Formulation of Linear Programming (LP):

Let “x₁” be the type 1 layout, “x₂” be type 1 layout, and “x₃” be type 3 layout.

The objective is to maximize the profit.

$z=[(net profit)(type 1 layout)+(net profit)(type 2 layout)+(net profit)(type 3 layout)]=50x1+30x2+60x3$

Therefore, the objective function is,

Maximize, $z=50x1+30x2+60x3$

Constraint 1:

At most, 1000 tulips are available.

$[(tulips used)(type 1 layout)+(tulips used)(type 2 layout)+(tulips used)(type 3 layout)]≤100030x1+10x2+20x3≤1000$

Constraint 2:

At most, 800 daffodils are available

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Chapter 3, Problem 34RP

Chapter 3, Problem 36RP

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Chapter 3 Solutions

Introduction to mathematical programming

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Solution Summary: The author explains the objective function of Linear Programming, which is to maximize the profit.

Explanation of Solution

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Chapter 3 Solutions