QPCh. 3 - 3.44 Peroxyacylnitrate (PAN) is one of the...Ch. 3 - Prob. 3.45QPCh. 3 - Prob. 3.46QPCh. 3 - Prob. 3.47QPCh. 3 - Prob. 3.48QPCh. 3 - Prob. 3.49QPCh. 3 - Prob. 3.50QPCh. 3 - Prob. 3.51QPCh. 3 - 3.52 The empirical formula of a compound is CH. If...Ch. 3 - Prob. 3.53QPCh. 3 - Prob. 3.54QPCh. 3 - Prob. 3.55QPCh. 3 - Prob. 3.56QPCh. 3 - Prob. 3.57QPCh. 3 - Prob. 3.58QPCh. 3 - Prob. 3.59QPCh. 3 - Prob. 3.60QPCh. 3 - Prob. 3.61QPCh. 3 - Prob. 3.62QPCh. 3 - Prob. 3.63QPCh. 3 - 3.64 Which of the following equations best...Ch. 3 - Prob. 3.65QPCh. 3 - Prob. 3.66QPCh. 3 - Prob. 3.67QPCh. 3 - Prob. 3.68QPCh. 3 - Prob. 3.69QPCh. 3 - Prob. 3.70QPCh. 3 - Prob. 3.71QPCh. 3 - Prob. 3.72QPCh. 3 - Prob. 3.73QPCh. 3 - Prob. 3.74QPCh. 3 - 3.75 Limestone (CaCO3) is decomposed by heating to...Ch. 3 - Prob. 3.76QPCh. 3 - Prob. 3.77QPCh. 3 - Prob. 3.78QPCh. 3 - 3.79 Define limiting reagent and excess reagent....Ch. 3 - Prob. 3.80QPCh. 3 - Prob. 3.81QPCh. 3 - Prob. 3.82QPCh. 3 - Prob. 3.83QPCh. 3 - Prob. 3.84QPCh. 3 - Prob. 3.85QPCh. 3 - Prob. 3.86QPCh. 3 - Prob. 3.87QPCh. 3 - Prob. 3.88QPCh. 3 - Prob. 3.89QPCh. 3 - Prob. 3.90QPCh. 3 - Prob. 3.91QPCh. 3 - Prob. 3.92QPCh. 3 - Prob. 3.93QPCh. 3 - Prob. 3.94QPCh. 3 - Prob. 3.95QPCh. 3 - Prob. 3.96QPCh. 3 - Prob. 3.97QPCh. 3 - Prob. 3.98QPCh. 3 - Prob. 3.99QPCh. 3 - Prob. 3.100QPCh. 3 - Prob. 3.101QPCh. 3 - Prob. 3.102QPCh. 3 - Prob. 3.103QPCh. 3 - Prob. 3.104QPCh. 3 - Prob. 3.105QPCh. 3 - Prob. 3.106QPCh. 3 - Prob. 3.107QPCh. 3 - Prob. 3.108QPCh. 3 - Prob. 3.110QPCh. 3 - Prob. 3.111QPCh. 3 - Prob. 3.112QPCh. 3 - Prob. 3.113QPCh. 3 - 3.114 In the total synthesis of a natural product,...Ch. 3 - Prob. 3.115QPCh. 3 - Prob. 3.116SPCh. 3 - Prob. 3.117SPCh. 3 - 3.118 A certain metal M forms a bromide containing...Ch. 3 - Prob. 3.119SPCh. 3 - Prob. 3.120SP
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