(1-a)
Interpretation:
The number of candy pieces in
Concept introduction:
Mole:
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(1-a)
Answer to Problem 3.17QP
Number of candy pieces in
Explanation of Solution
To calculate the number of candy pieces in
Given,
From the above mole concept, 1 mole of elemental sample contains
Number of candy pieces in
Give weight of candy and number of candies present in per kg are plugged in above equation to give number of candy pieces in
Number of candy pieces in
The number of candy pieces in
(1-b)
Interpretation:
The mass of 10 dozen candies should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(1-b)
Answer to Problem 3.17QP
The mass of 10 dozen candies is
Explanation of Solution
To calculate the mass of 10 dozen candies.
Given,
From the above mole concept, 1 mole of elemental sample contains
The mass of 10 dozen candies is,
1 dozen contains 12 pieces means 10 dozen contains 120 candy pieces.
The number of candies present in per dozen and number of candies present in
The mass of 10 dozen candies
The mass of 10 dozen candies was calculated.
(1-c)
Interpretation:
The mass of 1 candy piece should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(1-c)
Answer to Problem 3.17QP
The mass of 1 candy piece is
Explanation of Solution
To calculate the mass of 1 candy piece.
Given,
From the above mole concept, 1 mole of elemental sample contains
The mass of 1 candy piece is,
Number of candies present in
The mass of 1 candy piece is
The mass of 1 candy piece was calculated.
(1-d)
Interpretation:
The mass of 2.0 moles of candy should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(1-d)
Answer to Problem 3.17QP
The mass of 2.0 mole candy is
Explanation of Solution
To calculate the mass of 2.0 moles of candies.
Given,
From the above mole concept, 1 mole of elemental sample contains
1 mole of candy contains
The mass of 1 mole candy is,
Number of candies present in
The mass of 2.0 mole candy is
The mass of 2.0 moles of candies were calculated.
(2-a)
Interpretation:
The number of Helium atoms present in
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(2-a)
Answer to Problem 3.17QP
The number of Helium atoms present in
Explanation of Solution
To calculate the number of Helium atoms present in
Given,
Molar mass of Helium is
From the above mole concept, 1 mole of elemental sample contains
The number of Helium atoms present in
Molar mass of Helium and given weight of Helium sample are plugged in above equation to give the number of Helium atoms present in
The number of Helium atoms present in
The number of Helium atoms present in
(2-b)
Interpretation:
The mass of 10 dozen Helium atoms should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(2-b)
Answer to Problem 3.17QP
The mass of 10 dozen Helium atoms is
Explanation of Solution
To calculate the mass of 10 dozen Helium atoms
Given,
Molar mass of Helium is
From the above mole concept, 1 mole of elemental sample contains
1 dozen contains 12 numbers so 10 dozen contains 120 number of Helium atoms.
The mass of 10 dozen Helium atoms is,
Molar mass of Helium and number of atoms that are present in 10 dozen are plugged in above equation to give mass of 10 dozen Helium atoms.
The mass of 10 dozen Helium atoms is
The mass of 10 dozen Helium atoms calculated.
(2-c)
Interpretation:
The mass of one Helium atom should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(2-c)
Answer to Problem 3.17QP
The mass of one Helium atom is
Explanation of Solution
To calculate the mass of one Helium atom.
Given,
Molar mass of Helium is
From the above mole concept, 1 mole of elemental sample contains
The mass of one Helium atom is,
Molar mass of Helium and is plugged in above equation to give the mass of one Helium atom.
The mass of one Helium atom is
The mass of one Helium atom was calculated.
(2-d)
Interpretation:
The mass of 2.0 mole of Helium should be calculated.
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
(2-d)
Answer to Problem 3.17QP
The mass of 2.0 mole Helium is
Explanation of Solution
To calculate the mass of 2.0 mole Helium.
Given,
Molar mass of Helium is
From the above mole concept, 1 mole of elemental sample contains
The mass of 2.0 mole Helium is,
Molar mass of Helium and is plugged in above equation to give the mass of 2.0 mole Helium.
The mass of 2.0 mole Helium is
The mass of 2.0 mole of Helium was calculated.
(3-a)
Interpretation:
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
Binkles:
(3-a)
Answer to Problem 3.17QP
The masses of nails and Helium atom are different so the
Explanation of Solution
To explain the binkles of
Given,
Molar mass of Helium is
One binkle has
The masses of nails and Helium atom are different so the
Binkles of
(3-b)
Interpretation:
The higher mass containing option should be given from the
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
Binkles:
The
(3-b)
Answer to Problem 3.17QP
The masses of
Explanation of Solution
To explain the mass of
Given,
Molar mass of Helium is
One binkle has
The masses of
The higher mass containing option should be given from
(3-c)
Interpretation:
The more number of atom containing option should be given from
Concept introduction:
Mole:
Number of atoms present in gram atomic mass of element is known as Avogadro number.
Avogadro number is
One mole equal of atom equal to Avogadro number
The mole of taken gram mass of compound is given by ratio between taken mass of compound to molar mass of compound.
Binkles:
The
(3-c)
Answer to Problem 3.17QP
The masses of
Explanation of Solution
To explain the mass of
Given,
Molar mass of Helium is
Molar mass of Lithium is
One binkle has
The masses of
The more number of atom containing option was given from
Want to see more full solutions like this?
Chapter 3 Solutions
General Chemistry - Standalone book (MindTap Course List)
- Consider the following diagram, where atom X is represented by a square and atom Y is represented by a circle. (a) Write the equation for the reaction represented by the diagram. (b) If each circle stands for a mole of Y and each square a mole of X, how many moles of X did one start with? How many moles of Y? (c) Using the same representation described in part (b), how many moles of product are formed? How many moles of X and Y are left unreacted?arrow_forwardCalculate the molarity of solutions prepared by dilution or calculate the quantities needed to carry out a dilution to prepare a solution of a specified concentration.arrow_forwardWhat does it mean to say an equation is balanced? Why is it important for an equation to be balanced?arrow_forward
- 3.98 The characteristic odor of decaying flesh is due to the presence of various nitrogen-containing compounds. One such compound, called putrescine, was analyzed and found to contain 54.49% carbon, 13.72% hydrogen, and 31.78% nitrogen by mass. If the molar mass of putrescine is known to be between 85 and 105, what is its molecular formula?arrow_forwardThe “Chemistry in Focus” segment The Beetle That Shoots Straight discusses the bombardier beetle and the chemical reaction of the decomposition of hydrogen peroxide. m:math>H2O2(aq)H2O(l)+O2(g) e balanced equation given in the segment is m:math>2H2O2(aq)2H2O(l)+O2(g) y can’t we balance the equation in the following way? m:math>H2O2(aq)H2(g)+O2(g) e molecular-level pictures like those in Section 6.3 to support your answer.arrow_forwarderhaps the most important concept in introductory chemistry concerns what a mole of a substance represents. The mole concept will come up again and again in later chapters in this book. What does one mole of a substance represent on a microscopic, atomic basis? What does one mole of a substance represent on a macroscopic, mass basis? Why have chemists defined the mole in this manner?arrow_forward
- General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning