GENETIC ANALYSIS: INTEGRATED - ACCESS
3rd Edition
ISBN: 9780135349298
Author: Sanders
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 3, Problem 26P
In humans, SRY is located near a pseudoautosomal region (PAR) of the Y chromosome, a region of homology between the X and Y chromosomes that allows them to synapse during meiosis in males and is a region of crossover between the chromosomes. The diagram below shows SRY in relation to the pseudoautosomal region.
About 1 in every 25,000 newborn infants is born with sex reversal; the infant is either an apparent male, but with two X chromosomes, or an apparent female, but with an X and a Y chromosome. Explain the origin of sex reversalin human males and females involving the SRY gene. (Hint: See Experimental Insight 3.1 for a clue about the mutational mechanism.)
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A male Drosophila melanogaster has the genotype A/a; B/b; C/c; XD/Y (all genes are on separate chromosomes). How many different sperm genotypes can it produce through meiosis of one single pre-gametic (2n) cell? (remember, there is no crossing over in male Drosophila)
Explain.
Female flies with white eyes and miniature wings (both X-linkedrecessive traits) were crossed to male flies with red eyes and longwings. On rare occasions, female offspring were produced withwhite eyes. If we assume these females are due to errors in meiosis, what would be the most likely chromosomal composition ofsuch flies? What would be their wing length?
Kuliev and Verlinsky (2004) state that there was a relatively high number of separation errors at meiosis I. In these cases the centromere underwent a premature division, occurring at meiosis I rather than meiosis II. Regarding chromosome 21, what would you expect to be the chromosome 21 complement in the secondary oocyte in which you saw a single chromatid (monad) for chromosome 21 in the first polar body? If this secondary oocyte was involved in fertilization, what would be the expected consequences?
Chapter 3 Solutions
GENETIC ANALYSIS: INTEGRATED - ACCESS
Ch. 3 - Examine the following diagrams of cells from an...Ch. 3 - Our closest primate relative, the chimpanzee, has...Ch. 3 -
3. In a test of his chromosome theory of...Ch. 3 - Cohesion between sister chromatids, as well as...Ch. 3 - 5. The diploid number of the hypothetical animal...Ch. 3 - 6. An organism has alleles R1 and R2 on one pair...Ch. 3 - Explain how the behavior of homologous chromosomes...Ch. 3 - 8. Suppose crossover occurs between the homologous...Ch. 3 -
9. Alleles A and a are on one pair of autosomes,...Ch. 3 - Prob. 10P
Ch. 3 - Describe the role of the following structures or...Ch. 3 - A womans father has ornithine transcarbamylase...Ch. 3 - In humans, hemophilia A (OMIM 306700) is an...Ch. 3 -
14. A wild-type male and a wild-type female...Ch. 3 - 15. A woman with severe discoloration of her tooth...Ch. 3 - 16. In a large metropolitan hospital, cells from...Ch. 3 - In cats, tortoiseshell coat color appears in...Ch. 3 - 18. The gene causing Coffin–Lowry syndrome (OMIM...Ch. 3 - 19. Four eye-color mutants in Drosophila—apricot,...Ch. 3 - 20. For each pedigree shown,
a. Identify which...Ch. 3 - 21. Use the blank pedigrees provided to depict...Ch. 3 - 22. Figure 3.22 (page 89) illustrates reciprocal...Ch. 3 - 23. In fruit flies, yellow body (y) is recessive...Ch. 3 - 24. In a species of fish, a black spot on the...Ch. 3 - LeschNyhan syndrome (OMIM 300322) is a rare...Ch. 3 - 26. In humans, SRY is located near a...Ch. 3 - 27. In an 1889 book titled Natural Inheritance...Ch. 3 - 28. In Drosophila, the X-linked echinus eye...Ch. 3 - 29. A wild-type Drosophila male and female are...Ch. 3 - 30. Drosophila has a diploid chromosome number of...Ch. 3 - The cell cycle operates in the same way in all...Ch. 3 - 33. Form a small discussion group and decide on...Ch. 3 - 34. Duchenne muscular dystrophy (DMD; OMIM 310200)...Ch. 3 - Prob. 35P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Assume that a meiotic-nondisjunction event causes trisomy 8 in a newborn. If two of the three copies of chromosome 8 are absolutely identical, at what point during meiosis did the nondisjunction event take place?arrow_forwardBarr bodies are formed to adjust X chromosome dosage in species other than humans, such as Drosophila (fruit flies) and C. elegans (nematodes). True or False ?arrow_forwardA diploid individual is heterozygous for a chromosome rearrangement. The original chromosome and its rearranged homolog have the following segments, where ∙ represents a centromere: A B ∙ C D E F G A B ∙ C F E D G While paired in prophase I, a single crossing-over occurs between segment E and segment D of the paired chromosomes. Describe the unusual crossing-over structure that forms as a result.What gamete types will result from crossing over when meiosis is complete? please asaparrow_forward
- The STR DNA marker DS11 is located on the p arm of the chromosome #8 in humans. Molecular analysis has shown that Charlie Chaplin is a heterozygote for the STR marker (genotype DS11A and DS11B) Using this knowledge, provide a diagram of meiosis showing only the movements of chromosome 8 (assume no nondisjunction). Throughout, indicate where the marker may be found (in other words, label the chromosome to show where the STR markers can be found. (Show ONLY the chromosomes at interphase, metaphase 1, end of meiosis 1, metaphase 2, and end of meiosis 2). Suppose Charlie conceived a son with a chromosome 8 trisomy. Molecular analysis of the STR DS11 marker revealed that his son carried two copies of the DS11A marker and a DS11C marker. Based on the data, determine if the nondisjunction occurred in Charlie or in the mother? Provide your reasoning.arrow_forwardA diploid (2n) trihybrid individual with the genotype AaBbDd can make eight genetically different gametes. 2n = 4 n = 2 (1) A d. ID 1 1 2 2 Gt: AaBbDd Loci A/a and D/d are on chromosome 1 and locus B/b is on chromosome 2. Explain how a gamete containing the alleles A, D and b may be produced by meiosis. Refer specifically to meiotic events occurring during Prophase I, Metaphase I, Anaphase I and Anaphase II. (NB: remember to refer to the organism above). COarrow_forwardWhat adjectives can be used to describe a fruit fly that has a total of seven chromosomes because it is missing one copy of chromosome 3?arrow_forward
- A diploid species has 3 pairs of chromosomes in its somatic cells. In males, the first pair is large submetacentric[1]; the second is medium acrocentric[2], and the third is small telocentric[3]. In females, the first two pairs are like those of the males while the third is large metacentric[4][5], with satellite4 Illustrate the karyograms (drawing/picture of the chromosome) of the following: A triploid cell in females tetrasomic cell in males tetraploid cell in females [1] submetacentric --centrosome is just above the middle of the chromosome [2] acrocentric --centrosome is much higher location than submetacentric so that the “p” arm of the chromosome is much shorter than the q arm [3] telocentric --the centromere is at the end of the chromosome [4] metacentric --centrosome is in the middle of the chromosome; thus the “p-arm” and the “q-arm” or both arms of the chromosome are equal in length [5] satellite-a constriction in an arm of a chromosome, aside…arrow_forwardIn rice, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of rice plants (i.e. the stamen) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile rice plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Give the result(s) of the cross and explain the phenotype of the offspring.arrow_forwardcrossing over within a pericentric inversion produces chromosomes that have extra copies of some genes and no copies of other genes. The fertilization of gametes containing chromosomes with duplications or deletions often result in children with syndromes characterized by developmental delay, intellectual disability, abnormal development of organ systems, and early death. Maarit Jaarola and colleagues examined individual sperm cells of a male who was heterozygous for a pericentric inversion on chromosome 8 and determined that crossing over took place within the pericentric inversion in 26% of the meiotic divisions (M. Jaarola, R. H. Martin, and T. Ashley. 1998. American Journal of Human Genetics 63:218–224). Assume that you are a genetic counselor and that a couple seeks counseling from you. Both the man and the woman are phenotypically normal, but the woman is heterozygous for a pericentric inversion on chromosome 8. The man is karyotypically normal. What is the probability that this…arrow_forward
- For the following chromosome complements, what is the phenotypic sex of a person who has Q. XY with the SRY gene deleted?arrow_forwardIn Neurospora, his2 mutants require the amino acidhistidine for growth, and lys4 mutants require theamino acid lysine. The two genes are on the samearm of the same chromosome, in the ordercentromere - his2 - lys4.A his2 mutant is mated with a lys4 mutant. Draw all ofthe possible ordered asci that could result from meioses in which the following events occurred, accountingfor the nutritional requirements for each ascospore.Ascospores without any copy of a chromosome willabort and die, turning white in the process.a. A single crossover between the centromere and his2b. A single crossover between his2 and lys4c. Nondisjunction during the first meiotic divisiond. Nondisjunction during the second meiotic divisione. A single crossover between the centromere andhis2, followed by nondisjunction during the firstmeiotic divisionf. A single crossover between his2 and lys4,followed by nondisjunction during the firstmeiotic divisionarrow_forwardIn elegans, lon-2 and unc-2 are recessive mutations that are 8 map units apart on the X chromosome. An hermaphrodite who is Lon and Unc is mated to a wild-type male. An F1 hermaphrodite is mated to a wild-type male. What are the expected percentages of the different recombinant phenotypes among the male progeny?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mitochondrial mutations; Author: Useful Genetics;https://www.youtube.com/watch?v=GvgXe-3RJeU;License: CC-BY